Design and Optimization of Thermal Systems Episode 2 Part 3 pdf
Design and Optimization of Thermal Systems Episode 2 Part 3 pdf
...
equations
7c
1
c
2
2
c
3
c
4
3. 7
c
1
2
8c
2
3c
3
c
4
4.9
2c
1
2c
2
5c
3
c
4
2
8.8
c
1
c
2
c
3
2
14c
4
18 .2
Numerical Modeling and Simulation 28 7
(c) Set up this system of equations ... between the output and the production rate yields the equations
xxx
xxx
xx xx
124
1 23
12 37
25 32
32 6 36
35 2 4
11
21 0858
23 4
xxx...
Design and Optimization of Thermal Systems Episode 2 Part 8 pdf
... 8%, 6)
[35 00] 20 000/4. 6 23 500/7 .33 6 23 81.5/4. 6 23 $ 827 3. 31
C
B
[20 00 1000] 30 000/(P/S, 8%, 6) 30 00/(F/S, 8%, 6)
[1000] 30 000/4. 6 23 30 00/7 .33 6 $7080.51
Here, the refurbishing ... (6 .20 b).
Then, i 0.1, n 2, and m 12, and we obtain
S ( 136 , 833 . 62)
(./)( ./)
(./)
0 1 12 1 0 1 12
101 12 1
24
24
Đ
â
ă
ả
á
Ã
$6 ,31 4.18
Ther...
Design and Optimization of Thermal Systems Episode 2 Part 1 doc
... =
114.6578
109.7 928
105 .38 03
101 .39 81
97. 826 3
94.6467
91.8 434
89.4 022
87 .31 09
85.5588
84. 137 1
83. 038 8
82. 2581
81.7914
81. 636 0
81.7914
82. 2581
83. 038 8
84. 137 1
85.5588
87 .31 09
89.4 022
91.8 434
94.6467
97. 826 3
101 .39 81
105 .38 03
109.7 928
114.6578
T(1) ... results
Number of Iterations = 600
EPS = 0.00010
Number of Iterations = 766
EPS = 0.00001...
Design and Optimization of Thermal Systems Episode 2 Part 2 ppt
...
168.69990
168.69990
168.69990
168.69990
168.69990
168.69990
168.69980
168.69970
168.69950
168.69900
168.69 830
168.69680
168.69410
168.68890
168.67910
168.66060
168. 625 10
168.55670
168. 421 90
168.14510
167. 527 70
165.87840
158.95 630
105.65780NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
NH3:
FLOW:
FLOW:
FLOW:
FLOW:
F...
Design and Optimization of Thermal Systems Episode 2 Part 4 doc
... solidication.
3 12 Design and Optimization of Thermal Systems
900.0 720 .0540. 036 0.0180.00.0
0.00
0. 03
0.06
Mold wall thickness d
Mold material Iron
T
pour
= 1850 K
h = 80 W/m
2
K
3 cm
2. 5 cm
2 cm
Solid ... states.
30 4 Design and Optimization of Thermal Systems
Library of Previous Designs
Any industry involved with the design of systems and...
Design and Optimization of Thermal Systems Episode 2 Part 5 docx
... in the thickness and height of the board leads
32 4 Design and Optimization of Thermal Systems
discuss the design process for a typical system employed for thermal processing
of materials. The ... and constant heat ux
input q
s
, with q
s
R/k 5.0.
3 32 Design and Optimization of Thermal Systems
such as chips, techniques to enhance local heat transf...
Design and Optimization of Thermal Systems Episode 2 Part 6 doc
... losses and may be written as
p
V
gz p
V
gz
fL
D
V
K
V
h
1
1
2
12
2
2
2
22
22 2
R
R
R
R
RR
33
22
(5 .30 )
where the subscripts 1 and 2 refer to two locations in the ow, g is the magnitude
of ...
m
and P
to obtain the following two equations for
m
1
and
m
2
:
Fm m H Cm m P Am(, ) ( ) ()
.
12 1 2
2
11
27 5
(d)
Gm m H Cm m P Bm(,...
Design and Optimization of Thermal Systems Episode 2 Part 7 ppsx
... 10 % 12 % 15 %
5 128 .36 148.98 164. 53 181.67 21 0. 72
10 164.71 22 1.96 27 0.70 33 0.04 444. 02
15 21 1 .37 33 0.69 445 .39 599.58 935 . 63
20 27 1 .26 4 92. 68 7 32 . 81 1089 .26 1971.55
25 34 8. 13 734 . 02 120 5.69 ... 110. 52 110. 52
2 120 .0 121 .0 122 .04 122 .14 122 .14
5 150.0 161.05 164. 53 164.86 164.87
10 20 0.0 25 9 .37 27 0.70 27 1.79 27 1. 83
20 30...
Design and Optimization of Thermal Systems Episode 2 Part 9 pps
... present worth of buying
$30 0,000
1 23 4 5678910
Years
FIGURE P6 .22
$20 0,000
1 23 4 56
Years
Final
payment
FIGURE P6 . 23
Problem Formulation for Optimization 445
those of interest in thermal systems. ... formulation of the problem are
1. Determination of the design variables, x
i
where i 1, 2, 3, . , n
2. Selection and denition of the objective function, U...
Design and Optimization of Thermal Systems Episode 2 Part 10 ppsx
... 22 , and 24 hours, T is
obtained as 86.5, 97.7, 1 02. 0, 101.7, 92. 5, 62. 3, 55.0, 67.5, and 80.0nC,
respectively. Obtain a best t assuming a variation of the form A
sin (2 T /24 ) B cos (2 T /24 ) ... d/D and x
2
V
2
/V
1
. Then, the objective
function may be written as
UxxAFxxFxxA(,)=+ (,)+ (,)=
12 1 12 2 12
+++
21
Bx x Cx x
nm
12
(7. 13)
where F
1
and F...
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