Báo cáo toán học: "he spectral radius of subgraphs of regular graphs" ppt
... [2] and its proof is omitted. Proofs Proof of Theorem 2 Write dist F (s, t) for the length of a shortest path joining two vertices s and t in a graph F. Write d for the degree of G, let H = G ... 184, Springer- Verlag, New York (1998), xiv+394 pp. [2] S. M. Cioab˘a, The spectral radius and the maximum degree of irregular graphs, Elec- tronic J. Combin., 14 (2007), R38. [3] V. Niki...
Ngày tải lên: 07/08/2014, 13:21
... distance -regular graphs. The usefulness of the spectral excess theorem is for example demonstrated in the re- cent discovery of a new family of distance -regular graphs with the same parameters of particular ... number of vertices at extremal distance proves the distance-regularity. The goal of this paper is to give an elementary and global proof of the spectral excess th...
Ngày tải lên: 07/08/2014, 21:20
... order Reed-Muller code, consisting of the sup- ports of all functions V → GF(2) of degree at most k. A Kerdock set K induces a Kerdock code consisting of the cosets of the RM 1 represented by the ... bent. the electronic journal of combinatorics 5 (1998), #R34 5 Thus we call a set of functions a bent Kerdock set if the sum of every two of them is bent. As before without loss...
Ngày tải lên: 07/08/2014, 06:22
Báo cáo toán học: "The spectral radius and the maximum degree of irregular graphs" doc
... improve some recent results of Nikiforov [16] regarding the spectral radius of a subgraph of a regular graph. We also investigate the spectral radius of a graph obtained from a regular graph by adding an ... the spectral radius of a general (not necessarily regular) graph G and that of a subgraph of G, see [16]. 2 The spectral radius and the maximum degree...
Ngày tải lên: 07/08/2014, 15:22
Báo cáo toán học: "he spectral gap of random graphs with given expected degrees" pot
... Proofs of Auxiliary Lemmas 7.1 Proof of Lemma 2.2 The proof of Lemma 2.2 relies on the following general tail bound, which is a consequence of Azuma’s inequality (cf. [17, p. 38] for a proof). Lemma ... 3. The proof of Proposition 1.1 shows that the basic reason why the spectral gap of a sparse random graph G(n, d) is small actually is the existence of vertices of degree ≪ ¯...
Ngày tải lên: 08/08/2014, 01:20
Báo cáo toán học: "The spectral category and the Connes invariant $Gamma$ " ppt
Ngày tải lên: 05/08/2014, 15:21
Báo cáo toán học: "A Note on Maximal Nonhamiltonian Burkard–Hammer Graphs" pptx
... ∅,B 2 (H t ) = ∅ and B 1 (H t ) = ∅. The proof of Lemma 4 is complete. ProofofTheorem9. (a) Let k = 4. Then the graph L = S(I(L) ∪ K(L),E(L)) of Lemma 2 is a maximal nonhamiltonian Burkard–Hammer ... V (G), the set of all neighbors of W is denoted by N G (W )orN (W )inshort. Fora vertex v ∈ V (G), the degree of v, denoted by deg(v), is the number |N(v)|.The minimum degree of G...
Ngày tải lên: 06/08/2014, 05:20
Báo cáo toán học: "The spectral flavour of Scott Brown''''s techniques " pot
Ngày tải lên: 05/08/2014, 10:20