An Introduction to Thermodynamics phần 2 potx
An Introduction to Thermodynamics phần 2 potx
... preceding
∫
=−=∆
2
1
12
E
E
dEEEE
2
1
2
2
2
1
2
1
2
1
xxxdx
x
x
−=
∫
( ) ( )
1 122
,
,
,
,
22
11
22
11
yxyxxydydxxdy
yx
yx
yx
yx
−==+
∫∫
∫
22
11
,
,
yx
yx
ydx
( )
+−+=+=
∫∫
1
3
12
3
2
2
,
,
3
3
1
3
3
1
3
2
1
22
11
xxxxdxxydx
x
x
yx
yx
7/10/07 ... 7 /2 R = 29 J/mol·K. Inserting this
P
(approximate) value for H ,
2
= 2 mol x 29 J/mol·K x 25 K
=...
An Introduction to Thermodynamics phần 10 potx
... )
axva
aaxvdxdyaxvv
o
oof
2/
22 2/1/ 2
2
2/ 1
22
+=
+=+=
−
( )
dT
P
nR
dV = P constant
( )
dP
P
- nRT
dV = T
2
constant
drrdA = 2
π
dx
dx
dy
dy =
7/10/07 A- 125
f = q q /r df/dr = - 2q q /r
1 2 1 2
2 3
Differentials. ... (Table A2) that
(A31)
( )
12
TT
P
nR
−
(A23) ) ,0(
12
∑ ∑
∞→→∆−=∆==∆ NVVVVdVV
i
N
i
i
( )
(A24)
121 2
T
P
nR
TT
P
nR
VVV ∆=−=−=∆
(A25)
2
P...
An Introduction to Thermodynamics phần 1 pdf
... -14.0 0 .25 1.0
2
H O ,25 g 82. 2 66 .2 -7.8 0. 125 1.0
2
Al, 50g 86.35 66.35 -3.65 0.0050 0 .22
Al, 25 g 88. 12 68. 12 -1.88 0. 027 6 0 .22
* Temperatures in C. ∆T is the temperature change of the sample and
o
s
∆T ... at constant volume from 25 C to
2
o
50 C. For a diatomic gas near room temperature, C is constant and is about 5 /2 R = 21
o 4
V
J/mol·K. The gas can do no w...
An Introduction to Thermodynamics phần 3 docx
... C
P
o
He 20 .8 -20 0 up
H 28 .8 25 to 20 0
2
O 29 .4 25 to 20 0
2
H O(g)* 36.4 25 to 20 0
2
SO (g) 41.9 25 to 20 0
2
S (r) 23 .7 25 to 20 0
S (m) 25 .9 95 to 120
*For rough calculations it is sufficient to set
C ... pressure expands slowly at 25 C against a
2
o
constant pressure of 1 atm.
4. Calculate the work done when 0 .25 mol of SO at 27 C and 1 a...
An Introduction to Thermodynamics phần 4 ppsx
... -313.3
2 2 3
C (gr) + O CO +3.0
2 2
CO + ½ O CO -86.36
2 2
H + Cl 2 HCl +19.6
2 2
H + F 2 HF +14.1
2 2
H + I (c) 2 HI +166 .2
2 2
H + ½ O H O (lq) -163.1
2 2 2
H + S (rh) H S +43.14
2 2
N + 3H 2 ... 22 7.4 20 9.9
2 2
Fe O c - 824 . -7 42. 2 C H g 52. 4 68.4
2 3 2 4
Fe O c -1118.4 -1015.4 C H g -84.0 - 32. 0
3 4 2 6
HBr g -36.3 -53.4 CH OH g -20 1.0 -1...
An Introduction to Thermodynamics phần 5 docx
... ∆S to be positive or negative? Explain.
a. Ag O (s) 6 2 Ag (s) + ½ O (g)
2 2
b. 2 CO (g) + O (g) 6 2 CO (g)
2 2
c. 2 C (s) + O (g) 6 2 CO (g)
2
d. CaH (s) + 2 H O (l) 6 Ca(OH) (s) + 2 H (g)
2 2 ... (g)
2 2 2 2
e. H (g) + I (g) 6 2 HI (g)
2 2
f. 2 H (g) + O (g) 6 2 H O (l)
2 2 2
g. n C H (g) 6 — (C H ) — (polyethylene)
2 4 2 4 n
18. A Dewar flask con...
An Introduction to Thermodynamics phần 6 docx
... at 25 C is 18 x 10 m and RT is 8.314 x 29 8 = 2. 48 kJ/mol·K. Thus if N , the mole
o -6 3
2
(
)
(15c) 0
22 2
kcPc =→
(
)
( )
B
B
BB
A
A
AA
ckfc
ckfc
22 2
22 2
0
0
=→
=→
BA
ff
22
=
B
B
A
A
ckck
22
=
( ... (25 a) 0 ,
3 322 11
=⋅⋅⋅+++ GdnGdnGdnPT
( )
(27 ) ln 0
2
2
2
2
2
2
22 22
dN
N
dN
N
f
df
NfdNN ===→
7/10/07 3- 71
Equation 22 arises from the definition of partial mol...
An Introduction to Thermodynamics phần 7 pot
... 62. 20
25
5
ln478 ,26 40,16ln
ln
3
2/ 32/ 1
2/ 32/ 1
22
3
22
3
−=
+−=+∆=
+∆=∆
HN
NH
o
HN
NH
o
PP
P
RTG
aa
a
RTGG
(
)
(
)
OAg
2/ 1
O
2
Ag
2
2
ln
a
aa
RTGG
o
+∆=∆
(
)
(
)
kJ/mol
1.150
-
10ln 24 78559001010ln ... is
3
determined by equation 15, which can be rewritten as
(
)
(
)
3-
2/ 32/ 1
10
x
2
.
1
ln J/mol 640,16
3
22
=
−==∆
=
K
KRTG
a
aa
K
o
NH
HN
(
)
(
)
( )...
An Introduction to Thermodynamics phần 8 pdf
... 6 Ag + I -0.1 522 4 Hg + 2e 6 Hg 0.851
- ++ ++
2
Sn + 2e 6 Sn -0.1375 2 Hg + 2e 6 Hg 0. 920
++ ++ ++
2
Pb++ + 2e 6 Pb -0. 126 2 NO + 4 H + 3e 6
3
- +
O + H O + 2e NO + 2 H O 0.957
2 2 2
6 HO + OH ... 0. 521
2
+
Mn + 2 OH -1.5 I + 2e 6 2 I 0.5355
- -
2
Cr + 2e 6 Cr -0.913 MnO + e 6 MnO4 0.558
++ - =
4
Zn + 2e 6 Zn -0.7 628 MnO + 2 H O + 3e
++ -
4 2
2 CO (g) + 2 H +...
An Introduction to Thermodynamics phần 9 ppsx
... 72. 1
CO g 21 3.78 NaOH c 64.5
2
CS g 23 7.8 O g 20 5.15
2 2
Cl g 22 3.1 O g 23 8.9
2 3
F g 20 2.8 P red 22 .8
2
H g 130.68 white 41.1
2
HBr g 198.70 PH g 21 0 .2
3
HCl g 186.90 S rhombic 32. 05
HF ... 29 1.5
6
HI g 20 6.6 SO g 24 8 .2
2
H O g 188.83 CBr g 358.1
2 4
H O g 23 2.7 CCl g 309.4
2 2 4
H S g 20 5.8 lq 21 4.4
2
I c 116.1 CF g 26 1.6
2 4
g...
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