Báo cáo toán học: "Proof of the (n/2 − n/2 − n/2) Conjecture for large n" pps

Báo cáo toán học: " Proof of the Alon-Tarsi Conjecture for n = 2r p" docx

Báo cáo toán học: " Proof of the Alon-Tarsi Conjecture for n = 2r p" docx

... +1)=0=⇒AT(2n) =0. Together, these imply the truth of the Alon-Tarsi conjecture for n =2 r (p+1) for any r ≥ 0 and any odd prime p (and, by the table of known values, for p =2also). Our goal ... to N, so there is only one isotopy class in the sum (8), and its size is not divisible by p. Therefore, fdels(p) − fdols(p) ≡|NG|sgn(N)(modp). (9) Proof of the Alon-Tarsi...

Ngày tải lên: 07/08/2014, 06:22

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Báo cáo toán học: "Proof of the Razumov–Stroganov conjecture for some infinite families of link patterns" pdf

Báo cáo toán học: "Proof of the Razumov–Stroganov conjecture for some infinite families of link patterns" pdf

... − α i )  a+c+1−m j=c+ 1− (z − β j )  (3.7) To connect with Eq. (2.9), set P  (z) = (z − α 1 ) · · ·(z − α −1 ) (z − β 1 ) · · ·(z − β c− ) Q m (z) = (z − α b+m+1 ) · · ·(z − α b+c ) (z − ... F a,b;1 satisfies the following simple recurrence formula: F a,b;1 = α b+1 − γ a+b α b+1 − β a F a−1,b;1 + γ a+b − β a+1 α b − β a+1 F a,b−1...

Ngày tải lên: 07/08/2014, 13:21

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Báo cáo toán học: "Proof of the combinatorial nullstellensatz over integral domains, in the spirit of Kouba" docx

Báo cáo toán học: "Proof of the combinatorial nullstellensatz over integral domains, in the spirit of Kouba" docx

... substantially), and it is the purpose of the present note to try to lay bare the basic mechanism of Kouba’s proof. 2 Proof of Theorem 2 The proof of the Theorem 2 will be based on the following simple ... question Is there any interesting use for the fact that even in the case of integral domains the coefficients of Kouba’s map can be explicitly expressed in term...

Ngày tải lên: 08/08/2014, 11:20

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Báo cáo toán học: "Proof of the (n/2 − n/2 − n/2) Conjecture for large n" pps

Báo cáo toán học: "Proof of the (n/2 − n/2 − n/2) Conjecture for large n" pps

... |Y ′ | ≥ n/2 − n, then |Y | ≥ (1 − √ 3θ ) (n/2 − n). Since δ(X, V (G 1 )) ≥ n − n, we have δ(X, Y ) ≥ |Y |− n ≥ (1 − √ 3θ ) (n/2 − n) − θn >  1 2 − √ 3θ 2 − 2θ  n ≥  n 2  − √ θn, where the last ... graphs with degree constraints. the electronic journal of combinatorics 18 (2011), #P27 5 Proof of the (n/2 n/2 − n/2) Con...

Ngày tải lên: 08/08/2014, 12:23

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Báo cáo toán học: " Enhancement of the photoelectric performance of dye-sensitized solar cells by using Ag-doped TiO2 nanofiber in TiO2 nanoparticle film as an electrode" pot

Báo cáo toán học: " Enhancement of the photoelectric performance of dye-sensitized solar cells by using Ag-doped TiO2 nanofiber in TiO2 nanoparticle film as an electrode" pot

... understood by either looking at the improved connection of TiO 2 nanoparticles or the Ag effect of the electrons during transition. The increased electron lifetime and the reduction of the electron ... surface of the film, so the nanofiber-added TiO 2 film has an advantage to having higher adsorption of dye molecules and also supports the penetration of th...

Ngày tải lên: 20/06/2014, 20:20

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Báo cáo toán học: " Performance of the audio signals transmission over wireless networks with the channel interleaving considerations" pot

Báo cáo toán học: " Performance of the audio signals transmission over wireless networks with the channel interleaving considerations" pot

... show the variation of the Cr and the MSE of the received audio signals with the channel SNR, respectively. These figures reveal that the proposed chaotic interleaver improves the quality of the ... 16 gives the throughput variation with the different velocity of the mobility. So, these results indicate the mobility effects on the different metric of th...

Ngày tải lên: 20/06/2014, 20:20

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Báo cáo toán học: " Refinements of the Heinz inequalities" ppt

Báo cáo toán học: " Refinements of the Heinz inequalities" ppt

... 3 Proof. First assume that 0 ≤ µ ≤ 1 2 . Then it follows by the previous lemma that f  1 − µ + µ 2  ≤ 1 1 − 2µ  1− µ f(t)dt ≤ 1 4  f(µ) + 2f  1 − µ + µ 2  + f(1 − µ)  ≤ f(µ) + f(1 − µ) 2 , and ... 2          A 1 2 XB 1 2           ≤       A µ XB 1− + A 1− XB µ       . (2.3) Since lim µ→ 1 2 1 |1 − 2µ|      1−...

Ngày tải lên: 20/06/2014, 21:20

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