Báo cáo toán học: "Unimodal rays in the regular and generalized Pascal pyramid" ppt

... map returns the regular binomial coefficients in the Pascal triangle. We obtain the regular Pascal pyramid if r = 3. For the cases r ≥ 4 we will refer as generalized Pascal pyramids. The main purp ... k 1 + ···+ k m = n. In order to prepare the proof of Theorem 5, let introduce the notation of rays in generalized Pascal pyramids. As usual, a lattice ray in...

Ngày tải lên: 08/08/2014, 14:23

... Changing hierarchies in Chinese language education for the British Chinese learners. In Teaching and Learning Chinese in Global Contexts, eds. Linda Tsung and Ken Cruickshank, 11-28. Continuum International ... N.C.: Information Age Pub. Chen, Yea-Fen and Shih-Chang Hsin. 2011. The development of TCSL teacher training in Taiwan . In Teaching and learning Chinese in...

Ngày tải lên: 20/06/2014, 21:20

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Ngày tải lên: 05/08/2014, 15:20

Ngày tải lên: 05/08/2014, 15:21

... trivial.) Then, by the converse of Theorem 2.5 , it must be Q k  u ≥ 1. On the other hand, in the proof of Theorem the electronic journal of combinatorics 4 (1997), #R21 3 In the rest of this introductory ... as the diameter and the radius [16] . Here, after introducing these polynomials and recalling its main properties, we survey some of the main known results rela...

Ngày tải lên: 07/08/2014, 06:20

... c 2 n positive integer. The rough outline of the construction of a C 2l+1 in G(A)isthe following: First we will pick a number a ∈ A (6,1) with relatively large φ(a) and the remaining 2l numbers ... a C 2l+1 in G(A)first we pick a number a ∈ A (P r ,j 1 ) andthentheremaining2lnumbers will be chosen alternately from A (P r ,j 2 ) and A (P r ,j 3 ) . We will need the following lem...

Ngày tải lên: 07/08/2014, 06:22

... X n be a random variable equal to the sum of the fixed points in an element of G n \D n chosen uniformly at random. There is a gap if and only if the expected value of X n grows linearly with n.Inthiscase,n ... fixed points suffice, but r =2n requires at least three fixed points. Thus, the lack of further discontinuities in the graph of f(15,r) may, at first, seem counterintuitive....

Ngày tải lên: 07/08/2014, 07:21

... half of these permutations are odd. Now, interchange the entries containing the symbols n − 2 and n in these odd permutations. Together with the remaining even ones, they form a desired Latin square. It ... main results characterize intersecting families of maximal size in these groups. Theorem 1.2 Let n ≥ 2 and I be an intersecting family in A n . Then |I| ≤ (n − 1)!/2. Moreo...

Ngày tải lên: 07/08/2014, 15:22

... 2}. The first string of +3’s must exhaust the 0-congruence class and therefore we reach up to the vertex 3k + 3. The second string of −3’s will describe another congruence class in decreasing ... 3 4 + 3 2 Remark 3.13 The linear realizations of {2 6 , 3 c }, {2 8 , 3 c } presented in Lemma 3.11 are all perfect. Hence it can be seen in the proof by induction in the previ...

Ngày tải lên: 08/08/2014, 12:22