Báo cáo toán hoc:"On biembeddings of Latin squares" pdf

... each of which has a parallel class in one colour. The proof depends on the construction of a biembedding of a pair of Latin squares of side p, one of which has p 2 (p − 2)/8 subsquares of side ... biembeddings of Latin squares where paratopic copies are a llowed, and statements about particular realizations of Latin squares. For Latin squares A and A ′ with common...

Ngày tải lên: 08/08/2014, 01:20

... of a cycle or a union of cycles of the permutation π : x → 2x of Z n (the map is a permutation since gcd(2,n) = 1). Only one cycle of D (and of π) has length 1, namely {0}.Foreachm-cycle C of ... family of all k-cycles by C k . For example, a 2-cycle consists of a pair of vertices and a pair of edges such that the pair of vertices is a subset of each edge. The above...

Ngày tải lên: 07/08/2014, 07:21

Ngày tải lên: 05/08/2014, 15:20

Ngày tải lên: 05/08/2014, 15:20

Ngày tải lên: 05/08/2014, 15:20

... L. Sucheston, Convergence of classes of amart indexed by directed sets, Canad. J. Math. 32 (1980) 86–125. 13. U. Mosco, Convergence of convex sets and of solutions of variational inequalities, Adv. ... one-parameter discrete case, the notion of 1-mils coincides with the original notion of mils introduced by Talagrand [16]. The following lemma will be needed in the proof of the...

Ngày tải lên: 06/08/2014, 05:20

... contradiction. This completes the proof of the corollary.  Vietnam Journal of Mathematics 34:4 (2006) 423–440 On Systems of Quasivariational Inclusion Problems of Type I and Related Problems * Lai-Jiu ... Lin 1 andNguyenXuanTan 2 1 Department of Math., National Changhua University of Education, Changhua, 50058, Taiwan 2 Institute of Mathematics, 18 Hoang Quoc Viet Road, 10307 H...

Ngày tải lên: 06/08/2014, 05:20

... E)and for the Mackey topology τ(E ∗ , E)ofE, i.e. the topology of uniform convergence on all weakly compact convex cirled subsets of E. Thus by the separability of E,thespaceE ∗ is also separable ... a little more information of τ(E ∗ , E). Lemma 2.1. Let S be a total subset of E ∗ . Then there exists a sequence (x ∗ n ) of S such that the countable collection D of all linear co...

Ngày tải lên: 06/08/2014, 05:20

... yields the result that the absence of rainbow 5-cycles implies the absence of rainbow 9-cycles. Proof. The proof of this lemma has the same basic structure as that of Lemma 8, but the cycles we consider ... color of this chord. On the one hand, it must agree with one of the other edges of the n-cycle to avoid a rainbow n-cycle; on the other hand, it must similarly agree with one...

Ngày tải lên: 07/08/2014, 13:21

... this section we give a short polynomial proof of the convexity lemma, which is the crucial step in S´a-Thompson theorem [7, 10]. The original proofs of S´a and Thompson were long and complicated, ... if f ≺ ′ (d, a), then in the same way as in the proof of the equivalence of (15) and ( 18), we have d i = f i+l , i  h l − l + 1. (20) The aim of this section is to show that there is...

Ngày tải lên: 08/08/2014, 12:22