... In-Situ, Vol. 23, No. 1, 19 99, pp. 21- 53 . 10 0 Reservoir Formation Damage Symposium on Improved Oil Recovery held in Tulsa, Oklahoma, April 21- 24, 19 96, 51 1 - 51 7 . Kozeny, J., "Uber ... Deposition, ISCOP' 95, Rio de Janeiro, Brazil, November 26-29, 19 95, pp. 10 2 -10 7. Civan, R, "A Multi-Purpose Pormation Damage Model,"...
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... 399- 412 . Civan, F. "A Multi-Purpose Formation Damage Model," SPE 311 01 paper, Proceedings of the SPE Formation Damage Symposium, Lafayette, LA, February 14 -15 , 19 96, pp. 311 -326. Civan, ... Multiphase Flow, Vol. 13 , No. 1, 19 87, pp. 87- 97. Slattery, J. C. Momentum, Energy and Mass Transfer in Continua, McGraw- Hill Book Co., N...
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Reservoir Formation Damage Episode 1 Part 10 potx
... Civan (19 95): (10 -12 9) (10 -13 0) subject to =0, 0<jc<L, f = (10 -13 1) (10 -13 2) k is a particle exchange rate coefficient. A solution of Eqs. 10 -12 9 through 13 2 along with the particle ... are presented in Figure 10 -25. Next, they have solved their model equations, Eqs. 10 -12 1, 11 1, 11 2, 11 4, 11 5, 11 6, numerically by assuming t...
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Reservoir Formation Damage Episode 2 Part 1 ppsx
... fraction is given by: (11 - 12 ) (11 -13 ) where (() is porosity and S } is the saturation of phase J. Thus, substituting Eqs. 11 - 12 and 11 -13 into Eq. 11 -11 yields the following ... core samples 24 6 Reservoir Formation Damage and MS w 1 + (M -1) S W (11 -26 ) Consequently, Eq. 11 -19 can be simplified significantly by substituting Eqs....
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Reservoir Formation Damage Episode 2 Part 2 ppsx
... Modeling 27 1 K c L f )aK f ( 12- 22) aK ( 12- 23) Alternatively, eliminating (p c -p e ] between Eqs. 12- 18 and 12- 19 and then solving for 8 yields: aK t 5 = i- ( 12- 24) aK, Notice that Eq. 12- 24 ... Eqs. 12- 2, 12- 9, 12- 46, and 12- 48 into Eq. 12- 45 results in (1999a) dt r w -8 ' where ( 12- 49) ^yp^ ( 12 ~ 50) and B is given by Eq. 12- 13. The...
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Reservoir Formation Damage Episode 2 Part 3 doc
... 8 .29 7min/cm 6 , B/C = 0.1 136 cm- 3 , R 2 = 0.87 13 ( 12- 84) C = 0.0 034 cm 4 /min, D = 0.0076cm, R 2 = 0.949 ( 12- 85) A = 0. 022 9 cnT 2 , B = 0.00 03 cm/min, R 2 = 0.98 73 ( 12- 86) The coefficients ... of Eq. 12- 76 can be used with Eqs. 12- 30 , 12- 31 , 12- 12, and 12- 13 to obtain the following expressions: (B/C), k d (A/C)(t-T c >...
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Reservoir Formation Damage Episode 2 Part 4 doc
... 1970). 326 Reservoir Formation Damage migration, and redeposition of fine mineral particles and therefore cause formation damage (Chang and Civan, 1991, 19 92, 1997). Formation damage ... Chatelier principle. Because H 2 O 46 44 42 ~ 40 Q 01 3 38 O V) < ;2 s 20 0ôF C) DISSOLVED CALCIUM, MMOLE/B Figure 13-1. Natural and induced scale damag...
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Reservoir Formation Damage Episode 2 Part 5 potx
... Al cr Br so 4 - 2 C0 3 ~ 2 HCO 3 H 4 Si0 4 ° pH TDS Tartarate Malonate Succinate Glycolate Formate Acetate Propianate Butyrate Oxalate JMU # 723 4 58 650 28 47 663 9 62 2.41 780 10.3 0 .5 106400 8 35 28 3 0 24 0 2. 2 6.83 170837 ND ND 24 .6 ND 23 .3 304 22 5. 7 ND JMU # 723 1 60430 3037 753 4 12 2.18 8 12 0.16 0.6 110000 8 92 246 0 24 0 4.3 7 .23 1 759 32 ND ND 26 .2...
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Reservoir Formation Damage Episode 2 Part 6 ppsx
... 1177-1185. 3 72 Reservoir Formation Damage f + Fe +2 + 16H + + Ue~ t=> FeS 2 + 8// 2 0 Fe^O 23 + 38/T + 30e~ & 2FeS- + 19HQ + 6H + + 2e~ d 2Fe +2 + 3// 2 0 from ... \*"J—\jj) Fe 2 O 3 +6H + +6H + + 2e~ <=>2Fe +2 + 3H 2 O Fe 2 O 3 +2HCO 3 +4H + +2e FeCO 3 +H + <=> Fe +2 + HCO 3 + 5H + + 2e~ ^ 3FeCO 3 + 4...
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Reservoir Formation Damage Episode 2 Part 7 ppt
... Dekker, Inc.). 4 02 Reservoir Formation Damage 0.3 T Reservoir Pressure. 28 0.0 aon Reservoir Temperature, 338.0 *K 25 0 29 0 300 310 Temperature, °K 320 330 Figure 14 - 27 . Wax weight ... g/g-mol Component Saturates Aromatics Resins Asphaltenes Viscosity mPaằs . 12. 8 4 .2 - - Viscosity @59C d 4 .2 . - - - 0.1 23 0 wt.% 48.5 33.5 13 .2 4.8 OilW2" Density...
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Reservoir Formation Damage Episode 2 Part 8 doc
... md knp/kpi 3 11.3 20 0 0.5,1 ,2, 3 0.35 29 .29 2. 71 136 0.5 1 2 3 0.1 15 100 0.05 /1 0 20 0.0 08 6.3 0.00 085 through 0.01 0.0 32 0 .2 10 10 0. 82 10 11.3 10 * After Ali and Islam, â19 98 SPE; reprinted ... (Reference) Reservoir temperature ôa 50 80 119 81 S Sat 40.1 65.7 70.5 15 ARA/ AT 46.1 22 .8 25 .5 37 kNALYSIJ Resins 8. 5 7.5 3.3 34 5 Asph. 5.3 4 0.15 14 Re...
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Reservoir Formation Damage Episode 2 Part 9 pot
... g/gmol 50 13 29 5.3 6,000 50 13 29 5.3 6,000 - 5 .27 29 . 29 53đ 6,000 - 5 .27 29 . 29 53đ 6,000 Core Properties L, cm D, cm k ( , darcy A 5.08 2. 3 0.107 0.131 5.08 2. 3 0.0 122 0 .24 3 26 .5 2. 56 0.011 0.35 26 .5 2. 56 0.011 0.35 Data ... SPE International Symposium on Formation Damage Control, February 26 -27 , 19 92 , Lafayette, Louisiana, pp. 21 9...
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Reservoir Formation Damage Episode 2 Part 10 pot
... ambient laboratory conditions. 470 Reservoir Formation Damage Guidelines and Program for Laboratory Formation Damage Testing Recommended Practice for Laboratory Formation Damage Tests* Introduction The ... the wellbore. 458 Reservoir Formation Damage effect for clays and fines in the reservoir, an effect that would be removed by extraction." Fu...
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Reservoir Formation Damage Episode 3 Part 5 pdf
... change 8 47 03 3 93 699 0 0 29 0 1 65 86 80 47 03 3 93 7 35 0 0 29 0 161 1 15 0.2 90 47 03 3 93 1 056 109 90 (muscovite) 87 0 0.2 37 0 .3 0 0 -36 1 - 154 -112 +3 -17 +1 65 +86 +80 -31 0 +16.9 25. 7 0 0 -32 5 - 154 -112 +3 -17 +161 +1 15 +0.2 +90 - 239 + 13 24.9 0 0 -4 - 45 d ... Plagioclase Calcite (%) -31 90 .5 -31 91 .5 -31 92.7 -31 94.0 -31 95. 7 -31...
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Reservoir Formation Damage Episode 3 Part 7 potx
... /,(*./*,- 1 ) (19 -36 ) (19 - 37 ) Thus, they calculate the harmonic average permeability of the damaged portion of the core by: K(t\- Xf { dx K(t) -T 0 n^t (19 -38 ) Substituting Eqs. 19 -33 , 34 , and 36 ... Study," SPE Paper 38 180, Proceedings of the 19 97 SPE European Formation Damage Conference held in the Hague, The Netherlands, June 2 -3, 19 97,...
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