Design and Optimization of Thermal Systems Episode 2 Part 4 doc
Design and Optimization of Thermal Systems Episode 2 Part 4 doc
... states.
3 04 Design and Optimization of Thermal Systems
Library of Previous Designs
Any industry involved with the design of systems and equipment would generally
develop many successful designs ... design
4. Modeling of the system
5. Simulation of the system
6. Evaluation of the design
7. Selection of an acceptable design
Optimization of the design...
Design and Optimization of Thermal Systems Episode 2 Part 1 doc
... =
T( 14) =
T(15) =
T(16) =
T(17) =
T(18) =
T(19) =
T (20 ) =
T (21 ) =
T (22 ) =
T (23 ) =
T ( 24 )=
T (25 ) =
T (26 ) =
T (27 ) =
T (28 ) =
T (29 ) =
1 14. 6578
109.7 928
105.3803
101.3981
97. 826 3
94. 646 7
91. 843 4
89 .4 022
87.3109
85.5588
84. 1371
83.0388
82. 2581
81.79 14
81.6360
81.79 14
82. 2581
83.0388
84. 1371
85.5588
87.3109
89 .4 022
91. 843 4
94. 646 7
97. 826 3
101...
Design and Optimization of Thermal Systems Episode 2 Part 5 docx
... 5 .22 .
(b)(a)
T
4
T
4
yy
L
Q
s
h
h
W
m
3
q'''
h
T
a
T
4
FIGURE 5 .22 Model of an electric circuit board, as considered in Example 5.5.
330 Design and Optimization of Thermal Systems
3. ...
1.00.80.60 .40 .2
0.0
0.0
40 .0
80.0
120 .0
T – T
a
(°C)
160.0
20 0.0
Y
(a)
Temperature
limit
Q = 10 × 20 0 W
Q = 8 × 20 0 W
Q = 5 × 20 0 W
Q = 3 × 20 0 W...
Design and Optimization of Thermal Systems Episode 2 Part 6 doc
... losses and may be written as
p
V
gz p
V
gz
fL
D
V
K
V
h
1
1
2
12
2
2
2
22
22 2
R
R
R
R
RR
33
22
(5.30)
where the subscripts 1 and 2 refer to two locations in the ow, g is the magnitude
of ... crystal-growing process.
Acceptable Design of a Thermal System 349
Therefore,
h
o
r
5 74 0 015
0 02
43 1
.
.W/(m K)
2
and
U
1
1 541 8 9 1 43 1(/ . ) (...
Design and Optimization of Thermal Systems Episode 2 Part 2 ppt
...
168.69990
168.69990
168.69990
168.69990
168.69990
168.69990
168.69980
168.69970
168.69950
168.69900
168.69830
168.69680
168.6 941 0
168.68890
168.67910
168.66060
168. 625 10
168.55670
168. 42 1 90
168. 145 10
167. 527 70
165.87 840
158.95630
105.65780NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
FLOW:
FLOW:
FLOW:
FLOW...
Design and Optimization of Thermal Systems Episode 2 Part 3 pdf
... T
a
, as
d
d
HF
Q
T
QQ QQ
1
12 1 1 2
()(,)
(4. 44a)
d
d
HH G
Q
T
QQQQQ
2
22 3 2 1 1 2
()(,) (4. 44b)
where
H
hA
CV
H
hA
CV
H
hA
CV
1
11
111
2
22
222
3
11
22 2
RRR
,
Then the analytical ...
equations
7c
1
c
2
2
c
3
c
4
3.7
c
1
2
8c
2
3c
3
c
4
4. 9
2c
1
2c
2
5c
3
c
4
2
8.8
c
1
c
2
c
3
2
14c
4
18 .2
Numerical Modeling and Simula...
Design and Optimization of Thermal Systems Episode 2 Part 7 ppsx
... 110 .47 110. 52 110. 52
2 120 .0 121 .0 122 . 04 122 . 14 122 . 14
5 150.0 161.05 1 64. 53 1 64. 86 1 64. 87
10 20 0.0 25 9.37 27 0.70 27 1.79 27 1.83
20 300.0 6 72. 75 7 32. 81 738.70 738.91
30 40 0.0 1 744 . 94 1983. 74 20 07.73 ... 10 % 12 % 15 %
5 128 .36 148 .98 1 64. 53 181.67 21 0. 72
10 1 64. 71 22 1.96 27 0.70 330. 04 444 . 02
15 21 1.37 330.69 44 5.39 599.58...
Design and Optimization of Thermal Systems Episode 2 Part 8 pdf
... n 10 n 15
1 33.3 20 .0 14. 3 10.0 5.0
2 44 .5 32. 0 24 .5 18.0 9.5
3 14. 8 19 .2 17.5 14. 4 8.6
4 7 .4 11.5 12. 5 11.5 7.7
5 11.5 8.9 9 .2 6.9
6 5.8 8.9 7 .4 6 .2
7 8.9 6.6 5.9
8 4. 5 6.6 5.9
9 6.5 5.9
10 ...
to pay off this loan can be calculated from the formula given in Equation (6 .20 b).
Then, i 0.1, n 2, and m 12, and we obtain
S (136,833. 62)
(./)( ./)
(./)
0 1...
Design and Optimization of Thermal Systems Episode 2 Part 9 pps
... rates of 4, 6, and 10%. Compare the results obtained with
$150,000
Down payment
$30,000
Salvage
109876 54 321
Years
FIGURE P6 . 24
44 0 Design and Optimization of Thermal Systems
and
H
i
(x
1
, x
2
, ... formulation of the problem are
1. Determination of the design variables, x
i
where i 1, 2, 3, . , n
2. Selection and denition of the objective functi...
Design and Optimization of Thermal Systems Episode 2 Part 10 ppsx
... 22 , and 24 hours, T is
obtained as 86.5, 97.7, 1 02. 0, 101.7, 92. 5, 62. 3, 55.0, 67.5, and 80.0nC,
respectively. Obtain a best t assuming a variation of the form A
sin (2 T / 24 ) B cos (2 T / 24 ) ... may be used to develop a trade-off curve in
optimization.
47 0 Design and Optimization of Thermal Systems
7. 12. For the thermal systems considered in Example...
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