... belongs to M(N)m, we can state thatin P there is exactly one occurence of each one of N +1, ,N + m, and that thecorresponding boxes form a ribbon r numbered from bottom to top and from left to ... process to their mirror images areequal (cf. [7, 15]).Awordw(T ) can be associated with a Young tableau T over an alphabet A, by readingthe columns of T from top to bottom and from left to right. ... originaltableau (i.e. 1–3), etc. Thus we obtain the tableau Q from Figure 3-c.The only thing left to do now is to apply Knuth’s bijection to the pair (P, Q)toobtainthe matrix in Figure 3-d.Note 5.1 We denote...