Central Boiler Plants Episode 2 Part 5 pot

Bearing Design in Machinery Episode 2 Part 5 potx

Bearing Design in Machinery Episode 2 Part 5 potx

... is 20 ,000 N, or 50 00 N on each pad. The total manufac- tured clearance between the two pads ðh 1 þ h 2 Þ is 0.4 mm. Each circular pad is of 100-mm diameter and recess diameter of 50 mm. R ¼ 50 ... 50 mm and R 0 ¼ 25 mm. The oil viscosity is 0:01 N-s=m 2 .In order to minimize vertical displacement, the slider plate is prestressed. The reaction force at the top is W 1 ¼ 50 00 N, an...

Ngày tải lên: 21/07/2014, 17:20

19 301 0
New SAT Math Workbook Episode 2 part 5 pot

New SAT Math Workbook Episode 2 part 5 pot

... − − 22 5 2 5 2 25 2 2 f ()()( )− = − = − = − − 1 15 1 5 1 5 1 1 f(0) = (0) (5 0 ) = (0)(1) = 0 f (2) = (2) (5 2 ) = (2) ( 25 ) = 50 The range of f(x) = x x 5 − is the set { − 2 25 , − 1 5 , 0, 50 }. ... the city’s population 20 , 15, 10, and 5 years ago, as well as its current population). Solving for a: a a a a ×= ×= ×= = − 2 256 000 2 256 000 16 25...

Ngày tải lên: 22/07/2014, 11:20

20 440 0
Gear Noise and Vibration Episode 2 Part 5 potx

Gear Noise and Vibration Episode 2 Part 5 potx

... (brl*psil - brl*tan(phi2))/(pi*cos(phio)); r2 = (br2*psi2 - br2*tan(phi2))/(pi*cos(phio)); conratio = rl + r2; disp( f angle rl r2 contact ratio') disp([ phi2 rl r2 conratio ]) phi3 ... pinion teeth n2 = 131 ; % number of wheel teeth brl = nl*0 .5* cos(phio); br2 = n2*0 .5* cos(phio); % base radii psil = (tan(phio) + 2* pi/nl) ; psi2 = (tan(phio) +...

Ngày tải lên: 05/08/2014, 09:20

20 217 0
Fundamentals Of Structural Analysis Episode 2 Part 5 pot

Fundamentals Of Structural Analysis Episode 2 Part 5 pot

... maximize F CJ . 1kN 1kN 2 kN 1m 2m 2 kN 10 kN/m 10 kN/m x 6 m 1 . 25 1 . 25 0. 6 25 0.41 F CJ 2 kN 1 . 25 1 . 25 0. 6 25 0.41 F CJ 2 kN 1kN 1kN 1m2m 7 m 9 m Influence Lines by S. T. Mau 26 2 Problem 1. (1) Construct ... CJ. (F CJ ) max = −10[0 .5( 1. 82) (0. 6 25 )+0 .5( 9)(0. 6 25 )-0 .5( 4. 82) (0. 6 25 )(4. 82/ 9)] = −33.0 kN 10 kN/m 6 m 1 . 25 1 . 25 0. 6 25 0.41 F CJ 6...

Ngày tải lên: 05/08/2014, 11:20

20 265 0
Machinery''''s Handbook 27th Episode 2 Part 5 potx

Machinery''''s Handbook 27th Episode 2 Part 5 potx

... = 150 5 Constant C = 1010 V T SMRR V T SMRR V T SMRR V T SMRR 100 6 85 1 15 5 95 1 95 455 22 5 3 05 23 0 10 1 25 0 21 0 1080 355 8 25 4 15 555 4 15 1 22 70 3 85 1970 650 150 5 750 1010 760 Fig. 2a. T–V Fig. 2b. ... C = 53 85 Constant C = 38 85 V T SMRR V T SMRR V T SMRR V T SMRR 100 26 95 460 21 05 6 95 1 6 25 8 15 11 75 880 10 49 05 8 35 3830 126 5 29 60 1480 21...

Ngày tải lên: 05/08/2014, 12:20

63 439 0
CRC.Press A Guide to MATLAB Object Oriented Programming May.2007 Episode 2 Part 5 potx

CRC.Press A Guide to MATLAB Object Oriented Programming May.2007 Episode 2 Part 5 potx

... in /oop_guide/chapter_18. 58 end 59 % Replace with something like UNCLASSIFIED C911X_C018.fm Page 26 1 Friday, March 2, 20 07 9:06 AM 26 0 A Guide to MATLAB Object-Oriented Programming 22 % 23 24 switch which 25 case ... software 25 % A Class Wizard v.3 assembled file, generated: 20 -Dec -20 05 13 :23 :23 26 C911X_C018.fm Page 25 6 Friday, March 2, 20 07 9:06 AM 27 2 A...

Ngày tải lên: 05/08/2014, 21:21

20 337 0
Từ khóa:
w