Basic Geotechnical Earthquake Phần 4 docx

... (5.1a) a = (2,1 54, 000)(r) –2.10 (5.1b) b = (0. 046 )+(0 .44 5)log(r) (5.1c) d = (2.515)+(0 .48 6)log(r) (5.1d) where, Y = peak horizontal acceleration (in gal) (1 gal = 1 cm/sec 2 ) M = earthquake magnitude r ... Very sensitive clays may lose so 38 Basic Geotechnical Earthquake Engineering 38 DYNAMIC SOIL PROPERTIES 4 CHAPTER 4. 1 INTRODUCTION This book is concerned with geotec...

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... India. 3. Explain about earthquake resistant structures in India.

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... Basic Geotechnical Earthquake Engineering SLOPE STABILITY ANALYSES FOR EARTHQUAKES 9 CHAPTER 90 9.1 INTRODUCTION Slope movement is secondary effect of earthquake. There can be many types of earthquake induced ... 18.2) = 41 .4m 2 . For unit length of slope, total weight of wedge, W = (41 .4) (18.1) = 750 kN/m. Static case: F h =0 Using Eq. (9.2(a)) and the information given in the p...

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... (0.5)(0.295)(130)(5) 2 = 47 9.375 lb/ft From 5ft to 50ft, P 2A =k A γ t (5) (45 ) + (0.5)(k A )(γ b ) (45 ) 2 = (0.295)(130)(5) (45 ) + (0.5)(0.295)( 64) (45 ) 2 = 8628.75 + 19116 = 27 744 .75 lb/ft. P A =P 1A + P 2A = 47 9.375 ... pseudostatic force is calculated 1 14 Basic Geotechnical Earthquake Engineering Home Work Problems 1. Solve Example 10.1 for earthquake condition usi...

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... 38 4. 1 Introduction 38 4. 2 Soil Properties for Dynamic Loading 38 4. 3 Types of Soils 39 4. 4 Measuring Dynamic Soil Properties 41 (vii)

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... environments. The white dots in Fig. 2.8 locate earthquakes along strands of this fault system in the San Francisco Bay area. 14 Basic Geotechnical Earthquake Engineering Fig. 2.9 (Courtesy: NASA, ... below. Table 2.2: Rupture area of certain earthquakes (Courtesy: http:// eqseis.geosc.psu.edu) Date Location Length (km) Depth (km) (Mw) 12/16/ 54 Dixie Peak, NV 42 14 6. 94 06/28/66...

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... = 0.3g Aa = 0.4g Aa = 0.5g A 0.1 0.2 0.3 0 .4 0.5 B 0.12 0. 24 0.33 0 .4 0.5 C 0.16 0.28 0.36 0 .44 0.5 D 0.25 0. 34 0.36 0 .46 SI A a = Effective peak acceleration SI = Site specific geotechnical investigation ... environments. 54 Basic Geotechnical Earthquake Engineering Selection of Design Earthquake The selection of a design earthquake may be based on: (a) Known design-l...

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... (1.5)(18.9) + (1.5)(9. 84) = 43 kPa. Using, r d = 1 – 0.012z, with z = 3m, r d = 0.96 Also, σ σ v0 v0 ′ = 58 /43 = 1.35 and a g max = 0 .45 g/g = 0 .45 Substituting the values in Eq. (6 .4) , CSR = 0.38 Also, ... induced by the design earthquake. Solution: Using results of Example 6.1, σ v0 = 58 + 20 = 78 kPa. σ v0 ′ = 43 + 20 = 63 kPa. Using Eq. (6 .4) , CSR = 0.65(0.96)(78/63)(0 .45...

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... structures. 1 24 Basic Geotechnical Earthquake Engineering Fig. 11.8 Schematic of the earthquake design procedure (Courtesy: http://www.branz.co.nz) Earthquake Resistant Design of Buildings 131 4. Analyse ... spectra. 4. What are the types of earthquake resistant structural systems? Briefly explain about them. 5. Comment on earthquake engineering design techniques. 126 Basic...

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... 58 SASW 42 , 43 Scenario earthquakes 46 Seismic 46 , 47 , 48 , 50, 53, 54, 56 Seismic acceleration 122 Seismic coefficients 91, 54 Seismic mass 118, 122, 125, 128 138 Basic Geotechnical Earthquake ... 1 Sensitivity 40 , 84 Serviceability limit state 116, 117, 118, 131 Shake 49 Shallow dipping 22 Shallow earthquakes 19, 27 Shear (S) 15 Shear modulus 24, 29, 41 , 43 , 45...

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