Composite Materials Design and Applications Part 3 doc

... Figure 3. 24). Figure 3. 22 Tensile Test Figure 3. 23 Short Beam Shear Test Figure 3. 24 Variation In Stiffness During Curing TX846_Frame_C 03 Page 52 Monday, November 18, 2002 12:05 PM © 20 03 by ... proportion of composite materials design. They appear in almost all applications. Historically they were the first light and high-performance structures. 1 In the majority...

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... information on modulus and strength of a basic ply: see Section 3. 3 .3) 0∞: e x e x e y e xy ++ 0 .3= 90∞: e y e x e y e xy ++ 0 .34 = 45∞: e xy e x e y e xy ++ 0 .36 = ± TX846_Frame_C05 Page ... -45∞. (More information on modulus and strength of a basic ply: see Section 3. 3 .3) e xy T xy t rupture = TX846_Frame_C05 Page 93 Monday, November 18, 2002 12:09 PM © 20 03 by...

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... III j 33 33 = j 2222 s 4 j 33 33 + c 4 1–()2s 2 c 2 j 2 233 2 j 232 3 +()+ 0= j 2222 j 33 33 = j 2222 c 4 s 4 1–+()2s 2 c 2 j 2 233 2 j 232 3 +()+ 0= 2– s 2 c 2 j 2222 2s 2 c 2 j 2 233 2 j 232 3 +()+ ... II¢ j – 33 12 j 33 12 0; F II¢ III¢I¢ III¢ j – 231 3 j 231 3 0=== === e 11 e 22 e 33 g 23 g 13 g 12 Ó ˛ ÔÔ ÔÔ ÔÔ ÔÔ Ì ˝ ÔÔ ÔÔ ÔÔ ÔÔ Ï¸ j 1111 j 1122 j 1 133 000 j 2211...

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... Section 5.4.2, Table 5.1: s rupture = 1,059 MPa and with r = 1, 530 kg/m 3 (Table 3. 4 of Section 3. 3 .3, or the calculation in Section 3. 2 .3) : V max = 832 m/s dm w 2 r¥ 2 s eb d q 2 = r r d q ... –()+ E y ➀ H 1 3 H 2 3 –()E y ➁ H 2 3 + ¥¥= H 2 2 z H 1 2 ££ ; t yz Q y 6 E y ➀ H 1 2 4 z 2 –() E y ➀ H 1 3 H 2 3 –()E y ➁ H 2 3 + ¥¥= k x a x 8 E x ➀ H 1 3...

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... 5 :38 PM © 20 03 by CRC Press LLC COMPOSITE MATERIALS DESIGN AND APPLICATIONS © 20 03 by CRC Press LLC 3. 3 Unidirectional Ply 3. 3.1 Elastic Modulus 3. 3.2 Ultimate Strength of a Ply 3. 3 .3 ... Ply 18 .3 Level 3 18 .3. 1 Cylindrical Bonding 18 .3. 2 Double Bonded Joint 18 .3. 3 Composite Beam with Two Layers 18 .3. 4 Buckling of a Sandwich Beam 18 .3. 5 Shear D...

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... Press LLC Figure 6 .32 Composite Piece Under Tensile Load Figure 6 .33 Composite Piece under Compression Load Figure 6 .34 Composite Piece under Tension-compression Load Figure 6 .35 Arrangement to ... bolting, and bonding: Ⅲ of a composite part to another composite part and Ⅲ of a composite part to a metallic part. 6.1 RIVETING AND BOLTING Ⅲ In all mec...

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... Comparison Between Metallic and Composite Springs 5 S.M.C. process: See Section 2.1 .3 and 3. 2. 6 See Section 3. 3.2, comparison of load-elongation diagrams for a metal and a unidirectional. TX846_Frame_C08 ... 12:22 PM © 20 03 by CRC Press LLC 8 COMPOSITE MATERIALS FOR OTHER APPLICATIONS We have given in Chapter 1 an idea on the diversity of the products which can be...

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... g 23 g 13 g 12 j 1111 j 1122 j 1 133 2 j 11 23 2 j 11 13 2 j 1112 j 2211 j 2222 j 2 233 2 j 22 23 2 j 22 13 2 j 2212 j 33 11 j 33 22 j 33 33 2 j 33 23 2 j 33 13 2 j 33 12 2 j 231 1 2 j 232 2 2 j 233 3 4 j 232 3 4 j 231 3 4 j 231 2 2 j 131 1 2 j 132 2 2 j 133 3 4 j 132 3 4 j 131 3 4 j 131 2 2 j 1211 2 j 1222 2 j 1 233 4 j 12 23 4 j 12 13 4 j 1212 s 11 s 22 s...

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... s 11 s 22 s 33 ++() 2 º {= º 3 s 11 s 22 t 12 2 –() s 22 s 33 t 23 2 –() s 33 s 11 t 31 2 –()++()– } dW dV ˯ ʈ distorsion 1 12G s 11 s 22 –() 2 s 22 s 33 –() 2 + º {= º s 33 s 11 –() 2 6 t 12 2 t 23 2 t 31 2 ++()++} a s 11 s 22 –() 2 s 22 s 33 –() 2 s 33 s 11 –() 2 º ++{ ... s I 2 s II 2 s III 2 s I s II s III ++ 3 ˯ ʈ 2 –++ Ó ˛ Ì ˝ ϸ = dW dV ˯ ʈ dis...

Ngày tải lên: 10/08/2014, 11:21

... titanium: E x = 55 ,33 3 MPa E x = 31 ,979 MPa G xy = 16 ,31 5 MPa G xy = 28, 430 MPa 800 900 34 0++() 100 2.64 2.17– 2.17 21%= TX846_Frame_C18a Page 36 8 Monday, November 18, 2002 12:40 PM © 20 03 by CRC ... complete study of the shear stresses in a composite beam (Equation 15.16). s max M f p r 2 e = F max 26 10 6 ¥ 7200 36 00 N.== M f () F max M f () a 63 332 9¥ 36 00...

Ngày tải lên: 10/08/2014, 11:21