Báo cáo toán học: "Cubic Partial Cubes from Simplicial Arrangements" pdf

... 7 3 Partial Cubes from Line Arrangements We begin by recalling [19] the construction of a partial cube from a hyperplane arrangement in R d . Our construction of cubic partial cubes from simplicial ... sporadic examples; again, each leads to a new cubic partial cube or infinite family of cubic partial cubes. Finally, we discuss cubic partial cubes that do not come...

Ngày tải lên: 07/08/2014, 13:21

... we alternately add and subtract ǫ to the x e i ’s in starting from the subtraction. Also define x in a similar way except starting from the addition by ǫ. Then clearly both x and x still satisfy ... second ones, bridges traverse from the third row to the first and second rows. So |C(S, S ′ )|  8. Next we consider the case when m  4 is even and n  5 is odd. From Lemmas 2.1 and 2.2, we...

Ngày tải lên: 08/08/2014, 11:20

... run over the integers from 0 to m −1 and k,l run over the integers from 0 to n − 1, the numbers α, β will run over the integers from from 0 to mn − 1. So we have 4 Magic N -Cubes Form a Free Monoid Allan ... published concerning the set of all magic N -cubes as a whole. What was new in [ A-L], apart from a new construction of a remarkable class of magic N -cubes, was the introductio...

Ngày tải lên: 07/08/2014, 06:20

... k, λ) over a (multiplicatively writ- ten) group G is a matrix W =[ω ij ] of order v with entries from the set G ∪{0}such that (i) each row and each column of W contain exactly k non-zero entries ... by the matrix σP. In Section 2 (Lemma 2.1), we will prove the following modification of a result from [6]: Let M be a set of matrices of order v containing the incidence matrix M of a symmetric...

Ngày tải lên: 07/08/2014, 06:22

... N, the length of the tth row of this diagram (counting the rows from the bottom) is then N t =#{n: r A,B (n) ≥ t}. Wenoticethat from a well-known result of Pollard [P75] it follows that N 1 + ... ν k ≤ i + j −1 ≤ l + m − ν k } = lm − 2#{(i, j): i + j ≤ ν k } = lm − ν k (ν k − 1) and (4) follows from lm = ν 1 + ···+ ν k + ν k+1 + ···. Problem 3 What are the general properties shared by t...

Ngày tải lên: 07/08/2014, 08:22

... , ω. Recall from Section 5 that the first step of our construction is to transform P into a segregated partial Latin square. We begin by segregating column 2 of P . Let P  be the partial Latin ... symbols from the set {1, 2, . . . , n} \ {s 1 , s 2 , s 3 }. Lemma 3.8 Let P be a partial Latin square of order n ≥ 7 with one or two filled rows and at most four other filled cells. If each...

Ngày tải lên: 07/08/2014, 15:23

... http://www.bwl.uni-kiel.de/bwlinstitute/Prod/mab/ horbach/papers/SRRTmanuskript .pdf, 2008. [2] D. Briskorn, Feasibility of Home-Away-Pattern Sets: A Necessary Condition, avail- able at http://www.bwl.uni-kiel.de/Prod/team/doktoranden/briskorn/ HapSetFeasibility2007 .pdf, ... both A. We paint the matchable edges in the figure. Then, we consider a slightly different HAP set from the original o...

Ngày tải lên: 07/08/2014, 21:21

... Supervised Learning of Semantic Knowledge from Query Logs. IJC- NLP, pages 358–365. M. Pas¸ca and B. V. Durme. 2007. What You Seek is What You Get: Extraction of Class Attributes from Query Logs. IJCAI-07, ... between each node. The darker a node, the more likely it belongs to the Travel domain. Start- ing from “singapore,” the pattern “♯ airlines” 4 is strongly related to “singapore,”...

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