Aircraft structures for engineering students - part 6 potx

Aircraft structures for engineering students - part 6 potx

Aircraft structures for engineering students - part 6 potx

... +66 0 64 0 278 x lo6 35 .6 2 +60 0 60 0 2 16 x IO6 32.3 3 +420 60 0 1 06 x IO6 22 .6 4 +228 60 0 31 x lo6 12.3 5 + 25 62 0 0.4 x lo6 1.3 6 -2 04 64 0 27 x 1 06 -1 1.0 7 -3 96 640 ... 2.0 x 60 0 ( ;;l) B1 = 300 + 3.0x400(2-l)+ 6 6 2 +- which gives Also B1(= B6) = 1050mm2 i.e. 1.5 x 60 0 ( KM)) 2 +- 2.0 x 60 0 (...
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Aerodynamics for engineering students - part 6 potx

Aerodynamics for engineering students - part 6 potx

... (Eqn (6. 17)): which gives the differential equation Equation (6. 66) may now be integrated. Thus or From Eqn (6. 65) (6. 65) (6. 66) (6. 67) Compressible flow 339 i.e. when Mk(y - l)u'/U, ... 2+ ( 7- 1)M; For air 6. 4.5 Temperature rise across the normal shock Directly from the equation of state and Eqns (6. 43) and (6. 45): For air (6. 45) (6...
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Aircraft structures for engineering students - part 1 pps

Aircraft structures for engineering students - part 1 pps

... load for a flat plate 51 51 59 61 63 65 65 68 68 70 71 73 76 77 85 100 103 103 107 109 110 110 122 122 125 129 137 141 142 149 149 152 152 1 56 160 162 165 169 ... = - [a, + a,, + az - 2v(ax + ay + 41 or In the case of a uniform hydrostatic pressure, a, = a,, = az = -p and 3(1 - 2~) E P e =- (1.49) The...
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Aircraft structures for engineering students - part 2 pot

Aircraft structures for engineering students - part 2 pot

... satisfied. PX ax = - [5y(x2 - z2) - ioy3 + 6dZy] 20d3 ay = E( - 3yd2 - 2d3) 4d3 -P 40d3 Txy = - [5(3x2 - Z2)(y2 - d2) - 5y4 + 6y2d2 - $1 The boundary stress ... M=-Pz Rz, hence -= 4 2 dR 2z between F and B P d3 dM d3 4 2 dR 2 M = - (L - z) - -Rz, hence - = - -2 and between...
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Aircraft structures for engineering students - part 3 docx

Aircraft structures for engineering students - part 3 docx

... q(x,y)sin-sin- dxdy . mrx m'rx nry n'ry sin - sin - dx dy = m=l 2 n=l T/:jIamsin-sin- a a b b - ab 4 - since a 2 _- - when m=m' and . nry . n'ry sin-sin- ... and My are known. If either M, or My is zero then d2W - a2W d2W - d2W ax2 - 8Y2 ay2 - dX2 - -v- or - -v- and the plate has...
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Aircraft structures for engineering students - part 4 docx

Aircraft structures for engineering students - part 4 docx

... u EI, 7 = - PV EI,,,, = -Pu d48 P d28 d24 ( A)G= El? GJ-Io- (6. 87) (6. 88) (6. 89) Equations (6. 87), (6. 88) and (6. 89), unlike Eqs (6. 74), (6. 75) and (6. 83), are uncoupled ... oldest member 6. 1 2 Flexural-torsional buckling of thin-walled columns 185 0 P - ~EIJL~ -Pxs P - ~EI,,JL~ 0 PYS PYS - Pxs IOPIA - .rr2ET/L2...
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Aircraft structures for engineering students - part 5 pps

Aircraft structures for engineering students - part 5 pps

... g)2 ( Su,e 7 SA :-) ’ ( -3 .23 x 5. 26 x 105u;5. 6 Sqrn 10001~0 Substituting for and Skqm we have or D, = 16. 99 x lo2 ( - :)2 Jm (u;: 2u;5. 26 + u ;6. 26) due 2/10 ur ... for vertical equilibrium L+P- w=o (8.7) for horizontal equilibrium T-D=O and taking moments about the aircraft s centre of gravity in the plane of symmetry La -...
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Aircraft structures for engineering students - part 7 ppt

Aircraft structures for engineering students - part 7 ppt

... 60 0 N/mm2 then, from Eq. (10.27) x 1.22 = 3 .66 mm 3 x 2 760 0 27 60 0 t;, = Hence 1270 3 .66 67 , = - - - 347 Also 61 2 = 65 6 = 840, 62 3 = 783, 63 4 = 1083, 63 , = 57, 68 4 ... and -1 90 x lo6 5.22 x lo8 Yr = -0 . 364 ~~ 0z:r = Hence Pi = P3 = -P4 = -P6 = -0 . 364 X 295 X 900 = -9 66 42N and P2 -Ps =...
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Aircraft structures for engineering students - part 8 doc

Aircraft structures for engineering students - part 8 doc

... substitute in Eq. (1 1.28) for q from Eq. (1 1.25) and for PB from Eq. (1 1. 26) . Hence 1 #PA - Gt ( PA S,Z PA) - - - - - - - - - - - 2 dz2 dE 2B 2Bh A Rearranging, ... B3 = B6 = B7 = 60 0mm2 AFZS. ~1 = -1 90.7N/m2, 02 = -1 81.7N/mm2, 63 = -1 72.8N/mm2, U4 = -1 63 .8 N/lIUll2, 65 =...
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Aircraft structures for engineering students - part 9 pps

Aircraft structures for engineering students - part 9 pps

... matrix for a uniform beam 51 1 It is possible to write Eq. (12.44) in an alternative form such that the elements of [KJ are pure numbers. Thus 12 -6 -1 2 -6 -6 4 62 -1 2 6 12 6 -6 2 64 This form ... vj o 121~~ -6 1~~ o -1 21~~ -6 1~~ o -1 21~~ 61 ~~ o 121~~ 61 ~~ 00 000 0 0 -6 /L2 4/L 0 6/ L2 2/L 00 000 0 0 -6 /L2 2/L 0 6/ L...
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