Báo cáo toán học: "A unified view of determinantal expansions for Jack Polynomials" pptx

... + α)k 1 (14) the electronic journal of combinatorics 8 (2001), #R3 6 A unified view of determinantal expansions for Jack Polynomials Leigh Roberts 1 School of Economics and Finance Victoria University, ... (6) Again, for the application of H to e λ , the only alteration to the right side of (6) would be a change of c λ  to d λ  . One of the main aims of this pap...

Ngày tải lên: 07/08/2014, 06:22

... They hold for subsets of any abelian group, but here we state them only for subsets of F p . Lemma 1. For any subsets X, Y, Z of F p we have |X − Z| ≤ |X − Y ||Y − Z| |Y | . Lemma 2. For any subsets ... C||AB|  min  p|A|, |A| 2 |B||C| p  . 3 Proof of Theorem 1 If G ⊂ X × Y then for a given x ∈ X we denote by G(x) the set of all elements y ∈ Y for which (x, y) ∈ G. The...

Ngày tải lên: 07/08/2014, 15:23

... = dr dτ (≥ 0) = marginal response of cold-drink consumption to a change in τ(temperature) C 1 = opportunity cost of money tied up in inventory. C 2 = rate of change of inventory cost with respect ... − τ ∗ τ  2 p(τ) Vietnam Journal of Mathematics 33:4 (2005) 437–442 A Stochastic EOQ Policy of Cold-Drink -For a Retailer Shib Sankar Sana 1 and Kripasindhu Chaudhuri 2 1 Departme nt...

Ngày tải lên: 06/08/2014, 05:20

... saves more potential exam- ples of fluent speech rules, and therefore potentially makes better use of limited data. 3 Evaluation The evaluation of this system was performed on the Switchboard corpus, ... is intended to evaluate the use of the right corner transform and syntactic information on parsing speech repair. To make a fair comparison to the CYK baseline of (Hale et al., 2006)...

Ngày tải lên: 20/02/2014, 09:20

... accu- racy. 1 Introduction Single scan algorithms ofparsing are important for interactive applications of NLP. For instance, such algorithms would be more suitable for robots ac- cepting speech inputs or ... comparable performance with even a sin- gle scan of a sentence for dependency parsing in addition to bunsetsu chunking. According to the results in Table 2, we suppose that pe...

Ngày tải lên: 17/03/2014, 02:20

... observations: a set of func- tions has been defined, “labeled” by the values (ν, a, ω). Re- calling that the set of functions used for short-time Fourier transforms (STFT) are of the form ϕ ω,u (t) ... Full Professor in the Signals, Systems, and Control Group of the D epartment of Applied Physics at Delft University of Technology, and since 2003, he has been Codirector of the D...

Ngày tải lên: 22/06/2014, 23:20

... as a rendezvous region for the queries and the generated data. Therefore, it enables the gathering of all of the generated data in the network and permits the performing of certain data optimizations ... path of the sink’s query forwarding path can be calculated by using the cell address of the sink as given in the Algorithm 1-II, or can be stored in the query packet. The forwardi...

Ngày tải lên: 20/06/2014, 20:20

... prove the second statement of Theorem 1. ProofofStatement(ii) of Theorem 1. By the same argument in the proof of Stament (i) of Theorem 1, we can assume without loss of generality that A is complete. Assume ... 1  (H i m (M)), for every system of parameters x =(x 1 , ,x d ) of M, where H i m (M) stands for the i th local cohomology mo dule of M with respect to the maxima...

Ngày tải lên: 06/08/2014, 05:20

... concrete example, let S bethesetofallwordsoflength7overΣ={a, b}. Each word of S is 2-avoidable, but any binary word of length 7 or more encounters an element of S. An image of xxx or xyxyx under a non-erasing ... palindrome, we need only show that no prefix of m n is an overlap. First note that no prefix of m n is a square of length 12 or greater; otherwise the prefix of m n of...

Ngày tải lên: 07/08/2014, 06:20

... must have r k ≡ g (mod 2). The choice of residue for the modulus 3 is forced. There are then six choices for the modulus 9, two for 18, three for 27, and two for the second 27. Thus, there are 6 ... congruent modulo 4, we see that there are precisely five choices for the modulus 5, four for the modulus 10, three for 15, two for 30, and two for 20. So there are 5 × 4 × 3...

Ngày tải lên: 07/08/2014, 06:20