Solve prpblem sat 2 ppsx

Solve prpblem sat 2 ppsx

Solve prpblem sat 2 ppsx

... the graph of the equation y = (x + 1) 2 + 2? a. (–1, 2) b. (1, 2) c. (–1 ,2) d. (1 ,2) e. (2, –1) 4 3 2 1 –1 2 –3 –4 –4 –3 2 –1 1 2 3 4 y x –PRACTICE TEST 2 20 2 9. a ᎏ b c ᎏ is equivalent to a. ... Rentals Drama 42% Comedy 24 % Action 22 % Horror 12% –PRACTICE TEST 2 20 4 –LEARNINGEXPRESS ANSWER SHEET– 199 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17...

Ngày tải lên: 07/08/2014, 22:20

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Solve prpblem sat 1 pps

Solve prpblem sat 1 pps

... solve for a: – ᎏ 10 – 4 2a 2 ᎏ + 3a = 11 –10 + 2a 2 + 12a = 44 2a 2 + 12a – 54 = 0 (2a – 6)(a + 9) = 0 2a – 6 = 0, a = 3 a + 9 = 0, a = –9 The positive value of a is 3. 17. 4 .20 If one pound of almonds ... – 3) 2 – 2, 2 = 0 2 – 2, 2 = 2. 5. c. ᎏ 1 5 6 ᎏ = 0.3 125 and ᎏ 2 9 0 ᎏ = 0.45; ᎏ 3 8 ᎏ = 0.375, which is between 0.34 and 0.40, and between 0.3 125 and 0.45. 6. d. 2...

Ngày tải lên: 07/08/2014, 22:20

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Solve prpblem sat 3 pdf

Solve prpblem sat 3 pdf

... Rentals Drama 42% Comedy 24 % Action 22 % Horror 12% –PRACTICE TEST 2 20 4  Section 2 1. Which of the following expressions is undefined when x = 2? a. y = ᎏ x x + 2 2 ᎏ b. y = ᎏ x 2 +4 x x +4 ᎏ c. ... ᎏ x x + 2 2 ᎏ b. y = ᎏ x 2 +4 x x +4 ᎏ c. y = ᎏ x 2 2 – x 4 + x 4 +4 ᎏ d. y = ᎏ x 2 – + x 2 3 + x + 2 2 ᎏ e. y = ᎏ x x 2 2 + + 2 6 x x + + 2 8 ᎏ 2. If g...

Ngày tải lên: 07/08/2014, 22:20

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Solve prpblem sat 4 ppt

Solve prpblem sat 4 ppt

... pattern below? ᎏ 1, 1 0 0 24 ᎏ , ᎏ 5 9 12 ᎏ , ᎏ 2 8 56 ᎏ , ᎏ 1 7 28 ᎏ , a. ᎏ 1 2 ᎏ b. ᎏ 2 9 ᎏ c. ᎏ 9 2 ᎏ d. ᎏ 9 4 ᎏ e. 1 A J ML Q N DC B O P K Z 70˚ –PRACTICE TEST 2 21 2 17. Point A of rectangle ... the points (2, 3) and ( 2, 5)? a. y = x + 1 b. y = – ᎏ 1 2 ᎏ x + 4 c. y = – ᎏ 1 2 ᎏ x d. y = – ᎏ 3 2 ᎏ x e. y = – ᎏ 3 2 ᎏ x + 2 5. An empty crate weighs 8.16 kg and an...

Ngày tải lên: 07/08/2014, 22:20

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Solve prpblem sat 5 pptx

Solve prpblem sat 5 pptx

... dec- imal. (͙ 32 ෆ ) 3 = (͙ 32 ෆ )(͙ 32 ෆ )(͙ 32 ෆ ) = 32 32 ෆ = 32 16 ෆ 2 ෆ = ( 32) (4) 2 ෆ = 128 2 ෆ . 2 ෆ can- not be expressed as a repeating or terminating decimal, therefore, 128 2 ෆ is an irrational number. 19. ... ͙(x 2 – x ෆ 1 ) 2 + (y ෆ 2 – y 1 ) 2 ෆ Distance = ͙(11 – ( ෆ –1)) 2 + ෆ ((–7) ෆ – 2) 2 ෆ Distance = ͙( 12) 2 + ෆ (–9) 2 ෆ Distance = ͙144 + 8 ෆ 1...

Ngày tải lên: 07/08/2014, 22:20

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Solve prpblem sat 6 pps

Solve prpblem sat 6 pps

... length of AB: 2( 10) = 20 . The length of AC is 20 and the length of EC is 4͙3 ෆ . Therefore, the length of AE is 20 – 4͙3 ෆ . –PRACTICE TEST 2 22 0 –LEARNINGEXPRESS ANSWER SHEET– 22 3 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. 18. 19. 20 . a ... ᎏ 2 2 h g 2 ᎏ = ᎏ h g 2 ᎏ . 14. c. If four copy machines make 24 0 copies in three minutes, then five copy machi...

Ngày tải lên: 07/08/2014, 22:20

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Solve prpblem sat 7 docx

Solve prpblem sat 7 docx

... 29 4. If b 3 = –64, then b 2 – 3b – 4 = a. –6. b. –4. c. 0. d. 24 . e. 28 . –PRACTICE TEST 3– 22 5 22 4 –LEARNINGEXPRESS ANSWER SHEET– 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. a b c d ... 18 e. 26 3. Which of the following is the equation of a parabola whose vertex is at (5,–4)? a. y = (x – 5) 2 – 4 b. y = (x + 5) 2 – 4 c. y = (x – 5) 2 + 4 d. y = (x + 5) 2...

Ngày tải lên: 07/08/2014, 22:20

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Solve prpblem sat 8 pptx

Solve prpblem sat 8 pptx

... ᎏ x 3 + x 2 x – 2 – 16 20 x ᎏ can be reduced to a. ᎏ x + 4 5 ᎏ . b. ᎏ x + x 4 ᎏ . c. ᎏ x x + + 4 5 ᎏ . d. ᎏ x x 2 + + 5 4 x ᎏ . e. – ᎏ x3– 16 20 x ᎏ . 4 3 2 1 –1 2 –3 –4 –4 –3 2 –1 1 2 3 4 –PRACTICE ... Attendees >55 4% <18 10% 33–55 21 % 18 24 41% 25 –34 24 % A 6√⎯3 B ED FC –PRACTICE TEST 3– 23 2 16. If the lengths of the edges of a cube are decreased by 20 %, the...

Ngày tải lên: 07/08/2014, 22:20

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Solve prpblem sat 9 pot

Solve prpblem sat 9 pot

... formed in each town. There are (7)(4)(4) (2) = 22 4 bands that can be formed in Glen Oak. There are (5)(8) (2) (3) = 24 0 bands that can be formed in Belmont; 24 0 – 22 4 = 16 more bands that can be formed ... with endpoints at (6,0) and (6,–6) is ( ᎏ 6+ 2 6 ᎏ , ᎏ 0+ 2 –6 ᎏ ) = ( ᎏ 1 2 2 ᎏ ,– ᎏ 6 2 ᎏ ) = (6,–3). 7. a. The number of yellow marbles, 24 , is ᎏ 2 8 4 ᎏ = 3 times l...

Ngày tải lên: 07/08/2014, 22:20

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Solve prpblem sat 10 ppt

Solve prpblem sat 10 ppt

... + 12 cm = 60 cm. 9. 4 Substitute 2 for x and 5 for y :(3 xy + x ) ᎏ x y ᎏ = ((3) (2) (5) + 2) ᎏ 2 5 ᎏ = (30 + 2) ᎏ 2 5 ᎏ = 32 ᎏ 2 5 ᎏ = (͙ 5 32 ෆ ) 2 = 2 2 = 4. Or, 3 (2) (5) = 30, 30 + 2 = 32, ... equal to 2 r 2 , or 2 (9) 2 = 2( 81)π = 1 62 square units. 8. d. Cross multiply: a 20 ෆ = a 2 20 ෆ = 2 180 ෆ a 2 ͙4 ෆ ͙5 ෆ = 2 36 ෆ ͙5 ෆ 2a 2 ͙5 ෆ = 12 5...

Ngày tải lên: 07/08/2014, 22:20

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