Mechanics of Materials 1 Part 4 pot

... = 0. 54 Therefore, from (l), A= -60 +10 0~0. 54 A= -6 Therefore, at r = 0 .1 m, from eqn. (10 .4) , B rz a,=A+-= -6+0. 54 ~10 0 = 48 MN/mZ 2 34 Mechanics of Materials 810 .18 A full ... x m4 32 1OI2 32 lo6 200 x 20 x 10 -3 shear stress T = -6 = 4. 34 MN/m2 0.92 x 10 - 240 Mechanics of Materials Solution (b): graphical known)...

Ngày tải lên: 10/08/2014, 12:21

... 16 .15 Production of fringe patterns 16 .16 Interpretation of fringe patterns 16 .17 Calibration 40 2 40 3 40 3 40 3 40 3 40 4 40 6 41 0 41 1 41 1 41 2 41 3 41 4 41 4 41 6 41 7 42 7 ... 42 7 43 0 43 0 43 1 43 5 43 7 43 7 43 7 43 8 43 9 44 0 4 41 44 3 44 4 44 5 44 6 44 6 44 8 44 9 45 0 CHAPTER 2 COMPOUND BARS Summary...

Ngày tải lên: 10/08/2014, 12:21

... 17 0–83, 386–90, 40 3 4, 508 crack closure, 41 8 –22, 45 4–8, 630 4 K max –K concept, 41 9 –22 K PR concept, 42 2 overloads and load-history effect, 12 , 17 0–82, 19 0–3, 41 4 mechanisms, 41 2 14 Wöhler, A., 3, 47 2–3 Wöhler ... 6 31 0 50 10 0 15 0 200 250 0 200 40 0 600 800 10 00 12 00 N = 10 0 , n = 10 7 N = 10 2 , n = 10 5 N = 10 3 , n = 10...

Ngày tải lên: 03/07/2014, 20:20

... conservative nature of this design Applied Stress Number of Cycles to Crack Initiation Average Design Allowable Distribution Of Lives Figure 1. 2. Schematic of S–N curve with illustration of scatter. Introduction ... restricted to a value of 40 % of that allowed by the minimum value material property allowable due to the sensitivity of high cycle stresses to damping variabi...

Ngày tải lên: 03/07/2014, 20:20

... 93 0 20 40 60 80 10 0 40 42 44 46 48 50 Percent failures Stress (ksi) Ransom and Mehl (19 49 ) Figure 3.25. Experimental data of Ransom and Mehl [8]. 44 .5 45 45 .5 46 46 .5 47 47 .5 48 48 .5 . 01 .1 1 5 10 ... Background 0 20 40 60 80 10 0 36 38 40 42 44 46 Percent failures Stress (ksi) Epremian and Mehl (19 52) Figure 3.23. Experimental data of Epremian an...

Ngày tải lên: 03/07/2014, 20:20

... described at the beginning of this chapter. The net result, 20 40 60 80 10 0 300 10 1 10 0 10 1 10 2 10 3 10 4 Overload model σ e = 300 MPa K th = 5 MPa√m Baseline σ = σ e σ = 1. 25σ e Stress (MPa) Crack ... 17 6 Effects of Damage on HCF Properties K t = 1. 94 K t = 2.25 c a Fracture surface 1. 27 70 1. 27 1. 27R 2.03R 35 10 .16 1. 27 All dimensions in m...

Ngày tải lên: 03/07/2014, 20:20

... crack-growth rate acceleration drivers. 10 –7 10 –6 10 –5 10 4 0 .1 0 .12 0 . 14 0 .16 0 .18 0.2 0.22 0. 24 (a) (b) (c) (d) (e) (f) da /dN (in./cycle) Crack length (in.) Figure 4. 43. Test plan 2 results. Legend ... generated at 11 00  F, for R =0 1 and 0.8 in the <0 01/ 010 > orientation on alloy PWA 14 84. After precracking, the specimen was run at a stress ratio of...

Ngày tải lên: 03/07/2014, 20:20

... strength, 0 0.2 0 .4 0.6 0.8 1 1 1. 5 2 2.5 3 3.5 4 4.5 5 a N = 0.2, d = 0 .1 a N = 0.5, d = 0 .1 a N = 0.2, d = 0.25 a N = 0.5, d = 0.25 a N = 0.2, d = 0.75 a N = 0.5, d = 0.75 1/ K t 1/ k f k t k t ... 0203 02 54 572 5 21 Large 0330 0729 572 4 26 0 10 0 200 300 40 0 500 0 200 40 0 600 800 10 00 k t = 1 k f = 2.8 k f = 2.8 (alt only) A...

Ngày tải lên: 03/07/2014, 20:20

... stress = 12 5 ± 15 MPa Contact pressure = 31 MPa Defect shape = extended (a) (b) Crack depth, a (mm) Crack depth, a (mm) 0 3 2 1 0 0.2 0 .4 0.6 0.8 1. 0 0.2 0 .4 0.6 0.8 1. 0 0.8 0.6 0 .4 0.2 0 1 2 3 Stress ... fatigue data. 3 04 Effects of Damage on HCF Properties 0 2 4 6 8 10 0 0.05 0 .1 0 .15 0.2 K I,max K I,min K II,max K II,min a (mm) θ = 0° K (MPa√m) Figure 6 .40 ....

Ngày tải lên: 03/07/2014, 21:20

... “The Effect of Environment on the Mechanism of Fretting Fatigue”, Wear, 52, 19 79, pp. 17 5 19 1. 14 . Schütz, W., “A History of Fatigue”, Engng Fract. Mech., 54, 19 96, pp. 263–300. 15 . Giannakopoulos, ... 37, 19 92, pp. 77–97. 20. Hills, D.A., Nowell, D., and O’Connor, J.J., “On the Mechanics of Fretting Fatigue”, Wear, 12 5, 19 88, pp. 12 9 14 6. 21. Szolwinski, M. a...

Ngày tải lên: 03/07/2014, 21:20