Báo cáo toán học: "Convergence in distribution for subset counts between random sets" pptx
Báo cáo toán học: "Convergence in distribution for subset counts between random sets" pptx
... not converge. For a comprehensive account of Stein’s method see [1]. In applying Stein’s method to subset counts in P(m, n, p) we were able to use the “coupling” version of Stein’s methodand ... n, p)consideredbyR´enyi.2 A coupling for subset counts between random sets In this section we prove Theorem 1.It is convenient initially to work with the random variable W . Note that (1) impliesP(W ... of how many random subsets need to be chosen from aset of n elements, each element appearing in each subset with probability p =1/2, in order that at least one subset is contained in another....
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Báo cáo toán học: " Reconfigurable parasitic antennas for compact mobile terminals in multiuser wireless systems" pot
... using ESPAR atthe receiving terminal are examined both in opportunistic beamforming and in MIMO broadcastchannel MU systems, optimizing correspondingly the SNR or the SINR of the forward link.1 ... channelincreases, the effect of the increased training overhead is evident in the system performance.3.3 Receiver beamforming in Rician channels In order to evaluate the potential gains of using ... in the analysis for optimal beamforming and SINR optimization. The results show that in the case of opportunistic beamforming scenarios in Rayleigh channels only beamforminggains are achieved,...
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Báo cáo toán học: " Modified noor iterations for nonexpansive semigroups with generalized contraction in Banach spaces" pptx
... Setting f is a contraction on C in Theorem 2.1, we have the following results immediately.is continuous, strictly increasing and η(t) is strictly increasing and onto, where η(t):=t −ψ(t),t∈ ... others. In order to prove our main results, we need the following lemmas.Definition 1.5. [24] A Banach space is said to admit a weakly sequentially continuous normalizedduality mapping J from E in ... uniquesolution in Fix(S) to the following variational inequality:(f − I)q, j(x − q)≤0 for all x ∈ Fix(S). (2.2)Proof. We first show that {xn} is well defined. For any n ≥ 1, we consider a mapping Gnon...
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Báo cáo toán học: " Fixed point theorems for contraction mappings in modular metric spaces" pptx
... notice below). For information about publishing your research in Fixed Point Theory and Applications go tohttp://www.fixedpointtheoryandapplications.com/authors/instructions/ For information about ... Princi-ple appeared in explicit form in Banach’s thesis in 1922 [1]. Since its simplicityand usefulness, it has become a very popular tool in solving existence problems in many branches of mathematical ... x)(3.18) for all λ > 0 and for all n ∈ N. Taking n → ∞ in the inequality (3.18), weobtained thatwλ(T x, x) ≤ kwλ(T x, x).(3.19)Since k ∈ [0,12), we have T x = x. Thus, x is a fixed point...
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Báo cáo toán học: " Fixed point theorems for w-cone distance contraction mappings in tvs- cone metric spaces" docx
... versions of fixed pointtheorems in K-metric spaces and scalar versions of fixed point theorems in metric spaces. He showedthat many of the fixed point theorems for mappings satisfying contractive ... n → ∞. Similarly, following lines of the proof ofLemma 1 in [3], one can prove (i), (iii) and (iv). 3 Fixed point theorems for w-cone distance contraction mappings in K-metricspacesWe note ... ≤c4+c4=c2,7Fixed point theorems for w-cone distance contractionmappings in tvs-cone metric spacesLjubomir´Ciri´c∗1, Hossein Lakzian2and Vladimir Rakoˇcevi´c31Faculty of Mechanical Engineering, Kraljice...
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Báo cáo toán học: "Improved Upper Bounds for Self-Avoiding Walks in Zd" ppt
... staying completely in those j dimension and a single other onegoing on step in positive direction in dimension j +1. In our implementation we exploit this kind of symmetry by “normaliz-ing” ... stepclosing a loop of length 4 – both transfering to state ω. (3.2) A step in thesame direction as the previous step, transfering us back to state 1 again.(3.3) A step in any other of the remaining ... removing steps from the beginning of auntil we arrive at a walk athat could be the first part of such a loop.Note that this procedure terminates since the length of a is finite at thebeginning,...
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Báo cáo toán học: "A LOWER BOUND FOR THE NUMBER OF EDGES IN A GRAPH CONTAINING NO TWO CYCLES OF THE SAME LENGTH" pptx
... Chunhui Lai, On the size of graphs with all cycle having distinct length, DiscreteMath. 122(1993) 363-364.[6] Chunhui Lai, The edges in a graph in which no two cycles have the same length, J.Zhangzhou ... edges. In thispaper, we construct a graph G having no two cycles with the same length which leads tothe following result.Theorem. Let t = 27720r + 169 (r ≥ 1), thenf(n) ≥ n +32t −1 for n ≥691116t2+5144418t ... [6]).Combining this with Boros, Caro, F¨uredi and Yuster’s upper bound, we have1.98 ≥ lim supn→∞f(n) − n√n≥ lim infn→∞f(n) − n√n≥ 1.5397.the electronic journal of combinatorics 8...
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Báo cáo toán học: "Two new criteria for comparison in the Bruhat order" pot
... hλ− hµ for some appropriatepartitions λ, µ depending on π, σ, respectively. We claim that λ is incomparable to orgreater than µ in the dominance order. Since M(π)[k],[+1,n]contains k − ... of the form (2) and again is TNN.(⇐) Suppose that π is not less than or equal to σ in the Bruhat order. By Theorem 1we may choose indices 1 ≤ k, ≤ n − 1 such that M(σ)[k],[]contains q + ... recent interest in SNN polynomials is motivated by problems in algebraic geome-try [4, Conj. 2.8, Conj. 5.1].Theorem 3 Let π and σ be permutations in Sn. Then π is less than or equal to σ in...
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Báo cáo toán học: "Towards the Distribution of the Size of a Largest Planar Matching and Largest Planar Subgraph in Random Bipartite Graphs" ppt
... between tableaux in T (m,d) satisfying condition (II)and walks of length m starting at the origin, moving only in positive directions, staying in theregion x1≥ x2≥ ···≥ xdand satisfying ... 12 give a bijection between S(r,n,d) and pairs of walks oflength m starting at the origin, terminating at the same lattice point, moving only in positivedirections, staying in the region x1≥ ... row–insertions, firstrow inserting x in a tableau T and then row–inserting x in the resulting tableau T ← x. Thisgives rise to two new boxes B and Bcontaining x and xas shown in Figure 2:• If x...
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