Báo cáo toán học: "Asymptotics for the Probability of Connectedness and the Distribution of Number of Components Jason P Bell Department of Mathem" doc

... Compton [10] and by Knopfmacher and Knopfmacher [18] in their interesting papers. Inevitably, our examples overlap with these papers. Example 1: For forests of trees, C(x) enumerates trees and ... of Connectedness and the Distribution of Number of Components Jason P. Bell Department of Mathematics University of California, San Diego La Jolla, CA 92903-01...

Ngày tải lên: 07/08/2014, 06:20

... the covariance form of X.LetY N be the sum of N independent copies of X. For any vector v,letp(v) be the probability for the random walk, and let q(v) the density for the corresponding Brownian motion ... f µ /k!in(1). We can apply (2) to compute the distributions of the entries of random large Young tableaux with at most n rows. For example, the pr...

Ngày tải lên: 07/08/2014, 08:22

... = 1 n! n  k=1 s(n, k )P (k) 2 , where and s(n, k) and S(n, k) are Stirling numbers of the first and second kind respectively. As in the first proof, the number of pairs of preorders for which the meets of the blocks form ... Proof We will use the probabilistic method and the notation used in the proof of The- orem 2.1. The idea behind the proof is t...

Ngày tải lên: 07/08/2014, 13:21

... either temperature or gas concentra- tion. The modification of microclimate is primarily due to the production and capture of energy and gases by the tree components. Representation of canopy ... Cavelier J., Jackson P. , Control of transpiration from the upper canopy of a tropical forest: the role of stomatal, bound- ary layer and hydraulic architecture compon...

Ngày tải lên: 08/08/2014, 14:22

... Schensted-Knuth correspondence, in terms of standard and semi-standard Young tableaux. When n →∞, the asymptotics of the number of such words is calculated. ∗ Work partially supported by N.S.F. Grant ... associated with strips of Young diagrams, Adv. in Math. 41 (1981), 115–136. ASYMPTOTICS OF THE NUMBER OF k-WORDS WITH AN -DESCENT Amitai Regev ∗ Department of Mat...

Ngày tải lên: 07/08/2014, 06:22

... yields av p (n, d) p ≤ 2 p+ d n p p/2  k=1 k p/ 2 (k +1) d (k +2) d  (p/ 2,k,n) . If p ≥ 4d,then av p (n, d) p ≤ 2 p/ 2+3d n p p p/ 2 (p +2) −d (p +4) −d p/ 2  k=1  (p/ 2,k,n) ≤ 2 p/ 2+3d p p/2 (p +2) −d (p ... +2) −d (p +4) −d n p/ 2 . If p& lt;4d,then av p (n, d) p ≤ 2 p+ d n p p/2  k=1  (k +1)(k +2)  p/ 4−d  (p/ 2,k,d) ≤ 2 5p/ 4 3 p/ 4−d...

Ngày tải lên: 07/08/2014, 13:21

... y)ofelementsfromA n (respectively, S n ) such that the parts of Π are the orbits of the group x, y generated by x and y. Similarly let g A (Π) and g S (Π), respectively, be the number of pairs ... Secondary 2 0P0 5 05A16 20E05 Abstract The probability that a random pair of elements from the alternating group A n generates all of A n is shown to have an asymptot...

Ngày tải lên: 07/08/2014, 13:21

... l 2 ) z −  p prime  k,l≥1 (kp) a (lp) b ((kp) 2 + (lp) 2 ) z +  p 1  =p 2 prime  k,l≥1 (kp 1 p 2 ) a (lp 1 p 2 ) b ((kp 1 p 2 ) 2 + (lp 1 p 2 ) 2 ) z − + ··· =  1 −  p prime 1 p 2z−a−b +  p 1  =p 2 prime 1 (p 1 p 2 ) 2z−a−b − ... of this paper is to work out the exact asymptotics for the simple special case p = 2 by imitating the classical reasonin...

Ngày tải lên: 07/08/2014, 15:23

... 0.03001342380 6 Asymptotics of Fourier-Laplace integrals We conclude with the main analytic results behind the proofs of Theorems 3.2 and 3.3. Pemantle and Wilson’s approach in [PW02] and our approach here ... This improves upon [PW02] which gave formulas for the leading term only and only for the case p = 1. Furthermore, we prove that the expansions for F nα are...

Ngày tải lên: 07/08/2014, 21:20