APPLIED NUMERICAL METHODS USING MATLAB phần 5 pptx

APPLIED NUMERICAL METHODS USING MATLAB phần 5 pptx

APPLIED NUMERICAL METHODS USING MATLAB phần 5 pptx

... −0.03 650 380828 h 2 = 0.0100000000 0.70 355 94917 0.032 956 5188 −0.00 354 728 950 h 3 = 0.0010000000 0.706 753 1100 0.0031936183 −0.000 353 67121 h 4 = 0.0001000000 0.7070714247 0.0003183147 −0.0000 353 5 652 h 5 = ... 12896 x 0 = [1 0 .5] x (P4.7.7) ||f(x)|| Flops 21 25 2378 x 0 = [1 0 .5] x [0.2321 1 .50 67] (P4.7.8) ||f(x)|| 1.07 (1.07) Flops 651 6 6492 x 0 = [1 0 .5] x (P4.7.9) ||f...

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APPLIED NUMERICAL METHODS USING MATLAB phần 2 potx

APPLIED NUMERICAL METHODS USING MATLAB phần 2 potx

... − b i || inconsistent 1 .50 00 4.4409e- 15 A 1 x = b 1 0 (1.9860e- 15) 1 .50 00 0.3143 1.7889 A 2 x = b 2 0.6286 0.9429 A 3 x = b 3 A 4 x = b 4 2 .50 00 1.2247 0.0000 A 5 x = b 5 A 6 x = b 6 (cf) When ... the boundary vector and the centroid vector be, respectively, b=[-3-2-10123]; c=[-2 .5 -1 .5 -0 .5 0 .5 1 .5 2 .5] ; (a) Make a program that uses two ADC routines to find the outpu...

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APPLIED NUMERICAL METHODS USING MATLAB phần 3 docx

APPLIED NUMERICAL METHODS USING MATLAB phần 3 docx

... -0. 855 2 0.4998 -0.6 456 -0 .57 74 0 0.2403 0. 855 2 0 .51 84 0.8090 0.1100 0 .57 74 0 0 >>err = U*S*V’-A %to check if the result is right err = 1.0e-0 15* -0.2220 -0.2220 00 0.4441 0 2 .5 ITERATIVE METHODS ... forsubst(L,P*b) backsubst(U,tmp) gauss(A,b) A\b A^-1*b ||Ax i − b|| 1. 359 7e-016 5. 551 1e-017 1. 755 4e-016 3.0935e-012 # of flops 123 224 155 50 (cf) The numbers of flops...

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APPLIED NUMERICAL METHODS USING MATLAB phần 4 pot

APPLIED NUMERICAL METHODS USING MATLAB phần 4 pot

... x 10 0 20 −10 50 1020 15 (b) f 44 b ( x ) = ( x 2 − 25) ( x − 10) − 5 2.4 2.6 0 −10 −20 −30 −40 − 15 −10 50 5 151 0 x 1 x 0 x 1 x 2 x 3 x 2 x 3 x 0 x 0 x 0 x 3 x 3 x 2 x 2 x 1 x 1 1 1 25 1 0 −1 2 −2 5 051 0 (d) ... 4*x2^2 -5= 0’,’2* x 1^2 - 2*x1 - 3*x2-2 .5 = 0’) x1 = [ 2.] x2 = [ 0 .50 0000] [ -1.206 459 ] [ 0.941336] [0.603229 -0.392630*i] [-1.0 956 68 -0 .54 0415e-1*i] [0.6...

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APPLIED NUMERICAL METHODS USING MATLAB phần 6 docx

APPLIED NUMERICAL METHODS USING MATLAB phần 6 docx

... 1/2 = 0 .5 y(0 .50 ) = (3/4)y(0. 25) + 1/4 = 0.43 75 0. 75 y(0. 75) = (3/4)y(0 .50 ) + 1/4 = 0 .57 81 1.00 y(1.00) = (1/2)y(0 .5) + 1/2 = 3/4 = 0. 75 y(1.00) = (3/4)y(0. 75) + 1/4 = 0.6836 1. 25 y(1. 25) = (3/4)y(1.00) ... 9.4277e-3 0.00001 2.1 853 e-1 2.9 858 e-3 8.4937e-2 (P5.12.1,2) 0.001 1.2393e -5 1. 354 5e -5 0.0001 8.3626e-3 5. 0315e-6 6.4849e-6 0.00001 1.3846e-9 8.8 255 e-7 (P...

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APPLIED NUMERICAL METHODS USING MATLAB phần 7 doc

APPLIED NUMERICAL METHODS USING MATLAB phần 7 doc

... fminunc() sim anl() [0, 0] [2.90 35, 2.90 35] [2.90 35, 2.9036] [2.9036, 2.9036] [2.8966, 2.9036] (f o =− 156 .66) (f o =− 156 .66) (f o =− 156 .66) (f o =− 156 .66) [−0 .5, −1.0] [2.90 35, −2.7468] [−2.7468, −2.7468] ... -1.2118 -0 .57 65 -1. 757 3 %high margin -0.0000 %no margin -0.0000 %no margin xo_s = 1.2118 0 .57 65 fo_s = 0 .53 22 %min value xo_steep = 1.2768 0 .59 89 fo_steep = 0.28...

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APPLIED NUMERICAL METHODS USING MATLAB phần 8 pot

APPLIED NUMERICAL METHODS USING MATLAB phần 8 pot

... — f o 0 .53 0 .53 1.36 0.79 — 0 .53 0 .53 1.08 0.46 — 1 −1.21 −1.21 −1.12 −1.18 −1.21 −1.21 −1. 15 1.26 1 −0 .58 −0 .58 −0.76 −0.64 −0 .58 −0 .58 −0.71 −1.70 c o 3 −1.76 −1.76 −1.44 −1. 65 — −1.76 −1.76 −1 .54 ... minima [1.0 0 .5] 0 Weird (warning) [0.2 0.3] 0 [10. 25 0] ∞ (d) [2 5] 0 [5. 77 8.17] 25. 98 [100 10] 0 Minimum PROBLEMS 357 Table 7.3 The Names of MATLAB Built-In Minimizati...

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APPLIED NUMERICAL METHODS USING MATLAB phần 9 docx

APPLIED NUMERICAL METHODS USING MATLAB phần 9 docx

... drawn by using trimesh () x10 −3 5 0 .5 0 .5 −0 .5 −0 .5 5 0 0 0 1 1 y −1 −1 x u ( x , y ) u ( x , y ) u ( x , y ) (b) 31-point FEM solution by using mesh () x10 −3 5 0 .5 0 .5 −0 .5 −0 .5 5 0 0 0 1 1 y −1 −1 x (c) ... 10 −3 5 u ( x , y ) 0 0 5 0 .5 −0 .5 0 1 y 0 .5 −0 .5 −1 −1 1 x (d) The mesh plot of the solution obtained by using Adaptive mesh one time 0 1 y...

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APPLIED NUMERICAL METHODS USING MATLAB phần 10 pot

APPLIED NUMERICAL METHODS USING MATLAB phần 10 pot

... 234 Gauss–Chebyshev, 240 Gauss–Hermite, 238, 251 , 253 Gauss–Jordan elimination, 89, 106 Gauss–Laguerre, 239, 254 , 255 Gauss–Legendre, 2 35, 251 , 255 Gauss–Seidel iteration, 100, 103, 1 15 Gaussian distribution, 24 genetic ... 473 Laplace’s Equation, 402, 404, 427, 4 35, 442 largest number in MATLAB, 27 leakage, 155 , 174 least squares (LS), 144, 1 65, 169, 171, 351 , 354 INDEX FOR M...

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