ADVANCED THERMODYNAMICS ENGINEERING phần 7 ppt
... the figure, and the extensive 146 146.5 1 47 1 47. 5 148 148.5 149 149.5 150 150.5 151 0.04 0.05 0.06 0. 07 0.08 0.09 0.1 0.11 0.12 0.13 0.14 0.15 0.16 0. 17 0.18 0.19 0.2 v, m 3 / kmol e s, kJ/ kmole ... from theory c 3 = 0.4 275 , c 4 = 0.08664. If 0 50 100 150 200 0 0.1 0.2 0.3 0.4 0.5 0.6 0 .7 0.8 v, m 3 /kmol e P, bars 5 67 593 615 T 3 = 615 K T 1 = 59 3 T 2 = 56 7 A NS F G...
Ngày tải lên: 08/08/2014, 15:21
ADVANCED THERMODYNAMICS ENGINEERING phần 1 ppt
... States of America 1 2 3 4 5 6 7 8 9 0 Printed on acid-free paper Library of Congress Cataloging-in-Publication Data Annamalai, Kalyan. Advanced thermodynamics engineering / Kalyan Annamalai ... taught several courses at Texas A&M including Advanced Thermodynamics, Combustion Science and Engineering, Conduction at the graduate level and Thermodynamics, Heat Transfer, Com-...
Ngày tải lên: 08/08/2014, 15:21
ADVANCED THERMODYNAMICS ENGINEERING phần 6 ppt
... 169.59 A o 30.54 22.54 16 .77 8 17. 229 29 .75 28.58 29.1519 26 .76 5 † B o 0.01030 0.1141 077 0.2865 0. 475 7 .025 .00 377 –.001 573 0. 175 94 † C o 0.0 130196.35 0 0 –154808. 50208 0.292×10 –6 –. 27 10 7 D o 0.0 –0.329×10 –4 –2. 276 ×10 –4 2.893×10 –4 0.0 ... NH 3 N 2 CO 2 W m 18.015 86. 476 102.03 66.05 17. 03 28.013 44.01 120.92 P c (bar) 220.9 49 .77 5 40. 67 45.20 112.8 33.9 73 .9...
Ngày tải lên: 08/08/2014, 15:21
Software Engineering (phần 7) ppt
... volatilifyw 0. 87 1 .OO 1 . 1 5 1 .30 i : ': j . . #Computer turnaround time 0 . 87 1 .OO 1 .0Z 1 . 1 5 j . ) ' l Fersonnel ottributes . i 1 Analyst capabilities 1 .46 i . 1 9 1 .OO 0.86 0 .71 l ... capability 1 .:2 1 . 1 7 1 .OO 0.86 0 .70 t p I r Virtual machine experience* 1 .2 1 1 . 1 O 1 .OO 0.90 ' 1 ' ; 1 ; Frogramming Ianguage experience 1 . 1 zl. 1 .Q7 1 .00...
Ngày tải lên: 07/07/2014, 06:20
ADVANCED THERMODYNAMICS ENGINEERING phần 2 ppsx
... + c vo /R). (F) Using R = R /M = 8.314 ÷ 28. 97 = 0.2 87 kJ kg –1 K –1 , T 2 /T 1 = (200÷100 + 0 .7 0.2 87) ÷ (1 + 0 .7 ÷ 0.2 87) = 1.29, or T 2 = 3 87 K. Substituting this result in Eq. (E), V 2 /V 1 ... (E), V 2 /V 1 = (1 + (c vo /R)(P 1 /P 2 ))/(1 + c vo /R). (G) ∴ V 2 /V 1 = (1+ 0 .7 × 100 ÷ (0.2 87 × 200)) ÷ (1+ 0 .7 ÷ 0.2 87) = 0.65, and V 2 = 0.65 × 0.1 = 0.065 m 3 . Rema...
Ngày tải lên: 08/08/2014, 15:21
ADVANCED THERMODYNAMICS ENGINEERING phần 3 pdf
... m A c vA ln (T A / 273 ). (F) Therefore, at 290 K, S A = 0.4 (kg) × 0 .71 3 (kJ kg –1 K –1 ) × ln(290/ 273 ) = 0.0 172 2 kJ K –1 , and at 2 97. 335 K, S A = 0.02435 kJ K –1 . For a 7. 335 K temperature ... – 0.0 172 2 = 0.0 071 3 kJ K –1 . At 350 K, S = S W + S A = 1.0395 + 0.0 172 2 = 1.0568 kJ K –1 . At 349.5 K, S = 1.0 579 kJ K –1 . Therefore, dS = dS W + dS A = – 0.0059 + 0.0 0...
Ngày tải lên: 08/08/2014, 15:21
ADVANCED THERMODYNAMICS ENGINEERING phần 4 potx
... =1 × 673 – 298 × (1 × ln ( 673 /298)) = 430.2 kJ kg –1 , ψ a,e = 473 – 298 × 1 × ln ( 473 /298) = 335.3 kJ kg –1 , ψ w,i = 419 – 298 × 1.31 = 28.6 kJ kg –1 , and ψ w,e = 2 676 .1 – 298 × 7. 35 = ... (0.8314 × 298/0 .79 ) = 6190–298 × 193.5 + 100 × 31.4 = –48,333 kJ kmole –1 . Therefore, φ ∞ = 0.6 × (–46981) + 0.4 × (–48333) = – 475 21.8 kJ kmole –1 , and w ch = –52 473 .8 – (– 475 21....
Ngày tải lên: 08/08/2014, 15:21
ADVANCED THERMODYNAMICS ENGINEERING phần 5 potx
... SRK VW a´ 0.421 875 0.421 875 0.4 572 4 0.4 572 0.4 274 8 0.4 274 8 0.421 875 b´ 0.125 -0.02 0. 077 8 0. 077 8 0.08664 0.08664 0.125 c´ 0 0.145 0.1 878 26 0.1 878 26 0.08664 0.08664 0 d´ 0 0. 375 -0.03223 -0.03223 ... volume Z(T TP ,P TP ) = P v /( R T) = 0.00611× 371 5÷(0.08314× 273 ) = 1. Furthermore, employing Eq. (53), s( 273 , 371 5) – s o ( 273 , 371 5) ≈ 0, and using Eq. ( 57) s( 273...
Ngày tải lên: 08/08/2014, 15:21
ADVANCED THERMODYNAMICS ENGINEERING phần 8 doc
... K –1 . ν k h X k p k =X k P ˆ s s k o ( h – T o ˆ s ) k Reactants C 4 H 10 1 –126148 0.021 0.05 27 310.2 334 .7 –2258 87 O 2 9 .75 0 0.20 57 0.5141 205.1 210 .7 –6 278 1 N 2 36.66 0 0 .77 33 1.933 191.6 186.1 –55428 CO 2 4 –360 470 0.0818 0.205 269.3 282.52 –444302 H 2 O(g) ... = 5.25× ˆ g CO2 (3000, 4 bar, X CO2 =5.25/11. 37) + ^g CO (3000, 4 bar, X CO =3 .75 /11. 37) + ^g O2 (3000, 4...
Ngày tải lên: 08/08/2014, 15:21
ADVANCED THERMODYNAMICS ENGINEERING phần 9 pdf
... 309.6 72 .4 0. 274 0.0 974 0.165 182.3 184 .7 148 .7 376 .2 68.84 0.0308 3.86 071 0.04444 Nonane C 9 H 20 128.3 595 22 .73 0.252 0.5 477 0.4 37 219 .7 423 .7 120.6 293.8 1122.66 0.1886 45.4191 0. 272 04 Octane–n ... 231.1 79 .9 426.0 182.85 0.06 27 9.38315 0.09043 Propanol C 3 H 7 OH 60.1 536 .7 51 .7 0.253 0.2185 0.628 1 47. 0 370 .4 86.5 688.5 381.41 0. 074 8 16.2 471 0.1 078 9...
Ngày tải lên: 08/08/2014, 15:21