... X X49. I Have ,WhoHas ? X X X X X X778083 91 9597 10 0 10 4 10 6 10 9 11 2 11 9 12 2 12 5 12 8 13 3 13 6 13 9 14 3 14 7 15 1 15 4 15 8 16 3 16 8 17 0 17 4 17 9 18 2xiv ContentsChapter 8Number CutoutsGrades ... 98, 10 1, 10 2, 12 3, 12 6, 13 4, 15 6, 16 4, 17 1, 18 3, 19 8, 207, 212 ,225, 229, 234, 243, 272, 279, 285, 298, 302, 322, 343, 350, 356, 3 61, 365, 368, 3 81, 384, 398, 399, 402,405, 409, 415 , 417 , 4 21. Published ... Selected Potpourri Activities408 411 414 414 415 416 416 417 418 418 419 4204204 21 422423424Selected Bibliography 427Index 428Contents xvii2. The problem 16 +12 = is solved below (in equation...