Engineering Analysis with Ansys Software Episode 2 Part 3 pot

... description 24 2 5 .3 .2 Create a model for analysis 24 2 5 .3 .2. 1 Select kind of analysis 24 2 5 .3 .2. 2 Select element type 24 3 5 .3 .2. 3 Create keypoints 24 3 5 .3 .2. 4 Create areas for flow channel 24 5 5 .3 .2. 5 Subtract ... in lines and areas 22 2 5 .2. 2.6 Boundary conditions 22 6 5 .2. 3 Execution of the analysis 23 1 5 .2. 3. 1 FLOTRAN set up 23...

Ngày tải lên: 17/08/2013, 11:58

... kN a b c d 2. 77 kN 3. 36 kN-m 1 . 23 kN 0 .27 kN-m 0 .27 kN-m 1.64 kN-m 0.69 kN 0.69 kN c b 1.64 kN-m 0. 82 kN-m 1 . 23 kN 1 . 23 kN 1 . 23 kN 0.69 kN 0.69 kN 0.69 kN 0.69 kN 0.69 kN 1 . 23 kN c 1 . 23 kN 1 . 23 kN 0.69 ... (6) Problem 2. 2 m 2 m 3 m a c b 3 kN/m 4 kN 2EI E I 2 m 2 m 3 m a cb 8 kN 2EI E I 2 kN-m 50 kN a b c 4 m 4 m 4 m 8 m E I 2EI2EI 50 kN ab c 4 m 4 m 4...

Ngày tải lên: 05/08/2014, 09:20

... Given) ISO BS UNS DIN CuNi30MnlFe CN 107 C71500 CuNi30Fe 2. 08 82 Copper Minimum Rem. Rem. Rem. Rem. Maximum Nickel Minimum 29 .0 30 .0 29 .0 30 .0 Maximum 32 . 0 32 . 0 33 .0 32 . 0 Iron Minimum 0.4 0.4 0.4 ... C38500), and Tin Brasses (C 420 00, C4 430 0, C44500, C46400) in Different Chemical Environments (Continued) Environment/alloy 11000 122 00 22 000 23 000 26 000 28 000 36...

Ngày tải lên: 05/08/2014, 09:20

... example, 3. 028 +.0 03/ 009 has an upper limit of 3. 031 and a lower limit of 3. 019.) 2. Subtract the lower limit from the upper limit to get the total tolerance band. (3. 031 -3. 019=.0 12) 3. Divide ... shown in Figs. 8-1, 8 -2, and 8 -3. Statistical tolerance requirements can be indicated in the ST frame in one of the three ways defined in sections 8 .2. 1, 8 .2. 2, and 8 .2. 3....

Ngày tải lên: 21/07/2014, 15:20

... candidate processes //SYS21///INTEGRAS/B&H/PRS/FINALS_07-05- 03/ 075065 437 6-CH0 02- 1.3D – 22 3 – [35 24 8 /21 4] 9.5 .20 03 2: 05PM 7. 12 Brazing Process description . Heat is applied to the parts to be joined ... be removed. Resistance welding 21 3 //SYS21///INTEGRAS/B&H/PRS/FINALS_07-05- 03/ 075065 437 6-CH0 02- 1.3D – 21 2 – [35 24 8 /21 4] 9.5 .20 03 2: 05PM Process...

Ngày tải lên: 21/07/2014, 16:21

... P 1.0 2. 31 3. 89 1.0 2. 48 3 .22 Steel X 0.99 1 .25 3. 05 0.96 1. 43 2. 06 Steel Y 0.97 0.76 5.98 0.99 1.04 3. 04 Steel L 0.74 0 .38 8.78 0.88 0. 72 4 .21 Childs Part 2 28 :3 :20 00 3: 17 pm Page 24 4 With other ... –0.00011(T– 135 ) 2 + 150e –0.000 02( T 33 0) 2 + 100e –0.0001(T–650) 2 M = 0.0 32 5 + 0.000008T N = 0.18e –0.0007T + 0.055e –0.000015(T 37 0) 2...

Ngày tải lên: 21/07/2014, 17:20

Ngày tải lên: 21/07/2014, 17:20

... integrally with or it may be splined to the half shaft (Fig. 7 .22 ). It is made to engage with three planet gears carried on pins fixed to and rotating with the hub, thus driving Fig. 7 .21 Inboard ... (a±e) Crownwheel tooth contact markings 23 3 There are three stages of friction clutch loading: 1 Belleville spring action, 2 Bevel gear separating force action, 3 Vee slot wedgi...

Ngày tải lên: 21/07/2014, 17:20

Ngày tải lên: 21/07/2014, 22:20

... 26 6 A particle with a positive charge of 3 C moves upward at a speed of 10 m/s. It passes simultaneously through a magnetic field of 0 .2 T directed into the page and an electric field of 2 ... N/C. At what velocity must the particle be moving if it is not deflected when it enters this area? (A) 4.0 10 3 m/s (B) 125 m/s (C) 25 0 m/s (D) 500 m/s (E) The particle will be deflect...

Ngày tải lên: 22/07/2014, 10:22