SUPPLY CHAIN GAMES: OPERATIONS MANAGEMENT AND RISK VALUATION phần 1 pot

... diversity of supply chains. Examples: The Many Faces of Supply Chains The common view of supply chains, as stated in Figures 1. 1, 1. 2 and 1. 3 involves supply chains with intra-firms operations ... • Supply Chains and Operations Modeling and Management • Intertemporal Supply Chains Management • Risk and Supply Chain Management The first area pro...

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... case, with a demand, a random function of random prices). Then, the retailer profit at the next period is: ( ) () ( ) () () () () () 11 1 11 1 1 11 11 1 1 1 1 1 1 1 1 1 (1 ) (1) (1 ) f r f wRDQD ... measurement has its own error sources and 386 7 RISK AND SUPPLY CHAINS PART III RISK AND SUPPLY CHAIN MANAGEMENT 6.3 SUPPLY C...

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... of equations L 11= 0 and L12=0 >solve({L 11= 0, L12=0}, {m,w}); {}, = m 21. 83 319 513 = w 22.83 319 513 sponse m R (w) numerically as mR > mR:=solve(L 11= 0,m); mR + − 18 . 1. 200000000 + ... 21 , max qq J(q 1 ,q 2 ) = 21 , max qq [J 1 (q 1 ,q 2 )+J 2 (q 1 ,q 2 )]= 21 , max qq q 1 [p(q 1 +q 2 )-c]+ q 2 [p(q 1 +q 2 )-c] (2 .19 ) s.t. q 1 ≥ 0, q 2...

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... ∫ ∞ − +− − ∂ ∂ −−++ − − ++ c sws rr r dD Aw ws chhm A Dwschm 211 )( 1 111 1 1 ] )( 2 1 )[)( 2 )( 2 ( + ∫ ∞ − +− −+− +− − + ++ −+ ∂ ∂++ c sws rr rrr dD A Dws Dws A hhm chm w ws A hhm 211 )( 11 11 1 11 1 ])( 2 )( 2 [ )( 2 1 11 1 011 )( )()( w ws cwxws ∂ ∂ −+−+ ... and thus B 2 s (x 1 ) is random. Specifically, by taking into account that x 1 = x 0 +q 1 -d 1 , ,...

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... supplier ))()),()(()(([)( 12 111 tcttqtqptqtH − + = β )( 11 1 1 tq γψ − )( 22 1 2 tq γψ − , [)( 2 β =tH ))]()),()(()(( 2 212 tcttqtqptq − + )( 11 2 1 tq γψ − )( 22 2 2 tq γψ − . 18 4 4 MODELING IN AN ... centralized problem 21 , max qq J(q 1 ,q 2 )= 21 , max qq [J 1 (q 1 ,q 2 )+J 2 (q 1 ,q 2 )]= 21 , max qq ()() ∫ −+ T tcttqtqptq 0 12 11 )(),()()([ β + ( ) ( )...

Ngày tải lên: 10/08/2014, 07:21

... ). 4 1 2 1 2 1 4 1 2 1 2 1 ( 4 1 4 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 4 1 4 1 2 1 2 1 2 1 2 1 2 1 4 1 4 1 2 1 2 2 2 21 2 212 212 2 12 2 12 1 211 211 1 2 2 1 2 2 2 2 1 2 12 1 212 1 2 1 2 2 21 2 2 12 1 21 2 211 212 112 211 1 2 2 2 2 2 2 2 11 211 222 212 2 21 211 22 212 1 2 2 2 12 1 2* 2 fhbffhbfahbUfhb fbhbffbhbfahbUfhbhfb...

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... +− − = + −−− = ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ + − −+ ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ + − −+ ∑ pp tThwp t h ww TVt h wc TUX A n n n )( )]()([ 1 11 1 1 2 1 1 1 0 . That is, ∑ ∑ +− +− − = + ++ + −− − − −+ − −+ = n n n n n pp Ah UV pp hTwp A h ww TV h wc TUX t 1 1 2 1 1 0 1 )()( , and () 11 0 1 twc h t +−= ; () 11 22 1 tww h t ... of N +1 equations in N +1 unknowns, j i , j =1, ,N , K : [] 0)) (1( 2 1...

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... n n nn n n n n n n n n nn n n n n n n w k htT d TX p d TX p w k htT d TX p d TX p ⎟ ⎟ ⎠ ⎞ ⎜ ⎜ ⎝ ⎛ −−−+−= = ⎟ ⎟ ⎠ ⎞ ⎜ ⎜ ⎝ ⎛ −−−+− −+ − − − − − − − − + )() )( 1( )( )() )( 1( )( 1 1 1 1 1 1 1 n=2,…,N, (6.43) ) )( 1( )( )( 1 1 1 1 1 111 d TX p d TX phtT −+−=− −+ , )()( 1 nn n nn tt w M kTX −= + , n =1, 2,…,N; Tt N = +1 . Note, both ... (6.27): J ∫∫ +−⋅+−⋅+−⋅= 10 64...

Ngày tải lên: 10/08/2014, 07:21

... it is a solution of: () * 11 * ** 11 11 111 1 22 11 (1 ) ( ) ; f eewRLDD απ απ ππ α ππ π αα αα − − −− +− ⎛⎞⎛⎞ ⎡⎤ += +−+ − = ⎜⎟⎜⎟ ⎣⎦ ⎝⎠⎝⎠ ,(7.68) where: 1 11 1 11 11 1 () x ee Ledx π α παπ α π α ππ ... ** 11 00 10 01 00 10 11 01 ˆˆ ˆˆ (, ) ˆˆˆˆ N P aa aa Vxy aaaa − = −+− , or ( ) ()() () ** 1 (, ) 11 1 PPp N Pp PPPp ic Vxy E dc αν ν ν βαν +− = − −− − (8 .18 ) a...

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... u x txB utu x txB xH ∂ ∂ += ∂ ∂ ),( ),, ),( ,( 2 . A1.2 DYNAMIC PROGRAMMING 489 which, with respect to ),( 11 1 −−− = KKKK uxfx (see (A1. 21) ) is { } )),((),(min)( 11 111 1 )( 1 1 11 −−−−−−− − += −− KKKKKK xU K K uxfRuxLxB kK . ... .0 81, .226 . 016 9, .038 10 : Type II Type I (P,S) Type II (P,S) .224 . 31, .4 01 .08, .408 .11 34 .240, .4 01 .037, .18 9 .05 .18 6, ....

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