Fundamentals of Finite Element Analysis phần 6 pptx

... spreadsheet program) to obtain [C] −1 =   0.2339 −0. 062 4 0.01 56 −0. 062 4 0.2495 −0. 062 4 0.01 56 −0. 062 4 0.2339   Hutton: Fundamentals of Finite Element Analysis 7. Applications in Heat Transfer Text ... z 3 ) Figure 7.19 Cross section of a three-node axisymmetric element. Recall that the element is a body of revolution. Hutton: Fundamentals of Finite Ele...

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... model definition is a nicety of modern finite element software; automated analysis of results is not. Analysis of results is the postprocessing phase of finite element analysis. Practical models ... Mechanics or  k (1)  = 1 1250   62 5 62 5 0 62 5 62 5 0 000   + 1 1250   00 0 0 62 5 62 5 0 62 5 62 5   =   0.5 −0.50 −0.51−0.5 0 −0.50.5   The element nodal fo...

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... method, Hutton: Fundamentals of Finite Element Analysis 1. Basic Concepts of the Finite Element Method Text © The McGraw−Hill Companies, 2004 4 CHAPTER 1 Basic Concepts of the Finite Element Method the ... October 1 968 . 13. Wilson, E. L., and R. E. Nickell. “Application of the Finite Element Method to Heat Conduction Analysis. ” Nuclear Engineering Design 4 (1...

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... F 2 K 35 U 5 + K 36 U 6 = F 3 K 45 U 5 + K 46 U 6 = F 4 K 55 U 5 + K 56 U 6 = F 5 K 56 U 5 + K 66 U 6 = F 6 (3.44) Hutton: Fundamentals of Finite Element Analysis 3. Truss Structures: The Direct ... 1333 5 5.33(10 −4 ) 5333 6 −5 .67 (10 −4 ) − 565 7 7 2 .67 (10 −4 ) 266 7 8 4.00(10 −4 ) 4000 Hutton: Fundamentals of Finite Element Analysis 2. Stiffnes...

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... Flexure Elements Table 4.5 Global Stiffness Matrix 1234 567 1 19 ,62 7.2 2.944 ×10 6 −19 ,62 7.2 2.944 ×10 6 000 2 2.944 ×10 6 5.888 ×10 8 −2.944 ×10 6 2.944 ×10 8 000 3 −19 ,62 7.2 −2.944 ×10 6 66, 350.4 ... −19 ,62 7.2 2.944 ×10 6 −27,0 96 4 2.944 ×10 6 2.944 ×10 8 0 11.78 ×10 8 −2.944 ×10 6 2.944 ×10 8 0 50 0 −19 ,62 7.2 −2.944 ×10 6 19 ,62 7.2 −2.944 ×10 6 0 6 0 0...

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... 1, 4 (5.50) Hutton: Fundamentals of Finite Element Analysis 6. Interpolation Functions for General Element Formulation Text © The McGraw−Hill Companies, 2004 166 CHAPTER 6 Interpolation Functions ... y 3 ) Figure 6. 9 Three-node triangle having an element coordinate system attached to the element. Hutton: Fundamentals of Finite Element Analysis 6. Interpolat...

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... C 0 problems in finite element analysis? 6. 10 Repeat Problem 6. 9 for cubic polynomials in three dimensions. 6. 11 Derive Equation 6. 38. 6. 12 Show that Equations 6. 36 and 6. 43 are identical. 6. 13 Using area ... to Hutton: Fundamentals of Finite Element Analysis 6. Interpolation Functions for General Element Formulation Text © The McGraw−Hill Companies, 2004 P...

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... 42.914 21 100.03 99.37 47.109 45.215 22 67 .10 64 .67 51.535 49.121 23 40.55 39. 36 57.8 36 55.499 24 18.98 18.28 68 .142 65 .425 45 67 .88 65 .89 41.7 06 40.799 46 103.87 100.74 42.359 41.018 This solution ... 2k 14 ␦ 1 ␦ 4 +···+2k 56 ␦ 5 ␦ 6 + k 66 ␦ 2 6  − f 1x ␦ 1 − f 2x ␦ 2 − f 3x ␦ 3 − f 1y ␦ 4 − f 2y ␦ 5 − f 3y ␦ 6 (9. 26) The quadratic function representation o...

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... product [ A ] T [M][A] = 1 m   0.29 56 0.4289 0 .60 64 0 .65 75 0. 561 8 −0.3550 0 .69 30 −0.7124 0.0782     m 00 0 m 0 002m   ×   0.29 56 0 .65 75 0 .69 30 0.4289 0. 561 8 −0.7124 0 .60 64 −0.3550 0.0782   =   100 010 001   as ... is [A] T [K ][ A] = k m   0.29 56 0.4289 0 .60 64 0 .65 75 0. 561 8 −0.3550 0 .69 90 −0.7124 0.0782     3 −20 −23−1 0 −11   ×   0.29 5...

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... 279 Finite element, 2, 12 Finite element analysis (FEA). See Finite element method (FEM) Finite element formulation axisymmetric heat transfer, 273–2 76 axisymmetric stress analysis, 359– 360 general ... matrix, 21–22 Element transformation, 58 61 Elementary beam theory, 91–94 Elementary strength of materials theory, 150 Element- node connectivity table, 66 Elemen...

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