Number operation review 7 doc

Number operation review 7 doc

Number operation review 7 doc

... Question Which of the following are the factors of 56a 5 ϩ 21a? a. 7a(8a 4 ϩ 3a) b. 7a(8a 4 ϩ 3) c. 3a(18a 4 ϩ 7) d. 21a(56a 4 ϩ 1) e. 7a(8a 5 ϩ 3a) Answer b. To find the factors, determine a common ... can be divided by 7 and both variables can be divided by a. Therefore, a common factor is 7a. Now, to find the second factor, divide the polynomial by the first factor: ᎏ 56a 5 7 ϩ a 21a ᎏ...

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Number operation review 8 docx

Number operation review 8 docx

... ϭ x 2 Ϫ 3. x y 123456 1 2 3 4 5 –1 –2 –6 –5 –4 –3 –1–2–3–4–5–6 x y 12345 67 1 2 3 4 5 –1 –2 –3 –1–2–3–4–5–6 7 –ALGEBRA REVIEW 84 Answer b. To simplify the expression, first determine the LCD of ... x 2 except that the base is shifted down (on the y-axis) by 1: x y 12345 67 1 2 3 4 5 –1 –2 –3 –1–2–3–4–5–6 7 –ALGEBRA REVIEW 83 Practice Question If x 2 Ϫ 8x ϭ 20, which of the following co...

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Number operation review 9 docx

Number operation review 9 docx

... the (x Ϫ 2) terms from the top and bottom to yield: x ϩ 7 ϭ 30 Now solve for x: x ϩ 7 ϭ 30 x ϩ 7 Ϫ 7 ϭ 30 Ϫ 7 x ϭ 23 Practice Question If ϭ 17, what is the value of x? a. Ϫ16 b. Ϫ13 c. Ϫ8 d. 2 e. ... 3y ϭ 7 Ϫ (x Ϫ 6y ϭϪ5) (x Ϫ x) ϩ (Ϫ 3y ϩ 6y) ϭ 7 Ϫ (Ϫ5) 3y ϭ 12 y ϭ 4 is the answer. Now substitute 4 for y in one of the original equations and solve for x. x Ϫ 7 ϭ 3y x Ϫ 7 ϭ...

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Number operation review 1 pps

Number operation review 1 pps

... various operations with fractions. –NUMBERS AND OPERATIONS REVIEW 49 Odd and Even Numbers An even number is a number that can be divided by the number 2 to result in a whole number. Even numbers have ... in an odd number? a. even number ϩ even number b. odd number ϫ odd number c. odd number ϩ 1 d. odd number ϩ odd number e. ᎏ even n 2 umber ᎏ Answer b. a, c, and d defi...

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Number operation review 2 pdf

Number operation review 2 pdf

... because n > 2. –NUMBERS AND OPERATIONS REVIEW 50 Factors Factors of a number are whole numbers that, when divided into the original number, result in a quotient that is a whole number. Example The ... Ϫ2 67 on the number line.) Practice Question Which of the following statements is true? a. Ϫ25 > Ϫ24 b. Ϫ48 > 16 c. 14 > 17 d. Ϫ22 > 19 e. Ϫ 37 > Ϫ62 –NUMBERS AND O...

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Number operation review 3 pot

Number operation review 3 pot

... values of the numbers: |Ϫ12| Ϫ |7| ϭ 12 Ϫ 7 ϭ 5 Then apply the sign of the larger number: Ϫ12. The answer is Ϫ5. –NUMBERS AND OPERATIONS REVIEW 54  Sets Sets are collections of certain numbers. ... 0.04 > 0.004. This answer choice is FALSE. Answer choice b:0. 170 > 0.0 17 because 170 > 17. Therefore, 0. 17 > 0.0 17. This answer choice is FALSE. Answer choice c:0.83 > 0...

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Number operation review 4 potx

Number operation review 4 potx

... three numbers in the set. If X > 17, the median is 17 because the numbers would be ordered: X, 17, 17. If X < 17, the median is still 17 because the numbers would be ordered: 17, 17, X. ... is 4. sum of numbers in set ᎏᎏᎏ quantity of numbers in set –NUMBERS AND OPERATIONS REVIEW 60 The mode of a set of numbers is the number that occurs most frequently. Example For the number se...

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Number operation review 5 ppsx

Number operation review 5 ppsx

... 5 12 3   10 5 12 3   24 6 35 2   −21 2 −1   11 11 4 4   7 8 8 7   43 71  +  62 52  = –NUMBERS AND OPERATIONS REVIEW 67  Equations To solve an algebraic equation with one variable, ... GPA –NUMBERS AND OPERATIONS REVIEW 65 Practice Question Which of the following shows the correct solution to the problem above? a. b. c. d. e. Answer e.  43 71  +  62 52  =  4...

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Number operation review 6 pdf

Number operation review 6 pdf

... solution for 7x Ϫ 11 ϭ 29 Ϫ 3x is x ϭ 4. To check that the solution is correct, substitute 4 for x in the equation: 7x Ϫ 11 ϭ 29 Ϫ 3x 7( 4) Ϫ 11 ϭ 29 Ϫ 3(4) 28 Ϫ 11 ϭ 29 Ϫ 12 17 ϭ 17 This equation ... correct answer. 6 69 Example 7x Ϫ 11 ϭ 29 Ϫ 3x Move the variables to one side. 7x Ϫ 11 ϩ 3x ϭ 29 Ϫ 3x ϩ 3x Perform the same operation on both sides. 10x Ϫ 11 ϭ 29 Now move the numbers to t...

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Number operation review 10 pot

Number operation review 10 pot

... 3y ϭ 7 Ϫ (x Ϫ 6y ϭϪ5) (x Ϫ x) ϩ (Ϫ 3y ϩ 6y) ϭ 7 Ϫ (Ϫ5) 3y ϭ 12 y ϭ 4 is the answer. Now substitute 4 for y in one of the original equations and solve for x. x Ϫ 7 ϭ 3y x Ϫ 7 ϭ 3(4) x Ϫ 7 ϭ 12 x ... for x. x Ϫ 7 ϭ 3y x Ϫ 7 ϭ 3(4) x Ϫ 7 ϭ 12 x Ϫ 7 ϩ 7 ϭ 12 ϩ 7 x ϭ 19 Therefore, the solution to the system of equations is y ϭ 4 and x ϭ 19. –ALGEBRA REVIEW 89 f(x) ϭ 8x Ϫ 2...

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