Báo cáo toán học: "Cubic Partial Cubes from Simplicial Arrangements" pdf
Báo cáo toán học: "Cubic Partial Cubes from Simplicial Arrangements" pdf
... 7
3 Partial Cubes from Line Arrangements
We begin by recalling [19] the construction of a partial cube from a hyperplane arrangement
in R
d
. Our construction of cubic partial cubes from simplicial ... sporadic
examples; again, each leads to a new cubic partial cube or infinite family of cubic partial cubes.
Finally, we discuss cubic partial cubes that do not come...
Báo cáo toán học: "Gorenstein polytopes obtained from bipartite graphs" pdf
... we alternately add
and subtract ǫ to the x
e
i
’s in starting from the subtraction. Also define x in a similar way
except starting from the addition by ǫ. Then clearly both x and x still satisfy ... second ones, bridges traverse from the
third row to the first and second rows. So |C(S, S
′
)| 8.
Next we consider the case when m 4 is even and n 5 is odd. From Lemmas 2.1
and 2.2, we...
Báo cáo toán học: " Magic N -Cubes Form a Free" pptx
... run over the integers from 0 to m −1 and k,l run over the integers
from 0 to n − 1, the numbers α, β will run over the integers from from 0 to mn − 1. So we have
4
Magic N -Cubes Form a Free Monoid
Allan ... published concerning the set of all
magic N -cubes as a whole. What was new in [ A-L], apart from a new construction of a remarkable
class of magic N -cubes, was the introductio...
Báo cáo toán học: "New symmetric designs from regular Hadamard matrices" pdf
... k, λ) over a (multiplicatively writ-
ten) group G is a matrix W =[ω
ij
] of order v with entries from the set G ∪{0}such
that (i) each row and each column of W contain exactly k non-zero entries ... by the matrix σP. In Section 2 (Lemma 2.1), we
will prove the following modification of a result from [6]:
Let M be a set of matrices of order v containing the incidence matrix M of a
symmetric...
Báo cáo toán học: "Reconstructing integer sets from their representation functions" pot
... N, the length of the tth row of this diagram
(counting the rows from the bottom) is then N
t
=#{n: r
A,B
(n) ≥ t}. Wenoticethat
from a well-known result of Pollard [P75] it follows that N
1
+ ... ν
k
≤ i + j −1 ≤ l + m − ν
k
}
= lm − 2#{(i, j): i + j ≤ ν
k
}
= lm − ν
k
(ν
k
− 1)
and (4) follows from lm = ν
1
+ ···+ ν
k
+ ν
k+1
+ ···.
Problem 3 What are the general properties shared by t...
Báo cáo toán học: " Completing partial Latin squares with two filled rows and two filled columns" pdf
... , ω. Recall from Section 5 that the first step of
our construction is to transform P into a segregated partial Latin square. We begin by
segregating column 2 of P .
Let P
be the partial Latin ... symbols from the set {1, 2, . . . , n} \ {s
1
, s
2
, s
3
}.
Lemma 3.8 Let P be a partial Latin square of order n ≥ 7 with one or two filled rows
and at most four other filled cells. If each...
Báo cáo toán học: "Scheduling partial round robin tournaments subject to home away pattern sets." docx
... http://www.bwl.uni-kiel.de/bwlinstitute/Prod/mab/
horbach/papers/SRRTmanuskript .pdf, 2008.
[2] D. Briskorn, Feasibility of Home-Away-Pattern Sets: A Necessary Condition, avail-
able at http://www.bwl.uni-kiel.de/Prod/team/doktoranden/briskorn/
HapSetFeasibility2007 .pdf, ... both A. We
paint the matchable edges in the figure. Then, we consider a slightly different HAP set
from the original o...
Báo cáo khoa học: "Learning Semantic Categories from Clickthrough Logs" pdf
... Supervised
Learning of Semantic Knowledge from Query Logs. IJC-
NLP, pages 358–365.
M. Pas¸ca and B. V. Durme. 2007. What You Seek is What
You Get: Extraction of Class Attributes from Query Logs.
IJCAI-07, ... between each node. The darker a node, the
more likely it belongs to the Travel domain. Start-
ing from “singapore,” the pattern “♯ airlines”
4
is
strongly related to “singapore,”...
