Fundamentals of Electrical Drivess - Chapter 10 pot
Fundamentals of Electrical Drivess - Chapter 10 pot
... indicated by figure 10. 10. An example of an m-file which can
produce the results shown in figure 10. 22 is as follows
m-file Tutorial 6, part 1 chapter 10
%Tutorial 6, part 1, chapter 10
close all
clear ... voltages
290 FUNDAMENTALS OF ELECTRICAL DRIVES
Table 10. 3. Steady-state results Simulink model with variable armature voltage
n
m
(rpm)
T
ref
(Nm) T
e
(Nm) U
a
=110V U
a
=...
Fundamentals of Electrical Drivess - Chapter 8 potx
... 373.06 -5 3.13
0.75 0.42 241.73 -3 2.23
1.0 0.30 130.96 -2 3.58
1.25 0.23 25.81 -1 8.66
1.50 0.26 -7 6.84 -1 5.47
1.75 0.35 -1 78.16 -1 3.21
2.00 0.47 -2 78.66 -1 1.54
2.25 0.60 -3 78.62 -1 0.24
Build an m-file ... Simulink
Te=[0:1.25 /10: 1.25]; % selected load torque values
%measured, from display, load angle (deg)
rhoM=[0 -5 .74 -1 1.54 -1 7.46...
Fundamentals of Electrical Drivess - Chapter 9 potx
... |
i
s
|, T
e
and ω
m
.
Build an m-file which enables you to show the results of the simulations in
the form of four sub-plots. An example of such an m-file is given at the end of
this tutorial.
The results ... Machines 255
0 500 100 0 1500 2000 2500 3000
0
10
20
torque (Nm)
0 500 100 0 1500 2000 2500 3000
0
10
20
RMS stat. cur. (A)
0 500 100 0 1500 2000 2500 3000
0
5000
100 00...
Fundamentals of Electrical Drivess - Chapter 0 docx
... Heidelberg
Printed on acid-free paper SPIN: 11760481 62/techbooks 543 210
1-4 02 0-5 50 4-8 ebook
97 8-1 -4 02 0-5 50 4-1 ebook
Springer2007
ISBN -1 0
()
(
)
(HB)
(HB)
ISBN -1 0 1-4 02 0-5 503-X
ISBN-13 97 8-1 -4 02 0-5 50 3-4
... VA
p -number of pole pairs
PI -proportional-integral
PWM -pulse width modulation
Q -reactive power VA
R -resistance Ω
R -reluctance A...
Fundamentals of Electrical Drivess - Chapter 1 pptx
... were open
%%%%%%define variables
A_c=10e-3*10e-3; % cross-section of core and armature 10mm x10 mm
A_a=10e-3*10e-3; % assumed cross-section of airgap
g=10e-3; % distance (airgap) between armature ... cross-section A
c
100 mm
2
Airgap cross-section A
a
100 mm
2
Copper cross-section A
cu
1600 mm
2
Permeability in iron µ
c
0.008 H/m
Permeability in air µ
o
4 10
−7
H/m
Number of turns co...
Fundamentals of Electrical Drivess - Chapter 2 ppt
... 40 FUNDAMENTALS OF ELECTRICAL DRIVES
i
Psi
u
i(psi)
dat
To Workspace
Sine Wave
100
R
1
s
Clock
Figure 2.15. Simulink model of non-linear inductance with sinusoidal excitation function
of output ... concept of ‘incremental flux-linkage’ ∆ψ = ψ(t)−ψ(0) which
is fundamental to the control of electrical drives. The equation basically states
that a flux-linkage variation correspo...
Fundamentals of Electrical Drivess - Chapter 3 pps
... MATLAB
74 FUNDAMENTALS OF ELECTRICAL DRIVES
S COPE1GAI
0.0998
GAI
0.02
i
1
i
RM
i
2
i
M
@'
2
i
11
u
1/50
u
2 /10
u
1
@
2
@
1
i'
2
-1 2.282 -4 2.855m
-3 3.689
11.182m
118.755m
-1 2.239
-1 8.668 ... no-load and
short-circuit test. The third load resistance value R
L
= 10 has been chosen
arbitrarily to demonstrate the operation of the transformer under load...
Fundamentals of Electrical Drivess - Chapter 4 doc
... (A)’)
hold on
100 FUNDAMENTALS OF ELECTRICAL DRIVES
Figure 4.27. Generic, space vector based, model of three-phase R-L circuit (delta connected)
was and is used to study linear electrical circuits ... u
Sβ
−400 −300 −200 100 0 100 200 300 400
−300
−200
100
0
100
200
300
u
Sα
(V)
u
Sβ
(V)
Figure 4.34. Waveforms: u
S123
, vector locus diagram
m-file Tutorial 1, chapter 4
%tu...
Fundamentals of Electrical Drivess - Chapter 5 ppt
... SCOPE5
SCOPE4
SCOPE1
SCOPE3
B_S
+
-
i
p
c
u
c
i
p
L
u
L
i
u
c
u
L
u
s
i
p
s
u
s
i
u
c
u
L
10
ground
-9 89.810u -1 581.294n 1597.573u
-9 89.810u
-9 896.523u 9.998
-9 89.810u
1597.573u
9.998
10. 000
-9 89.810u
-9 898 .102 u 10. 000
-9 89.810u
1597.573u
9.998
0 [Volt]
Figure ... input power
of the circuit is equal to the real power, hence
P = p
in
(...
Fundamentals of Electrical Drivess - Chapter 6 pptx
... with the steady-state
results obtained from the dynamic simulation.
m-file Tutorial 6, chapter 6
%Tutorial 6, chapter 6
close all
%parameters
L_sig=10e-3; % leakage inductance
L_M=300e-3; % magnetizing ... period of 0.4s, using a ‘step-size’ of 10
−5
s
and ‘solver’ ode4. Outputs of the simulation should be the vectors
i
1
,
i
2D
,
ψ
1
and
ψ
2D
. An example of a possible i...
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