APPLIED NUMERICAL METHODS USING MATLAB phần 3 docx

... dy 1 − h 1 3 (S 2,2 + 2S 1,2 ) = 3 − 1 3 ( 3 +2 3) = 2 (E3 .3. 7b) S 2,1 = dy 2 − h 2 3 (S 3, 2 + 2S 2,2 ) = 1 − 1 3 (3 + 2 ×( 3) ) = 2 (E3 .3. 7c) S 0 ,3 = S 1,2 − S 0,2 3h 0 = 3 −( 3) 3 = 2 (E3 .3. 8a) S 1 ,3 = S 2,2 − ... a 32 − l 31 u 12 a (1) 33 = a 33 − l 31 u 13    (2.4.6a) step 2: →    u 11 u 12 u 13 l 21 u 22 = a (1) 22 u 23 = a (1) 23 l 31...

Ngày tải lên: 09/08/2014, 12:22

... 2.9822e-2 8.4103e-2 0.0001 9.4278e -3 9.4277e -3 0.00001 2.1853e-1 2.9858e -3 8.4 937 e-2 (P5.12.1,2) 0.001 1. 239 3e-5 1 .35 45e-5 0.0001 8 .36 26e -3 5. 031 5e-6 6.4849e-6 0.00001 1 .38 46e-9 8.8255e-7 (P5. 13. 1) N/A ... y ( t ) = e t − 1 and numerical solutions 0246810 0 1 2 3 × 10 4 (a3) Numerical solutions by ode 23, ode45, ode1 13 0246810 × 10 3 1 0.5 0 ode 23 ( ) od...

Ngày tải lên: 09/08/2014, 12:22

... N(S(s,2),:) + N(S(s ,3) ,:)) /3; %gravity center %phi_i,x*phi_n,x + phi_i,y*phi_n,y - g(x,y)*phi_i*phi_n p_vctr = [p([i n],s,1) p([i n],s,2) p([i n],s ,3) ]; tmpg(s) = sum(p(i,s,2 :3) .*p(n,s,2 :3) ) -g(xy(1),xy(2))*p_vctr(1,:)*[1 ... solution drawn by using trimesh () x10 3 5 0.5 0.5 −0.5 −0.5 −5 0 0 0 1 1 y −1 −1 x u ( x , y ) u ( x , y ) u ( x , y ) (b) 31 -point FEM solution by...

Ngày tải lên: 09/08/2014, 12:22

... column.     a (3) 11 a (3) 12 a (3) 13 b (3) 1 a (3) 21 a (3) 22 a (3) 23 b (3) 2 a (3) 31 a (3) 32 a (3) 33 b (3) 3     =     2 −1 −10 03/ 2 −1/21 01 1 2     : r (3) 1 : r (3) 2 : r (3) 3 (2.2.10c) Andwedopivotingata (3) 22 by ... get r (2) 1 − 0 × r (3) 3 → r (2) 2 − (−1) × r (3) 3 → r (2) 3 →     a (3) 11 a (3) 12 a...

Ngày tải lên: 09/08/2014, 12:22

... more reliable data. %do_wlse1 for Ex .3. 7 clear, clf x=[ 135 79246810]; %input data y = [0.0 831 0.9290 2.4 932 4.9292 7.9605 0.9 536 2.4 836 3. 41 73 6 .39 03 10.24 43] ; %output data eb = [0.2*ones(5,1); ... - 3* x2-2.5 = 0’) x1 = [ 2.] x2 = [ 0.500000] [ -1.206459] [ 0.94 133 6] [0.6 032 29 -0 .39 2 630 *i] [-1.095668 -0.540415e-1*i] [0.6 032 29 +0 .39 2 630 *i] [-1.095668 +0.540415e...

Ngày tải lên: 09/08/2014, 12:22

... −0. 036 5 038 0828 h 2 = 0.0100000000 0.7 035 594917 0. 032 9565188 −0.0 035 4728950 h 3 = 0.0010000000 0.7067 531 100 0.0 031 936 1 83 −0.00 035 367121 h 4 = 0.0001000000 0.7070714247 0.00 031 831 47 −0.000 035 35652 h 5 = ... (5.9.3a), w 1 + w 1 = 2 w 1 = w 2 = 1 → (5.9.3c), t 2 1 + (−t 1 ) 2 = 2 3 ,t 1 =−t 2 =− 1 √ 3 PROBLEMS 207 for five different sets of data rates a = [32 32 32...

Ngày tải lên: 09/08/2014, 12:22

... err_of_sol_de(df,xx,ys) subplot (32 1), plot(xx,Ts) UNCONSTRAINED OPTIMIZATION 32 3 2 1 0 −1 0 0.5 1 (1 − r ) h = rh 1 = r 2 h c 3 c 1 c 2 c d 3 d 2 d 1 d b 3 b 2 a 3 a 1 1.5 2 2.5 3 b 1 h 1 = b 1 ... 0 bvp2 fdf() 3. 2 ×10 − 13 bvp4c() (P6.10 .3) with bvp2 shoot() NaN (divergent) N/A y(1) = 4, y(2) = 8 bvp2 fdf() bvp4c() 3. 5 ×10 −6 (P6.10.4) with bvp2 shoot() y(1) =...

Ngày tải lên: 09/08/2014, 12:22

... order x i of each user for five different sets of data rates a = [32 3 232 32], [6 432 3 232 ], [128 32 32 32 ], [256 32 32 32 ], and [512 32 32 32 ] and plots a 1 /x 1 (the number of subchannels assigned to ... results. >> nm 733 xo_lp = [0 .33 33 1.5000], fo_lp = -4.0000 cons_satisfied = -0.0000 % <= 0(inequality) -0. 833 3 % <= 0(inequality) -0.0000 % = 0(equality) xo...

Ngày tải lên: 09/08/2014, 12:22

... a 3 × 3matrix,the principal minor matrices are a 11 ,a 22 ,a 33 ,  a 11 a 12 a 21 a 22  ,  a 22 a 23 a 32 a 33  ,  a 11 a 13 a 31 a 33  ,   a 11 a 12 a 13 a 21 a 22 a 23 a 31 a 32 a 33   among ... choice. USEFUL FORMULAS 479 sin 3 A = 1 4 (3sinA − sin 3A) (F .32 ) cos 3 A = 1 4 (3cosA + cos 3A) (F .33 ) sin 2A = 2sinA cos A(F .34 ) sin 3A = 3sinA − 4sin...

Ngày tải lên: 09/08/2014, 12:22