Foundations of Technical Analysis phần 2 pdf

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Ngày tải lên: 21/01/2014, 08:20

... consequences of this, too, are pursued in what follows, especially in Chapters 11 and 12. Comparative histories are instructive; in the case of comparisons of the evolution of diVerent traditions of ideas ... registered in (20 ) and (21 ): (20 ) a. De jongelei dansen hier vaak (‘The young people dance here often’) b. Er wordt hier door de jongelei vaak gedanst it is here by the yo...

Ngày tải lên: 24/07/2014, 09:20

... identifiers, vol1, vol2, and vol3. #light type Volume = | Liter of float | UsPint of float | ImperialPint of float let vol1 = Liter 2. 5 let vol2 = UsPint 2. 5 let vol3 = ImperialPint (2. 5) To deconstruct ... follows: Enter day of the month on which you were born: 23 Enter number of the month you were born: 5 Enter last two digits of the year of your birth: 78 Date of bir...

Ngày tải lên: 05/08/2014, 10:21

... consist of a list of points or sections that consist of functions. The definition of the type is as follows: CHAPTER 11 ■ LANGUAGE-ORIENTED PROGRAMMING 27 2 7575Ch11.qxp 4 /27 /07 1:07 PM Page 27 2 This ... tree: type Expr = | Ident of string | Val of System.Double | Multi of Expr * Expr | Div of Expr * Expr | Plus of Expr * Expr | Minus of Expr * Expr The tree consists...

Ngày tải lên: 05/08/2014, 10:21

... (Rowntree, 1976: 1 12) . When reading or listening, your mind may tend to wander off. You might be inclined to think about work, money, or relationships. It is quite easy for other aspects of your life ... hand (Kesselman-Turkel and Peterson, 19 82: 2) . l Taking notes will help you to remember what you have heard or read (Kesselman-Turkel and Peterson, 19 82: 3). We learn more effecti...

Ngày tải lên: 22/07/2014, 22:20

... . )(1 1 , )(1 1 , )(1 1 2 3 2 2 1 2 3 2 2 2 2 2 1 2 2 2 2 1 2 3 2 1 2 1 2 1 2 1 2 1 2 dt xd td xd dt xd td xd dt xd td xd dt dx c dt dx c dt dx c  c c  c c  c c Insertion into Newton’s law 1 2 1 2 3 2 1 )(1 1 2 F dt xd m dt dx c ... surface of an ellipsoid with a contracted axis in the direction of the motion, viz. . 1 2 2 3 2 2 2 1...

Ngày tải lên: 23/07/2014, 16:21

... 12 )( )( 2 Lengthw = − 12 (4) (3) 2 = − 4 kN-m M F cb = 12 )( )( 2 Lengthw = 12 (4) (3) 2 = 4 kN-m (d) Compute DF at b: 2 m 2 m 4 m a c b 3 kN/m 4 kN 2 m 2 kN 2 m 2 m 4 m a c b 3 kN/m 4 ... moments of the frame shown. 0.4 1 .2 −3.8 3.8 −0.4 −1 .2 I nflection point P P /2 P /2 P /2 P /2 = + 175 Beam and Frame Analysis: Displacement Method Part I 1...

Ngày tải lên: 05/08/2014, 09:20

... maximize F CJ . 1kN 1kN 2 kN 1m 2m 2 kN 10 kN/m 10 kN/m x 6 m 1 .25 1 .25 0. 625 0.41 F CJ 2 kN 1 .25 1 .25 0. 625 0.41 F CJ 2 kN 1kN 1kN 1m2m 7 m 9 m Influence Lines by S. T. Mau 26 4 S = ( L aL − ) S i ... m 1 .25 1 .25 0. 625 0.41 F CJ 10 kN/m 6 m 9 m 1.18 1. 82 1 .25 1 .25 0. 625 0.41 F CJ 6 m 9 m 1.18 1. 82 Influence Lines by S. T. Mau 26 2 Problem 1. (1) Constru...

Ngày tải lên: 05/08/2014, 09:20

... R s2 : i i R 1 = v g – v a ≈ v g - s ss s v RR R 12 2 + = v g - gv ss s vA RR R 12 2 + ⇒ i g i i v Z = ≈ 21 2 1 1 1 ss s RR R R + × + − µ µ ≈ ( µ + 1)R 1 (Giả sử R s2 ... với phần mạch cực D 2) Phản ánh vào D: Giữ nguyên phần mạch cực D và đoạn tương đương DS Phần mạch cực S × ( µ + 1) 3) Phản ánh vào S: Giữ nguyên phần mạch cực S Phần mạch cực D...

Ngày tải lên: 20/08/2012, 11:16