Gear Geometry and Applied Theory Episode 2 Part 4 pdf
... (Fig. 14. 3.3): x 2 = r b2 cos(θ 2 − η 2 ) + u 2 cos λ b2 sin(θ 2 − η 2 ) y 2 =−r b2 sin(θ 2 − η 2 ) + u 2 cos λ b2 cos(θ 2 − η 2 ) z 2 = u 2 sin λ b2 − p 2 θ 2 ( 14. 3.15) n 2 = [sin λ b2 sin(θ 2 − ... λ b2 sin(θ 2 − η 2 ) y 2 =−r b2 sin(θ 2 − η 2 ) + u 2 cos λ b2 cos(θ 2 − η 2 ) z 2 =−u 2 sin λ b2 + p 2 θ 2 ( 14. 3.17) n 2 = [sin...
Ngày tải lên: 08/08/2014, 12:21
... φ 2 =−r a2 sin w a2 2r a2 r ac cos(φ c − φ 2 + ) + E c cos φ 2 = r a2 cos w a2 2r a2 (11.3.8) P1: JTH CB6 72- 11 CB6 72/ Litvin CB6 72/ Litvin-v2.cls February 27 , 20 04 0 : 24 11 Internal Involute Gears 11.1 INTRODUCTION A gear drive ... system. P1: FHA/JTH CB6 72- 10 CB6 72/ Litvin CB6 72/ Litvin-v2.cls February 27 , 20 04 0:19 10.8 Contact Ratio 29 3 Thus, l = KB...
Ngày tải lên: 08/08/2014, 12:21
... ( 12. 2 .4) Equations ( 12. 2.1), ( 12. 2.3), and ( 12. 2 .4) yield tan µ 1 =− m 12 (φ 1 ) ± 1 m 12 (φ 1 ) ( 12. 2.5) tan µ 2 =± m 12 (φ 1 ) ± 1 m 12 (φ 1 ) . ( 12. 2.6) Here, m 12 = (∂/∂φ 1 )[m 12 (φ 1 )]. Function ... ratio function is m 12 = dφ 1 dφ 2 = k 1 k 2 y x ( 12. 2.8) P1: GDZ/SPH P2: GDZ CB6 72- 12 CB6 72/ Litvin CB6 72/ Litvin-v2.cls February 27 , 2...
Ngày tải lên: 08/08/2014, 12:21
Gear Geometry and Applied Theory Episode 2 Part 3 pot
... equation r t (θ 2 ,φ 2 ) = M t2 (φ 2 )r 2 (θ 2 ), (13.6.5) which yields θ 2 ≥ 90 ◦ ,φ 2 = 2( θ 2 − 90 ◦ ) x t =−r 2 (φ 2 − sin φ 2 ) +ρ 2 sin(θ 2 − φ 2 ) y t =−r 2 (1 −cos φ 2 ) −ρ 2 cos(θ 2 − φ 2 ). (13.6.6) Axis ... r 2 . P1: GDZ/SPH P2: GDZ CB6 72- 12 CB6 72/ Litvin CB6 72/ Litvin-v2.cls February 27 , 20 04 0: 32 12. 11 Evolute of Tooth Profiles...
Ngày tải lên: 08/08/2014, 12:21
Gear Geometry and Applied Theory Episode 2 Part 5 pptx
... section X ( 12) f , Y ( 12) f , Z ( 12) f components of contact force (Figs. 14. 8 .2 and 14. 8.3) P1: GDZ/SPH P2: GDZ CB6 72- 15 CB6 72/ Litvin CB6 72/ Litvin-v2.cls February 27 , 20 04 0 :44 15 .2 Axodes of Helical Gears ... M ba [a c u 2 c u c 01] T (15 .2. 7) P1: GDZ/SPH P2: GDZ CB6 72- 15 CB6 72/ Litvin CB6 72/ Litvin-v2.cls February 27 , 20 04 0 :44 42 2 Modified Involu...
Ngày tải lên: 08/08/2014, 12:21
Gear Geometry and Applied Theory Episode 2 Part 6 ppsx
... CB6 72/ Litvin CB6 72/ Litvin-v2.cls February 27 , 20 04 0 :44 15.9 Stress Analysis 43 9 (Ave. Crit.: 75%) S, Mises +1.569e+03 +4. 956e- 04 +7.500e+01 +1.500e+ 02 +2. 250e+ 02 +3.000e+ 02 +3.750e+ 02 +4. 500e+ 02 +5 .25 0e+ 02 +6.000e+ 02 +6.750e+ 02 +7.500e+ 02 +8 .25 0e+ 02 +9.000e+ 02 1 2 3 Bending ... 3D-space. Worm Helical gear Figure 16.1 .2: Gear drive formed by...
Ngày tải lên: 08/08/2014, 12:21
Gear Geometry and Applied Theory Episode 2 Part 7 pps
... λ o2 (16.B.8) sin 2 γ o cos 2 α on = cos 2 λ b1 sin 2 λ o2 ± 2 cos λ b1 cos λ b2 sin λ o1 sin λ o2 + cos 2 λ b2 sin 2 λ o1 = cos 2 λ b1 ± 2 cos λ b1 cos λ b2 sin λ o1 sin λ o2 + cos 2 λ b2 − 2 ... Pressure -8.180e+01 +2. 500e+01 +9.731e+01 +1.696e+ 02 +2. 41 9e+ 02 +3. 142 e+ 02 +3.865e+ 02 +4. 588e+ 02 +5.311e+ 02 +6.035e+ 02 +6.758e+ 02 +7 .48 1e+ 02 +8 .20...
Ngày tải lên: 08/08/2014, 12:21
Gear Geometry and Applied Theory Episode 2 Part 8 pps
... equations (see Section 3 .4) cot γ 1 = m 12 + cos γ sin γ , cot γ 2 = m 21 + cos γ sin γ = 1 + m 12 cos γ m 12 sin γ (18 .2. 2) P1: JXR CB6 72- 18 CB6 72/ Litvin CB6 72/ Litvin-v2.cls February 27 , 20 04 1:5 18.1 Introduction ... ”“s” and “1, ” and “1” and 2 are considered. Angle γ s that is formed between the shaper axis and IA s2 is P1: JXR CB6 72- 18 CB6 72/ Litvin CB...
Ngày tải lên: 08/08/2014, 12:21
Gear Geometry and Applied Theory Episode 2 Part 9 pps
... face -gear 47 1.0 mm Outer radius of the face -gear 559.0 mm P1: JXR CB6 72- 18 CB6 72/ Litvin CB6 72/ Litvin-v2.cls February 27 , 20 04 1:5 544 Face -Gear Drives (Ave. Crit.: 75%) S, Mises +2. 48 4e+00 +4. 364e+ 04 +8. 727 e+ 04 +1.309e+05 +1. 745 e+05 +2. 182e+05 +2. 618e+05 +3.055e+05 +3 .49 1e+05 +3. 927 e+05 +4. 364e+05 +4. 800e+05 +7.515e+05 1 2 3 Bending ... Analysis...
Ngày tải lên: 08/08/2014, 12:21
Gear Geometry and Applied Theory Episode 2 Part 10 doc
... left-hand worm and worm -gear, we have R o = p ax N 2 cos λ (o) 1 2 sin γ + λ (o) 1 . (19.3.10) P1: JsY CB6 72- 19 CB6 72/ Litvin CB6 72/ Litvin-v2.cls February 27 , 20 04 1 :28 19.5 Generation and Geometry ... d sin α sin λ p (cos 2 α + sin 2 α sin 2 λ p ) 0.5 (19.5 .20 ) where d = r p − s p 2 cot α. P1: JsY CB6 72- 19 CB6 72/ Litvin CB6 72/ Litvin-v2.cls February 2...
Ngày tải lên: 08/08/2014, 12:21