APPLIED NUMERICAL METHODS USING MATLAB phần 6 docx

... solving ODEs, it gives us a Applied Numerical Methods Using MATLAB  , by Yang, Cao, Chung, and Morris Copyr ight  2005 John Wiley & Sons, I nc., ISBN 0-471 -69 833-4 263 292 ORDINARY DIFFERENTIAL ... Gauss (P5.11.1,2) 0.001 4 .62 12e-2 2.9822e-2 8.4103e-2 0.0001 9.4278e-3 9.4277e-3 0.00001 2.1853e-1 2.9858e-3 8.4937e-2 (P5.12.1,2) 0.001 1.2393e-5 1.3545e-5 0.0001 8. 362 6e-...

Ngày tải lên: 09/08/2014, 12:22

... interpolation/extrapolation. Applied Numerical Methods Using MATLAB  , by Yang, Cao, Chung, and Morris Copyr ight  2005 John Wiley & Sons, I nc., ISBN 0-471 -69 833-4 117 1 26 INTERPOLATION AND CURVE ... 3x  T 4 (x  ) = 8x  4 − 8x  2 + 1 T 5 (x  ) = 16x  5 − 20x  3 + 5x  T 6 (x  ) = 32x  6 − 48x  4 + 18x  2 − 1 T 7 (x  ) = 64 x  7 − 112x  5 + 56x  3 − 7x...

Ngày tải lên: 09/08/2014, 12:22

... =      −3/10 0 0 −1/8 −7/10 −7/ 16 0 0 03/ 16 1/10 0 007/30 7/24 25/42/35 /6      , p(:, :, 2) =      −1/20 0 −5/8 1/215/ 16 0 0 05/ 16 1/20 00−1/2 −5/24 0 −5/40 5 /6      , (9.4.17) p(:, ... using the routine “ fem_basis_ftn()” and plot one of them for node 1 by using the MATLAB command mesh(), as depicted in Fig. 9.8a. Second, without generating the basis fun...

Ngày tải lên: 09/08/2014, 12:22

... =  123 4 56    x 1 x 2 x 3   =  6 15  = b 1 (P1.14.1) (ii) A 2 x =  123 2 46    x 1 x 2 x 3   =  6 8  = b 2 (P1.14.2) (iii) A 3 x =  123 2 46    x 1 x 2 x 3   =  6 12  = b 3 (P1.14.3) Table ... (1.9 860 e-15) 1.5000 0.3143 1.7889 A 2 x = b 2 0 .62 86 0.9429 A 3 x = b 3 A 4 x = b 4 2.5000 1.2247 0.0000 A 5 x = b 5 A 6 x = b 6 (cf) When the mismatching erro...

Ngày tải lên: 09/08/2014, 12:22

... 3*x2-2.5 = 0’) x1 = [ 2.] x2 = [ 0.500000] [ -1.2 064 59] [ 0.9413 36] [0 .60 3229 -0.39 263 0*i] [-1.09 566 8 -0.540415e-1*i] [0 .60 3229 +0.39 263 0*i] [-1.09 566 8 +0.540415e-1*i] >>S = solve(’x^3 - y^3 ... {(x k ,y k ), k = 0 :6} in two columns and we must fit these data into polynomials of degree 1, 3, 5, and 7. x −3 −2 −1 0 1 2 3 y −0.2774 0.8958 −1. 565 1 3.4 565 3. 060 1 4.8 568...

Ngày tải lên: 09/08/2014, 12:22

... 0.7071 066 633 0.00001 166 72 −0.00000011785 h 4 = 0.0001000000 0.7071 067 800 0.0000001 167 −0.00000000118 h 5 = 0.0000100000 ∗ 0.7071 067 812 0.0000000012 −0.00000000001 ∗ h 6 = 0.0000010000 0.7071 067 812 ... ||f(x)|| 4.5506e-15 (4 .65 76e-15) Flops 18,273 21,935 x 0 = [1 1 1] x (P4.8.5) ||f(x)|| Flops 68 11 5525 x 0 = [1 1 1] x [2.0000 1.0000 3.0000] (P4.8 .6) ||f(x)|| 3. 465 9e-8 (2 ....

Ngày tải lên: 09/08/2014, 12:22

... 2.9035] [2.9035, 2.90 36] [2.90 36, 2.90 36] [2.8 966 , 2.90 36] (f o =−1 56. 66) (f o =−1 56. 66) (f o =−1 56. 66) (f o =−1 56. 66) [−0.5,−1.0] [2.9035, −2.7 468 ] [−2.7 468 , −2.7 468 ] [−2.7 468 , −2.7 468 ] [2.9029, 2.9028] (f o =−128.39) ... condition (P6.11.11) into (P6.11.10) yields y −1 − 4y 0 + 6y 1 − 4y 2 + y 3 = λy 1 (P6.11.11a) −−−−−→ 5y 1 − 4y 2 + y 3 = λy 1 y 0 − 4y 1 + 6y 2 −...

Ngày tải lên: 09/08/2014, 12:22

... 1.34 x o 1 0.58 0 .62 0 .62 0 .62 1 f o 0.53 0.17 0.17 0.17 1 −1.21 −1.34 −1.34 −1.38 −1.21 −1.34 −1.34 −1.34 1. 26 0.00 −0.58 −0 .62 −0 .62 −0 .63 −0.58 −0 .62 −0 .62 −0 .62 −1.70 −1.59 1/3 c o −1. 76 −1.34 −1.34 ... ∂ 2 f/∂x 2 i (1) [0 .69 65 −0.1423] −, − M (6) [−1 .69 26 −0.1183] (2) [2.5 463 −0.18 96] (7) [−2 .65 73 −2.8219] +, + m (3) [2.5209 2.9027] +, + G (8) [−0.3227 −2.4257] (4)...

Ngày tải lên: 09/08/2014, 12:22

... 429–431, 435, 4 56 penalty, 3 46 349, 362 , 366 permutation, 94, 467 persistent excitation, 169 physical meaning of eigenvalues and eigenvectors, 385 pivoting, 85– 88, 105–1 06 plot, 6 11 Plot mode, ... Recktenwald, G. W., Numerical Methods with MATLAB, Prentice-Hall, Upper Sad- dle River, NJ, 2000. [S-1] Schilling, R. J., and Harris, S. L., Applied Numerical Methods for Engi...

Ngày tải lên: 09/08/2014, 12:22