Fundamentals of Electrical Drivess - Chapter 8 potx

Fundamentals of Electrical Drivess - Chapter 8 potx

Fundamentals of Electrical Drivess - Chapter 8 potx

... 241.73 -3 2.23 1.0 0.30 130.96 -2 3. 58 1.25 0.23 25 .81 -1 8. 66 1.50 0.26 -7 6 .84 -1 5.47 1.75 0.35 -1 78. 16 -1 3.21 2.00 0.47 -2 78. 66 -1 1.54 2.25 0.60 -3 78. 62 -1 0.24 Build an m-file which will display the ... (deg) rhoM=[0 -5 .74 -1 1.54 -1 7.46 -2 3. 58 -3 0.00 -3 6 .87 -4 4.43 -5 3.13 -6 4.16 -8 9.29]; %measured, fro...
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Fundamentals of Electrical Drivess - Chapter 9 potx

Fundamentals of Electrical Drivess - Chapter 9 potx

... 15.15 16. 68 4760.36 10299 .87 83 .41 200 87 8.93 17.17 15.94 5393.19 94 08. 48 79.72 100 1301.94 18. 83 14.94 5916 .81 82 63.42 74.71 70 1590.66 19. 68 13.91 6 182 .47 7166.30 69.57 60 1726.55 19 .87 13.29 ... inductance nm2=[ 184 4.66 2100 .86 2 288 .64 2556.27 2744.29]; Te2=[ 18. 90 14.71 11.64 7.26 4. 18] ; Is2= [8. 73 6 .80 5. 38 3.35 1.93]; Ps2=[59 38. 94 4621.94 3656.71 2 280 .9...
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Fundamentals of Electrical Drivess - Chapter 0 docx

Fundamentals of Electrical Drivess - Chapter 0 docx

... Heidelberg Printed on acid-free paper SPIN: 11760 481 62/techbooks 543210 1-4 02 0-5 50 4 -8 ebook 97 8- 1 -4 02 0-5 50 4-1 ebook Springer2007 ISBN-10 () ( ) (HB) (HB) ISBN-10 1-4 02 0-5 503-X ISBN-13 97 8- 1 -4 02 0-5 50 3-4 ... VA p -number of pole pairs PI -proportional-integral PWM -pulse width modulation Q -reactive power VA R -resistance Ω R -reluctance At/Wb r...
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Fundamentals of Electrical Drivess - Chapter 1 pptx

Fundamentals of Electrical Drivess - Chapter 1 pptx

... variables A_c=10e-3*10e-3; % cross-section of core and armature 10mm x10 mm A_a=10e-3*10e-3; % assumed cross-section of airgap g=10e-3; % distance (airgap) between armature and C core mu_c=0.64/79. 58; % ... located between 28 FUNDAMENTALS OF ELECTRICAL DRIVES two-dimensional finite element package which was also used to calculate the flux distribution shown in figure 1. 18. Observat...
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Fundamentals of Electrical Drivess - Chapter 2 ppt

Fundamentals of Electrical Drivess - Chapter 2 ppt

... following entries under: ‘vector of input values:’ set to tanh( [-5 :0.1:5]), and ‘vector 38 FUNDAMENTALS OF ELECTRICAL DRIVES 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0 .8 0.9 1 0 0.5 1 1.5 (a) time (s) voltage ... concept of ‘incremental flux-linkage’ ∆ψ = ψ(t)−ψ(0) which is fundamental to the control of electrical drives. The equation basically states that a flux-linkage variation c...
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Fundamentals of Electrical Drivess - Chapter 3 pps

Fundamentals of Electrical Drivess - Chapter 3 pps

... MATLAB 74 FUNDAMENTALS OF ELECTRICAL DRIVES S COPE1GAI 0.09 98 GAI 0.02 i 1 i RM i 2 i M @' 2 i 11 u 1/50 u 2/10 u 1 @ 2 @ 1 i' 2 -1 2. 282 -4 2 .85 5m -3 3. 689 11. 182 m 1 18. 755m -1 2.239 -1 8. 6 68 ... -3 3. 689 11. 182 m 1 18. 755m -1 2.239 -1 8. 6 68 -3 3.706 -9 33. 381 43. 184 m 1.257m -1 2.251 Figure 3. 28. Caspoc model...
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Fundamentals of Electrical Drivess - Chapter 4 doc

Fundamentals of Electrical Drivess - Chapter 4 doc

... An example of this phasor calculation together with the commands needed to display the results of the simulation are shown in the m-file below. m-file Tutorial 8, chapter 4 %tutorial 8, chapter 4 close ... 40]) grid legend(’i_{D\alpha}’,’i_{D\beta}’) subplot(3,1,3) plot(datoutn(:,6),datoutn(:,5),’g’) xlabel(’time (s)’) ylabel(’i_R (A)’) grid axis([0 20e-3 -6 0 60]) 4 .8. 8 Tutorial...
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Fundamentals of Electrical Drivess - Chapter 5 ppt

Fundamentals of Electrical Drivess - Chapter 5 ppt

... SCOPE5 SCOPE4 SCOPE1 SCOPE3 B_S + - i p c u c i p L u L i u c u L u s i p s u s i u c u L 10 ground -9 89 .81 0u -1 581 .294n 1597.573u -9 89 .81 0u -9 89 6.523u 9.9 98 -9 89 .81 0u 1597.573u 9.9 98 10.000 -9 89 .81 0u -9 89 8.102u 10.000 -9 89 .81 0u 1597.573u 9.9 98 0 [Volt] Figure 5.16. ... input power of the circuit is equal to the real...
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Fundamentals of Electrical Drivess - Chapter 6 pptx

Fundamentals of Electrical Drivess - Chapter 6 pptx

... 166 FUNDAMENTALS OF ELECTRICAL DRIVES SCOPE2 SCOPE1 u 1 i 2S U 1 @ 2D i 2D 0 i 2S i 1 @ 2S 0 @ 2S i 1 i 2D @ 1 @ 2D @ 1 381 .051 17.1 48 220.000 782 .597m 9.901 17.1 48 9. 088 451 .83 3m ... results NOTE1 PI @ 1 i m u 1 1.25 @ 1 @ s U 2 u 2 u 1 U 1 i 2 i 1 I1 I 2 P 1 Q 1 @ s @ s @ 2 1.250 83 3.333m 392.699 1.250 314.159 45.345 78. 540 392.699 226.725 154.4...
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Fundamentals of Electrical Drivess - Chapter 7 pps

Fundamentals of Electrical Drivess - Chapter 7 pps

... directly 182 FUNDAMENTALS OF ELECTRICAL DRIVES example, in the two-pole machine we can rotate the resultant magnetic field by an angle of π 2 radians by way of a voltage excitation sequence of the ... physically Chapter 7 INTRODUCTION TO ELECTRICAL MACHINES 7.1 Introduction This chapter considers the basic working principles of the so-called ‘clas- sical’ set of machines...
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