Fundamentals of Electrical Drivess - Chapter 9 potx

... 18.83 19. 68 19. 87 19. 81 17. 39 13 .93 8.31 4.54]; Is3=[16.68 15 .94 14 .94 13 .91 13. 29 12.40 9. 32 6 .95 3 .93 2.11]; Ps3=[4760.36 5 393 . 19 591 6.81 6182.37 6243.31 6224 .90 5464.44 4375.32 26 09. 29 1426 .96 ]; Qs3=[10 299 .87 ... 3 69. 29 15.15 16.68 4760.36 10 299 .87 83.41 200 878 .93 17.17 15 .94 5 393 . 19 9408.48 79. 72 100 1301 .94 18.83 14 .94 591 6.81 8263.42 74.71 70...

Ngày tải lên: 09/08/2014, 06:22

... (deg) rhoM=[0 -5 .74 -1 1.54 -1 7.46 -2 3.58 -3 0.00 -3 6.87 -4 4.43 -5 3.13 -6 4.16 -8 9. 29] ; %measured, from display, real power (W) PM=[0 39. 27 78.54 117.81 157.08 196 .35 235.62 274. 89 314.16 353.43 392 .67]; %measured, ... 0.30 0.625 -3 0.00 196 .35 150. 79 0.36 0.750 -3 6.87 235.62 176.71 0.43 0.875 -4 4.43 274. 89 210.43 0.51 1.00 -5 3...

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... Heidelberg Printed on acid-free paper SPIN: 11760481 62/techbooks 543210 1-4 02 0-5 50 4-8 ebook 97 8-1 -4 02 0-5 50 4-1 ebook Springer2007 ISBN-10 () ( ) (HB) (HB) ISBN-10 1-4 02 0-5 503-X ISBN-13 97 8-1 -4 02 0-5 50 3-4 ... VA p -number of pole pairs PI -proportional-integral PWM -pulse width modulation Q -reactive power VA R -resistance Ω R -reluctance At/Wb...

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... variables A_c=10e-3*10e-3; % cross-section of core and armature 10mm x10 mm A_a=10e-3*10e-3; % assumed cross-section of airgap g=10e-3; % distance (airgap) between armature and C core mu_c=0.64/ 79. 58; % ... ring of width ‘h’ placed on the middle of the airgap at radius r + g/2. An observation of figure 1.17 learns that the flux crossing the airgap has a larger cross-sectional 10 FU...

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... 40 FUNDAMENTALS OF ELECTRICAL DRIVES i Psi u i(psi) dat To Workspace Sine Wave 100 R 1 s Clock Figure 2.15. Simulink model of non-linear inductance with sinusoidal excitation function of output ... concept of ‘incremental flux-linkage’ ∆ψ = ψ(t)−ψ(0) which is fundamental to the control of electrical drives. The equation basically states that a flux-linkage variation correspond...

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... MATLAB 74 FUNDAMENTALS OF ELECTRICAL DRIVES S COPE1GAI 0. 099 8 GAI 0.02 i 1 i RM i 2 i M @' 2 i 11 u 1/50 u 2/10 u 1 @ 2 @ 1 i' 2 -1 2.282 -4 2.855m -3 3.6 89 11.182m 118.755m -1 2.2 39 -1 8.668 ... figure 3 .9 is directly based on the earlier model given in figure 3.6. Shown in figure 3 .9 Figure 3 .9. Generic model of transformer with load and - nit...

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... (A)’) hold on 100 FUNDAMENTALS OF ELECTRICAL DRIVES Figure 4.27. Generic, space vector based, model of three-phase R-L circuit (delta connected) was and is used to study linear electrical circuits ... by the presence of a component u S0 (see equation (4. 39) ). The m-file which is able to plot the results of this simulation is as follows m-file Tutorial 3, chapter 4 %tutorial 3,...

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... SCOPE5 SCOPE4 SCOPE1 SCOPE3 B_S + - i p c u c i p L u L i u c u L u s i p s u s i u c u L 10 ground -9 89. 810u -1 581. 294 n 1 597 .573u -9 89. 810u -9 896 .523u 9. 998 -9 89. 810u 1 597 .573u 9. 998 10.000 -9 89. 810u -9 898 .102u 10.000 -9 89. 810u 1 597 .573u 9. 998 0 [Volt] Figure 5.16. ... input power of the circuit is equal to the real powe...

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... results NOTE1 PI @ 1 i m u 1 1.25 @ 1 @ s U 2 u 2 u 1 U 1 i 2 i 1 I1 I 2 P 1 Q 1 @ s @ s @ 2 1.250 833.333m 392 . 699 1.250 314.1 59 45.345 78.540 392 . 699 226.725 154.418 25.642 18.132 89. 153 9. 538k 7.818k 314.1 59 314.1 59 250.000m Figure 6.15. Caspoc ... to|  i 1 | =9. 09A, |  i 2D | =9. 90Aand|  ψ 1 | =0 .94 Wb, |  ψ 2D | =0.79Wb respectively. The m-...

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... physically Chapter 7 INTRODUCTION TO ELECTRICAL MACHINES 7.1 Introduction This chapter considers the basic working principles of the so-called ‘clas- sical’ set of machines. This set of machines ... directly 182 FUNDAMENTALS OF ELECTRICAL DRIVES example, in the two-pole machine we can rotate the resultant magnetic field by an angle of π 2 radians by way of a voltage excit...

Ngày tải lên: 09/08/2014, 06:22