... toUk−21−x2√x√xUk−11−x2√xl0−1(33) and the generating functions for steps 3 and 4 are both equal to(−1)k−2√xUk−11−x2√x. (34)Taking the product of x, the quantities in (32) and (33), and the square of the quantityin ... #R7 22 and 2143 and has π(i +1)=n,exactlyoneof1, 2, ,n− i appears to the left of n inπ.(Iftwoormoreof1, 2, ,n−i appeared to the left of n then two of these elements,together with n and some ... pattern of either type in n, π the n must play the role of the 4. But this is impossible, since the n is the left-most elementof n, π, but 4 is not the left-most element of 1243 or 2143. Therefore...