Báo cáo toán học: "An inverse matrix formula in the right-quantum algebra" ppt

... prove the right-quantum Jacobi ratio theorem, and we use the matrix inverse formula to find a generalization of the (right-quantum) MacMahon master theorem. 1 Introduction Combinatorial linear ... p-sequence in the order they appear, then all the steps starting at height 2 in the p-sequence in the order they appear, etc. Clearly, this map preserves the type of th...

Ngày tải lên: 07/08/2014, 15:23

... point in t(P ⊕ Q) can be assigned uniquely to a lattice point in tP by projection onto the R d P coordinate. Further, as P is reflexive, all of the lattice points in R d P are contained in the ... journal of combinatorics 13 (2006), #N15 5 interesting that the Ehrhart polynomial and the Ehrhart series are “dual” to each other in this sense. It would also be interesting to fi...

Ngày tải lên: 07/08/2014, 13:21

... of the on-line version, but will be important when [4] becomes available.) The %O, or “offset”, line contains two numbers. The first gives the subscript of the initial term in the sequence (in the ... the sequence in the lexicographic order in the table is determined by the terms of the sequence beginning at this point. Rule 4. The sequence must be well-defined a...

Ngày tải lên: 07/08/2014, 06:20

... (standard) independence number of the k-th power of the graph, and the study of the limit case in which such a bound is attained. Let us now fix the terminology and notation used throughout the paper. ... (that is, the sets of antipodal vertices) have all cardinality r, a number depending on the order and the eigenvalues of the graph. This result is obtained via an spectr...

Ngày tải lên: 07/08/2014, 06:22

... hyperplane in the projective space PG(6, 3). Let E 1 be the following point-line geometry: (i) the points of E 1 are the points of PG(6, 3) \ PG(5, 3); (ii) the lines of E 1 are the lines of PG(6, ... and z distinct from y. Then f (v) = f(y). The line uv is a line through u ∈ F x containing a point with value f(u) − 1, namely the point v. By the induction hypothesis, uv ⊆...

Ngày tải lên: 07/08/2014, 21:21

... 2-methoxyestradiol, decreasing 3, 4-estradiol quinone or indirectly via the inactivation of E 2 . The importance of the CYP1A1/CYP1B1 ratio in- vivo is evident in the increased presence of 4-OH-E 2 in breast ... iodine/iodide could enhance the efficacy of Tamoxifen therapy: 1) having an additive effect on estrogen inhibition and 2) inhibiting the expression of CCND1 t...

Ngày tải lên: 08/08/2014, 17:20

... since they hold for L 3 . We must show that the third invariant holds initially, when j = 0. Indeed, in L 3 ,all the edges adjacent to a vertex of S are either non-covered, or covered once in ... Concludingremarksandanopenproblem WhenH=K h ,theconstantn 0 (H)inTheorem1.1isshownintheprooftobenolargerthan max{h 8 ,h 1 +h(h−1)},whereh 1 =h 1 (h)isthecorrespondingconstantinWilson’sTheorem...

Ngày tải lên: 07/08/2014, 06:20

... continuity that the chromatic polynomial has a root in the interval (1, 2). We can perform a similar analysis on the graphs obtained by adding the single edge v 1 v 4 to X(s, t) with the following ... maybe it is the toughness of hamiltonian graphs (rather than the actual cycle itself) that is important, and along these lines Dong & Koh have made the following interestin...

Ngày tải lên: 07/08/2014, 13:21

... isomorphism, the roots decorating the vertices will have changed. Furthermore, the construction of ˜ D respects the fact that the edges in the Dynkin diagram represent the inner products of the the electronic ... 4 2 These are the simple roots of E 8 , which span the E 8 lattice. They correspond to the vertices v 1 , . . . , v 8 of Dyn(E 8 ), in the order shown on...

Ngày tải lên: 07/08/2014, 21:20

... and r ≥ 2 then we can find easily a rainbow 2-matching, but we may not find a ra inbow 3-matching. Generally, if n ≥ 2k + 1 then the following colorings do not allow a rainbow k-matching to exist. (See ... monochromatic. In the coloring (b), a complete subgraph K n−(k−2) of G is monochromatic and the other edges are rainbow. In each coloring, it is clear that there is no rainbow k-mat...

Ngày tải lên: 07/08/2014, 21:21