ADVANCED THERMODYNAMICS ENGINEERING phần 5 potx
ADVANCED THERMODYNAMICS ENGINEERING phần 5 potx
... SRK VW a´ 0.4218 75 0.4218 75 0. 457 24 0. 457 2 0.42748 0.42748 0.4218 75 b´ 0.1 25 -0.02 0.0778 0.0778 0.08664 0.08664 0.1 25 c´ 0 0.1 45 0.187826 0.187826 0.08664 0.08664 0 d´ 0 0.3 75 -0.03223 -0.03223 ... relations are also available, e.g., ω = (ln P R sat – 5. 92714 + 6.0964/T R,BP +1.28862 ln T R,BP – 0.169 35 T R,BP )/ ( 15. 257 8 – 15. 68 75/ T R,NBP + 0.4 357 7 T R,NBP )...
Ngày tải lên: 08/08/2014, 15:21
ADVANCED THERMODYNAMICS ENGINEERING phần 4 potx
... f5 )/(h f3 - h f4 ) = ((0.0 25 256 5.3+ 35) -(0.0 05 253 8.1+20) – (0.02)×104.9)/(188. 45 - 104.9) = 0.794 kg of water per kg dry air. The optimum work m ake up water w et air in 25 ° °° C , 35% Cold ... h v1 = 254 7.2, h v2 = 256 5.3, s g (25C) = 8 .55 8, with R= 8.314/18.02=0.461 kJ/kgk, s g1 =s g sat (25C) - Rln(p v1 /P v sat (T 1 ))= 8.6672 kJ/kg K, s g2 = 8. 353 1 kJ/kg K,...
Ngày tải lên: 08/08/2014, 15:21
ADVANCED THERMODYNAMICS ENGINEERING phần 1 ppt
... references and index. ISBN 0-8493- 255 3-6 (alk. paper) 1. Thermodynamics. I. Puri, Ishwar Kanwar, 1 959 - II. Title. III. Series. TJ2 65 .A 55 2001 621.402 ′ 1—dc21 20010 356 24 1.First Law 2.Adiabatic ... works International Standard Book Number 0-8493- 255 3-6 Library of Congress Card Number 20010 356 24 Printed in the United States of America 1 2 3 4 5 6 7 8 9 0 Printed on ac...
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ADVANCED THERMODYNAMICS ENGINEERING phần 2 ppsx
... and leaves a steady state open system, Eq. (52 ) yields δQ c.v. – δW c.v. = dm(∆e T ). (55 ) This expression may also be obtained by multiplying Eq. (53 ) by dm. xxvii. Closed System Equation (36) ... Eq. (50 ), (dU c.v /dt) = ˙ m i h i . (B) Figure 15b: Metabolic rates of different species. (Adapted from Scaling: Why is animal size so important. K.S. Nielsen, Cambridge University Press, p...
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ADVANCED THERMODYNAMICS ENGINEERING phần 3 pdf
... Hence, u(l,1 45. 5) = 377.7 + 54 42 =58 19.9 kJ kmole –1 , and u(l,240.3) = 58 19.9 + 76 .5 × (240.3 – 1 45. 5) = 13132 kJ kmole –1 . In the gaseous state s (g, 240.3) – s (l,240.3) = 20, 058 ÷240.3 = 83 .5 kJ ... 297.3 35 K, S A = 0.024 35 kJ K –1 . For a 7.3 35 K temperature rise, dS A = 0.024 35 – 0.01722 = 0.00713 kJ K –1 . At 350 K, S = S W + S A = 1.03 95 + 0.01722 = 1. 05...
Ngày tải lên: 08/08/2014, 15:21
ADVANCED THERMODYNAMICS ENGINEERING phần 6 ppt
... kg –1 ) 250 1.3 233.18 1389.0 2 15. 188 52 4 .53 4 169 .59 A o 30 .54 22 .54 16.778 17.229 29. 75 28 .58 29. 151 9 26.7 65 † B o 0.01030 0.1141077 0.28 65 0.4 757 .0 25 .00377 –.00 157 3 0.1 759 4 † C o 0.0 130196. 35 0 ... 233.14 233. 15 64.143 216 .55 233. 15 P ref (bar) 0.006113 1.04 95 0 .51 26 15 .7177 .1 253 5. 178 .6417 h ref (kJ kg –1 ) 0.01 0.0 0.0 150 .3 301. 45 0.0 u...
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ADVANCED THERMODYNAMICS ENGINEERING phần 7 ppt
... metastable vapor state K, σ = (– 953 0 .5 – (–9638.8)) 59 3 = 0.183 k kmole -1 K - . -4000 - 350 0 -3000 - 250 0 -2000 - 150 0 -1000 -50 0 0 50 0 1000 0 0. 05 0.1 0. 15 0.2 0. 25 0.3 v, m 3 /kmole a, kJ/kmole 0 20 40 60 80 100 120 140 160 180 200 P, ... state (∂T/∂v) u = – ((3/2) a/(c v T 1/2 v(v+b))) (F) 0 50 100 150 200 250 0 0. 05 0.1 0. 15 0.2 0. 25 0.3 0. 35 0.4 v, m 3...
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ADVANCED THERMODYNAMICS ENGINEERING phần 8 doc
... conditions. Time, sec CO, kmole CO 2 , kmole O 2 , kmole 05 3 4 t A 4.998 2.999 4.002 t B 4 .5 2. 75 4. 5 t C 4. 25 2.6 25 4. 75 t D 3. 75 2.3 75 5. 25 t E 3. 75 2.3 75 5. 25 dN dN dN CO O CO − = − − =+ − =+ + =+ 1 0 ... 0. 052 7 310.2 334.7 –2 258 87 O 2 9. 75 0 0.2 057 0 .51 41 2 05. 1 210.7 –62781 N 2 36.66 0 0.7733 1.933 191.6 186.1 55 428 CO 2 4 –360470 0.0818 0.2 05 269...
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ADVANCED THERMODYNAMICS ENGINEERING phần 9 pdf
... 0. 258 0.492 0.398 216.4 398.8 181.6 301 .5 919.40 0.1 652 38.0427 0.23836 Octene C 8 H 16 112.24 57 8. 15 25. 84 171 .5 394.2 919.13 0.1612 37.723 0.23 253 Oxygen O 2 32 154 .6 50 .5 0.288 0.0734 54 .4 ... C 3 H 8 44.1 369.8 42 .5 0.281 0.203 0. 153 85. 5 231.1 79.9 426.0 182. 85 0.0627 9.383 15 0.09043 Propanol C 3 H 7 OH 60.1 53 6.7 51 .7 0. 253 0.21 85 0.628 147.0 370.4 86 ....
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ADVANCED THERMODYNAMICS ENGINEERING phần 10 docx
... 1 .5 2 3 5 7 10 0.3 5. 987 5. 9 75 5. 957 5. 927 5. 868 5. 748 5. 628 5. 446 0. 35 5.8 45 5.833 5. 814 5. 783 5. 721 5. 5 95 5.469 5. 278 0.4 5. 7 5. 687 5. 668 5. 636 5. 572 5. 442 5. 311 5. 113 0. 45 5 .55 1 5. 538 5. 519 ... 5. 519 5. 486 5. 421 5. 288 5. 154 4. 95 0 .5 5.401 5. 388 5. 369 5. 336 5. 27 5. 1 35 4.999 4.791 0 .55 5. 252 5. 239 5....
Ngày tải lên: 08/08/2014, 15:21