APPLIED NUMERICAL METHODS USING MATLAB phần 8 pot

... 0.53 1. 08 0.46 — 1 −1.21 −1.21 −1.12 −1. 18 −1.21 −1.21 −1.15 1.26 1 −0. 58 −0. 58 −0.76 −0.64 −0. 58 −0. 58 −0.71 −1.70 c o 3 −1.76 −1.76 −1.44 −1.65 — −1.76 −1.76 −1.54 −1 .84 — −0.00 −0.00 −3 .82 1 −0.00 ... −1.33 −1 .84 −0.65 1 −0.00 0.00 0.29 −3 .82 −1.41 −0.00 −0.00 −0.00 −0.00 0.00 −0.00 −0.00 −0.00 −22.1 −16.4 1.21 1.21 1.12 1. 18 — 1.21 1.21 1.15 −1.26 — x o 1 0. 58 0. 58...

Ngày tải lên: 09/08/2014, 12:22

... (1. 986 0e-15) 1.5000 0.3143 1. 788 9 A 2 x = b 2 0.6 286 0.9429 A 3 x = b 3 A 4 x = b 4 2.5000 1.2247 0.0000 A 5 x = b 5 A 6 x = b 6 (cf) When the mismatching error ||A i x − b i ||’s obtained from MATLAB ... two integrals (P1 .8. 2a) and (P1 .8. 2b) by using the in-line/M-file functions. function xfx = xGaussian_pdf(x,m,sigma,x0) xfx = (x - x0).*exp(-(x - m).^2/2/sigma^2)/sqrt(2*pi)/sig...

Ngày tải lên: 09/08/2014, 12:22

... polynomials of degree 1, 3, 5, and 7. x −3 −2 −1 0 1 2 3 y −0.2774 0 .89 58 −1.5651 3.4565 3.0601 4 .85 68 3 .89 82 We make the MATLAB program “do_polyfit.m”, which uses the routine “ polyfits()” to ... %LS subplot(220+i) plot(x,y,’k*’,xi,yi,’b:’) end %xy1.dat -3.0 -0.2774 -2.0 0 .89 58 -1.0 -1.5651 0.0 3.4565 1.0 3.0601 2.0 4 .85 68 3.0 3 .89 82 Example 3.6. Polynomial Curve Fit by LS...

Ngày tải lên: 09/08/2014, 12:22

... Recktenwald, G. W., Numerical Methods with MATLAB, Prentice-Hall, Upper Sad- dle River, NJ, 2000. [S-1] Schilling, R. J., and Harris, S. L., Applied Numerical Methods for Engineers Using MATLAB and C, ... t m u s (t) m! s m+1 (8) cos ωt u s (t) s s 2 + ω 2 Applied Numerical Methods Using MATLAB  , by Yang, Cao, Chung, and Morris Copyr ight  2005 John Wiley & S...

Ngày tải lên: 09/08/2014, 12:22

... interpolation/extrapolation. Applied Numerical Methods Using MATLAB  , by Yang, Cao, Chung, and Morris Copyr ight  2005 John Wiley & Sons, I nc., ISBN 0-471-6 983 3-4 117 126 INTERPOLATION AND CURVE FITTING (a) 4 /8/ 10 th ... -0 .85 52 0.49 98 -0.6456 -0.5774 0 0.2403 0 .85 52 0.5 184 0 .80 90 0.1100 0.5774 0 0 >>err = U*S*V’-A %to check if the result is right err =...

Ngày tải lên: 09/08/2014, 12:22

... (3.66e-15) Flops 2 489 30 28 x 0 = [1 0.5] x (P4.7.3) ||f(x)|| Flops 1476 382 1 x 0 = [1 0.5] x [0.5024 0.1506] (P4.7.4) ||f(x)|| 8. 88e-16 (1.18e-6) Flops 1127 1932 x 0 = [1 0.5] x (P4.7.5) ||f(x)|| Flops 288 4 ... (4.6576e-15) Flops 18, 273 21,935 x 0 = [1 1 1] x (P4 .8. 5) ||f(x)|| Flops 681 1 5525 x 0 = [1 1 1] x [2.0000 1.0000 3.0000] (P4 .8. 6) ||f(x)|| 3.4659e -8 (2.6130e -8) Flops...

Ngày tải lên: 09/08/2014, 12:22

... 4.6212e-2 2. 982 2e-2 8. 4103e-2 0.0001 9.4278e-3 9.4277e-3 0.00001 2. 185 3e-1 2. 985 8e-3 8. 4937e-2 (P5.12.1,2) 0.001 1.2393e-5 1.3545e-5 0.0001 8. 3626e-3 5.0315e-6 6. 484 9e-6 0.00001 1. 384 6e-9 8. 8255e-7 (P5.13.1) ... 1.3545e-5 0.0001 8. 3626e-3 5.0315e-6 6. 484 9e-6 0.00001 1. 384 6e-9 8. 8255e-7 (P5.13.1) N/A 8. 881 8e-16 0 8. 881 8e-16 5.12 Surface Area of Revolutionary 3-D...

Ngày tải lên: 09/08/2014, 12:22

... 2.9036] [2 .89 66, 2.9036] (f o =−156.66) (f o =−156.66) (f o =−156.66) (f o =−156.66) [−0.5,−1.0] [2.9035, −2.74 68] [−2.74 68, −2.74 68] [−2.74 68, −2.74 68] [2.9029, 2.90 28] (f o =−1 28. 39) (f o =−100.12) ... 0.5 989 fo_steep = 0. 289 9 %not a minimum co_steep = -1.27 68 -0.5 989 -1.5 386 0.1525 %violating -0.0001 Warning: Gradient must be provided Maximum # of function evaluation...

Ngày tải lên: 09/08/2014, 12:22

... using the routine “ fem_basis_ftn()” and plot one of them for node 1 by using the MATLAB command mesh(), as depicted in Fig. 9.8a. Second, without generating the basis functions, we use the MATLAB ... 5000 (E9 .8. 1) with the initial conditions and boundary conditions u(x, y, 0) = 0fort = 0 (E9 .8. 2a) u(x, y, t) = e y cos x − e x cos y for x = 0,x= 4,y= 0,y= 4 (E9 .8. 2b) The procedu...

Ngày tải lên: 09/08/2014, 12:22