ADVANCED THERMODYNAMICS ENGINEERING phần 2 ppsx

ADVANCED THERMODYNAMICS ENGINEERING phần 2 ppsx

ADVANCED THERMODYNAMICS ENGINEERING phần 2 ppsx

... tube. Solution Q 12 – W 12 = = U 2 – U 1 + KE 2 – KE 1 + PE 2 – PE 1 . 0+3000=U 2 –U 1 +( (20 00 2) (24 .6ms –1 ) 2 –0 +20 00×(9.81×100)–0)÷1000 =25 68 kJ, i.e., U 2 – U 1 = 3000 – 25 68 = 4 32 kJ. Remarks The ... c.v. With Wt = 2 kN, P 2 = 2 ÷ 0.01 = 20 0 kPa. Applying the First Law to the system, Q 12 – W 12 = 0 = E 2 – E 1 , or E 2 = E 1 . Neglecting the...
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ADVANCED THERMODYNAMICS ENGINEERING phần 1 ppt

ADVANCED THERMODYNAMICS ENGINEERING phần 1 ppt

... namely, ∂ 2 /∂x 1 ∂x 2 = ∂ 2 /∂x 2 ∂x 1 , ∂ 2 /∂x 1 ∂x 3 = ∂ 2 /∂x 3 ∂x 1 , , etc., and generate (k–1) equations for the k variables. Likewise, in terms of ∂ 2 /∂x 2 ∂x 1 = ∂ 2 /∂x 1 ∂x 2 , ∂ 2 /∂x 2 ∂x 3 ... index. ISBN 0-8493 -25 53-6 (alk. paper) 1. Thermodynamics. I. Puri, Ishwar Kanwar, 1959- II. Title. III. Series. TJ265 .A55 20 01 621 .4 02 ′ 1—dc21 2...
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ADVANCED THERMODYNAMICS ENGINEERING phần 3 pdf

ADVANCED THERMODYNAMICS ENGINEERING phần 3 pdf

... N CO 2 s CO 2 (T, P CO 2 ) + N N 2 s N 2 (T, P N 2 ), (B) S 1 = ( N CO 2 s CO 2 (T, P CO 2 ) + N N 2 s N 2 (T, P N 2 )) 1 , (C) S 2 = ( N CO 2 s CO 2 (T, P CO 2 ) + N N 2 s N 2 (T, P N 2 )) 2 ,where ... = 0.04 × 22 1.8 + 0.06 × 26 3.6 = 24 .69 kJ K –1 , and S 2 – S 1 = 24 .69 – 23 . 92 = 0.77 kJ K –1 . S 2 – S 1 – Q 12 /T b = σ 12...
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ADVANCED THERMODYNAMICS ENGINEERING phần 4 potx

ADVANCED THERMODYNAMICS ENGINEERING phần 4 potx

... h s s s s s s s 1 2 2 2 12 2 2 1 ∫ +− ∫ =− −− . The path 1 2 s involves no entropy change so that T (s 2 – s 2s ) – w 12 = h 2 – h 1 . Hence, – w 1–2s 2 = 23 45.4 – 3 422 .2 – 318.8 × (7.4 – 6.88) – 124 2.6 ... work is q 12 – w 12 = h 2 – h 1 , i.e., (A) w 12 = 25 85 – 3 422 = 837 kJ kg –1 . The heat rejected in the condenser q 23 – w 23 = h 3 – h 2 , i.e.,...
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ADVANCED THERMODYNAMICS ENGINEERING phần 5 potx

ADVANCED THERMODYNAMICS ENGINEERING phần 5 potx

... (1 /2) B 2 T v 2/ 3 . Furthermore, h = u + P v so that h = (1/4) B 2 T 2 v 2/ 3 + (1/6) B 2 T 2 v 2/ 3 = (5/ 12) B 2 T 2 v 2/ 3 , and (E) c P = (∂h/∂T) P = (5/ 12) B 2 (2T v 2/ 3 + (2/ 3) T 2 v –1/3 (∂ v /∂T) P ). ... VW a´ 0. 421 875 0. 421 875 0.45 724 0.45 72 0. 427 48 0. 427 48 0. 421 875 b´ 0. 125 -0. 02 0.0778 0.0778 0.08664 0.08664 0. 125 c´ 0 0.145...
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ADVANCED THERMODYNAMICS ENGINEERING phần 6 ppt

ADVANCED THERMODYNAMICS ENGINEERING phần 6 ppt

... subscript “o” µ N 2 , .mix = µ N 2 (29 8, 2 bar) + RT ln X N 2 = 29 8 – 29 8×(ln (29 8 27 3) – 0 .29 7×ln (2 1)) + 0 .29 7 29 8 ln(0.6) A mixture contains 60% N 2 and 40% O 2 at 29 8 K and 2 bar. The mixture ... (9a), bbXbX=+ )) 11 2 2 (24 c) Multiplying Eq (24 b) by X 2 , rearranging and simplifying, ) b 1 X 2 = ) b 2 X 2 - X 2 d b /dX 2 and using Eq. (24 c)...
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ADVANCED THERMODYNAMICS ENGINEERING phần 7 ppt

ADVANCED THERMODYNAMICS ENGINEERING phần 7 ppt

... X N 2 /X O 2 = 3.76. Furthermore, (X O 2( )l /X N 2( )l ) = (X O 2 /X N 2 )/( P N sat 2 (T)/ P O sat 2 (T)) (C) Since P N sat 2 (T) ≈ P O sat 2 (T), (X O 2( )l /X N 2( )l ) = (X O 2 /X N 2 ) ... AX 2, l 2 /((A/B) X 1( l ) +X 2( l ) ) 2 , ln γ 2 (58) = B X 1( l ) 2 /(X 1( l ) +(B/A)X 2( l ) ) 2 , (59) ln γ 2( l ) = – ln(X 2( l ) + X 1( l ) A...
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ADVANCED THERMODYNAMICS ENGINEERING phần 8 doc

ADVANCED THERMODYNAMICS ENGINEERING phần 8 doc

... – 126 148 0. 021 0.0 527 310 .2 334.7 22 5887 O 2 9.75 0 0 .20 57 0.5141 20 5.1 21 0.7 – 627 81 N 2 36.66 0 0.7733 1.933 191.6 186.1 –55 428 CO 2 4 –360470 0.0818 0 .20 5 26 9.3 28 2. 52 –4443 02 H 2 O(g) 5 21 5849 ... 28 2. 52 –4443 02 H 2 O(g) 5 21 5849 0.1 022 0 .25 6 23 2.7 24 4.05 28 8561 O 2 3 .25 22 707 0.0665 0.166 24 3.6 25 8.51 –54 326 N 2 36.66 21 46...
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ADVANCED THERMODYNAMICS ENGINEERING phần 9 pdf

ADVANCED THERMODYNAMICS ENGINEERING phần 9 pdf

... C 7 H 8 92. 14 591.7 41.1 0 .26 4 0.3158 178 .2 383.8 72. 0 364.7 6 12. 31 0.1037 24 .8408 0.149 62 Water H 2 O 18. 02 647.3 22 0.9 0 .23 0 0.056 0.344 27 3 .2 373 .2 333.7 22 58.3 1 42. 60 0. 021 1 5.53 12 0.03045 Xenon ... 0 .27 204 Octane–n C 8 H 18 114 .2 568.8 24 .8 0 .25 8 0.4 92 0.398 21 6.4 398.8 181.6 301.5 919.40 0.16 52 38.0 427 0 .23 836 Octene C 8 H 16 1 12. 24...
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ADVANCED THERMODYNAMICS ENGINEERING phần 10 docx

ADVANCED THERMODYNAMICS ENGINEERING phần 10 docx

... 37,867 22 5.317 -20 4 ,23 1 1,300 32. 114 30,353 37,704 22 7.869 -22 6,8 92 1,400 32. 540 33,586 37,548 23 0 .26 5 -24 9,800 1,500 32. 943 36,860 37,397 23 2. 524 -27 2,941 1,600 33. 323 40,174 37 ,25 2 23 4.6 62 -29 6,300 1,700 ... 1.76690 -24 5.118 325 325 .31 1.8345 23 2. 02 508.4 1.7 824 9 -25 3.99 925 330 330.34 1.93 52 235.61 489.4 1.79783 -26 2.9439 340 340. 42 2.149 24 2...
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