fundamentals of heat and mass transfer solutions manual phần 5 ppsx

... the Explore and Graph options of IHT. 5 10 15 20 25 Freestream velocity, uinf(m/s) 0 50 0 1000 150 0 2000 250 0 3000 350 0 4000 Power dissipation, q(W) Continued Dimensions of chip and pin fin. ... at x = 95 mm, 10x0.095m hh. = = 1/21/3 10x k h0. 453 RePr x = 5 x -62 ux40 m/s0.0 95 m Re2.0 651 0 18.410 m/s ν ∞ × ===× × ( ) ( ) 1/2 1/3 52 10 0.0282 W/mK h0. 453 2.0 6...

Ngày tải lên: 08/08/2014, 17:20

... values of P and R as given by Fig. 11.11 with ( ) ( ) ( ) ( ) P 953 5/300 350 .23R300196/120 351 .22=−−==−−= giving F ≈ 1. Based upon CF arrangement, ( ) ( ) ( ) ( ) m,CF T300 951 9635C/n300 95/ 196.2 351 82K.  ∆=−−−°−−=  l l Using ... 210.45W/K C C 755 .25W K == == . Hence, C min /C max = 0.279 and () max min h,i c,i q C T T 210. 45 W K (100 K) 21,045W =−= = max q q 14,732W 2...

Ngày tải lên: 08/08/2014, 17:20

... and only for surface and surrounding temperature differences of 50 to 100°C. Coefficients (W/m 2 ⋅K) T s (°C) ε h r h r,a h 35 0. 05 0.32 0.32 2.1 0.9 5. 7 5. 7 1 35 0. 05 0 .51 0 .50 ... m) 2 ( 85 - 15) ° C = 0. 35 W. < In the dielectric liquid P max = 3000 W/m 2 ⋅ K(0.0 05 m) 2 ( 85- 15) ° C = 5. 25 W. < COMMENTS: Relative to liqui...

Ngày tải lên: 08/08/2014, 17:20

... system. PROBLEM 3 .50 (Cont.) 0.0 35 0.0 45 0. 055 0.0 65 0.0 75 Outer radius of insulation, r3(m) 0 400 800 1200 1600 2000 Heat loss, qprime(W/m) q1 0.0 35 0.0 45 0. 055 0.0 65 0.0 75 Outer radius of insulation, ... trial -and- error solution, T s,o ≈ 50 2K. Hence the heat loss is () ( ) 44 oo s,o ,o o s,o sur q = D h T T D T T πεπσ ∞ ′ −+ − () ( )() 28444 24 W q = 0.07...

Ngày tải lên: 08/08/2014, 17:20

... x and y are in mm and the temperatures are in ° C. y\x 0 15 30 45 60 0 50 80.33 85. 16 80.33 50 15 50 63 .58 67.73 63 .58 50 30 50 56 .27 58 .58 56 .27 50 45 50 52 .91 54 .07 52 .91 50 60 50 51 .32 51 .86 ... 52 .91 50 60 50 51 .32 51 .86 51 .32 50 75 50 50 .51 50 .72 50 .51 50 90 50 50 50 50 50 The improved prediction of the temperature f...

Ngày tải lên: 08/08/2014, 17:20

... 3 25 3 25 3 25 1 18 304.2 324.7 3 25 3 25 3 25 3 25 3 25 3 25 2 36 303.2 3 15. 3 324 .5 3 25 3 25 3 25 3 25 3 25 3 54 294.7 313.7 320.3 324 .5 3 25 3 25 3 25 3 25 4 72 293.0 307.8 318.9 322 .5 324 .5 3 25 3 25 3 25 ... p ⋅∆ t = 300 p (s) = 5 p (min). pt(min) T 0 T 1 T 2 T 3 T L ( ° C) 0 0 85 85 85 85 20 1 85 85 85 52 .5 20 2 10 85 85 68.8 52 .5 20 3 85...

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... (K) (Assumed) Eq. (5) Eq. (6) Eq. (7) 1 1000 3.0 25 × 10 -2 348.6 9 15. 0 2 950 4.321 × 10 -2 463.7 898. 3 900 5. 041 × 10 -2 52 4.6 891.0 4 890 5. 2 15 × 10 -2 53 9.0 889 .5 Hence, we find 2 am,o m5.2210 kg/s ... temperature, volume and properties of pharmaceutical. Heat transfer coefficient at outer surface and dimensions of coil. FIND: (a) Expressions for T c (t) a...

Ngày tải lên: 08/08/2014, 17:20

... 3.03 Table A-6, Water 0.497 650 0. 158 3. 15 0 .50 4 Table A -5, Ethylene glycol 5. 15 260 0.0936 55 .0 0. 65 ANALYSIS: The electrical power (P e ) required to offset convection heat transfer is ( ) ( ) 2 convsss qhATThDTT. π ∞∞ =−=− (1) The ... ) D 2 1/6 8 8/27 9/16 0.3871.0 251 0 Nu0.6 056 .93 10 .55 9/0.703  ×   =+=    +     D 2 D hNuk/D56.930.0285W/mK/0.300m5....

Ngày tải lên: 08/08/2014, 17:20

... for q sh - d / q tot = 0 .5, 1 or 1 .5 % was computed and plotted as a function of the sample emissivity. 0. 05 0. 15 0. 25 0. 35 Sample emissivity, epss 50 100 150 200 250 Shield temperature, Th ... 0 .55 9 0.7 15 =+ =⋅ +           (5) With values of ε and α from part (a), the rate of temperature change with time is () () 824 2 8244 s 3 4 0...

Ngày tải lên: 08/08/2014, 17:20

... 13 .5 or Table 13 .5, () 1/2 2 2 14 4 1 F 0 .5 S S 4 r /r =−−       (5) () 1/2 2 2 14 F 0 .5 5.01 5. 01 4 15/ 150 0.001997 =−− =       22 4 22 1 1 R 1 0. 05 S 1 1 5. 010 R0 .5 ++ =+ ... of heat transfer to tube without ash deposit, (b) Rate of heat transfer with an ash deposit of diameter D d = 0.06 m, (c) Effect of deposit diameter and con...

Ngày tải lên: 08/08/2014, 17:20