Design and Optimization of Thermal Systems Episode 3 Part 2 pdf

... This leads to the equation 20 41 67 29 1 1 20 8 22 . (. / )  VV or 2. 9 V 1  (9.816) 1 /2  3. 133 Therefore, V *  1. 425 m 3 . Then, A *  26 . 536 m 2 and U *  122 5.16. It can easily be shown ...  m 1   m 2 , is given as 14 and the follow- ing equations apply: qmm qmm 11 2 1 22 2 2 436 32 5     Obtain the values of  m 1 and  m 2...

Ngày tải lên: 06/08/2014, 15:21

... w ww w * .  ¤ ¦ ¥ ³ µ ´ ¤ ¦ ¥ ³ µ ´ ¤ ¦ ¥ ³ µ ´ ¤ ¦ 122 02 12 3 4 12 3 ¥¥ ³ µ ´  ¤ ¦ ¥ ³ µ ´ ¤ ¦ ¥ ³ µ ´ ¤ ¦ ¥ ³ pw 4 1 13 2 13 2 13 13 13 /// // µµ ´ ¤ ¦ ¥ ³ µ ´   13 23 2 02 1 13 92 / / . .m The independent variables ... D1 Cost to D2 Cost to D3 C1 27 31 37 C 22 930 31 C 338 3 433 The optimal path for each subsection is underlined. We can similarly c...

Ngày tải lên: 06/08/2014, 15:21

... given as A–1 A 2 A 3 A–4 1–D 2 D 3 D 4–D 10 14 12 15 16 12 10 8 and 1–1 1 2 1 3 1–4 2 1 2 2 2 3 2 4 16 20 14 17 12 14 15 6 3 1 3 2 3 3 3–4 4–1 4 2 4 3 4–4 10 11 13 18 8 11 14 22 Determine the ... Linear, and Dynamic Programming 597 and for the others 1–1 1 2 1 3 2 1 2 2 2 3 3–1 3 2 3 3 12 15 19 15 13 17 18 18 16 10 .20 . Solve the dynamic programmin...

Ngày tải lên: 06/08/2014, 15:21

... . )( . ) . 35 14 148 22 49 04 32  mm 04 32 32 56 0 .  Therefore,  m  ¤ ¦ ¥ ³ µ ´  32 56 49 1 6 92 136 . . . /. The second derivative is obtained as dC dm mm 2 2 06 42 1 96 104 19     ... constant Δ G y (b) x 4.0 3. 0 2. 0 1.0 4. 03. 0 3 2 1 2. 01.00.0 U = x + y = 4 U*= 2 G = xy – 1 = 0 474 Design and Optimization of Thermal Systems seek...

Ngày tải lên: 06/08/2014, 15:21

... 1. 633 9.840 1.944 1. 633 6.788 1.944 0. 828 5.598 2. 438 0. 828 5.456 2. 438 0.740 5. 428 2. 5 32 0.740 5.4 23 2. 5 32 0. 726 5.4 23 2. 548 0. 726 5. 422 2. 548 0.7 23 5. 422 2. 550 0.7 23 5. 422 2. 550 0.7 23 5. 422 For ... Increment 1 .35 2 2.670 26 .668 –6 .27 5 Return 1 .35 2 2.675 26 .690 0 Increment 1 .21 1 2. 875 26 .2 43 3. 20 5 Return 1 .21 1 2. 879 26 ....

Ngày tải lên: 06/08/2014, 15:21

... 5 12 0 15 05 1 2 2 12 TT w w 125 3 3 . ¤ ¦ ¥ ³ µ ´ with w 1  w 2  w 3  1 w 1  2w 2  w 3  0 0.5w 1  1 .25 w 3  0 The last two equations are obtained by setting the sum of the exponents of ... W 1 W 2 W 3 . (c) Response surface for the objective function F for W 1 W 2 W 3 / 2. 554 Design and Optimization of Thermal Systems Stoecke...

Ngày tải lên: 06/08/2014, 15:21

... at x = 2. 5 and 3. 6 % x1 =2. 5; y1=a(1)*x1^5+a (2) *x1^4+a (3) *x1 ^3+ a(4)*x1 ^2+ a(5)*x1+a(6) x2 =3. 6; y2=a(1)*x2^5+a (2) *x2^4+a (3) *x2 ^3+ a(4)*x2 ^2+ a(5)*x2+a(6) % Curve Fitting % % Enter data % x=[1 23 4 56]; y=[106.4 ... data % x=[1 23 4 56]; y=[106.4 57.79 32 .9 19. 52 12. 03 7.67]’; % % Form Matrix for exact fit % c1=[x(1)^5 x(1)^4 x(1) ^3 x(1) ^2 x(1)^1 1]; c2=[x (2) ^5...

Ngày tải lên: 06/08/2014, 15:21

... 38 33 31 31 5% 7, 833 0.46 40 1.110 40 38 36 36 33 29 29 29 10% 7,785 0.46 31 0.867 31 31 31 29 29 28 28 29 20 % 7,689 0.46 22 0. 635 22 22 22 22 24 24 26 29 30 % 7, 625 0.46 19 0.5 42 Cr–Ni (chrome-nickel); 15 ... 38 0.9 39 0.5 38 5 111.85 23 3 0.9169 1.0 12 1 .39 71 22 .24 32 .59 0.690 38 6.0 39 3.0 39 0 116.85 24 2 0.9050 1.0 13 1 .39 68 22 .44...

Ngày tải lên: 06/08/2014, 15:21

... 2. 025 8E 00 4. 936 3E-01 1 .26 59E 01 7.8993E- 02 20 2. 1911E 00 4.5 639 E-01 1 .35 90E 01 7 .35 82E- 02 25 2. 6658E 00 3. 7512E-01 1.5 622 E 01 6.4012E- 02 30 3. 2 434 E 00 3. 0 8 32 E-01 1. 729 2E 01 5.7 830 E- 02 35 3. 9461E ... 02 7. 630 6E-01 6.7952E-01 25 1.6003E 00 1.5610E 02 7 .2 138 E-01 6 .24 88E-01 30 1.4458E 00 2. 0106E 02 6. 8 32 2E-01 5.7640E-01 35 1 .33...

Ngày tải lên: 06/08/2014, 15:21

... systems, 33 6 34 2, 33 8 34 2 three-dimensional problem, 33 9 two-dimensional surface ow due to, 34 1 7 02 Design and Optimization of Thermal Systems optimization of, 433 priority for changing, 32 2 sensitivity ... 594–598 720 Design and Optimization of Thermal Systems System design applications, 32 2 32 3 component design vs. system design,...

Ngày tải lên: 06/08/2014, 15:21