Engineering Analysis with Ansys Software Episode 1 Part 7 potx

... (3 .11 ) 0 .1 1.0060 1. 0062 1. 0048 1. 0060 0.2 1. 0246 1. 0254 1. 0208 1. 0245 0.3 1. 0 577 1. 0594 1. 0 510 1. 0 574 0.4 1. 1094 1. 111 8 1. 1000 1. 1090 0.5 1. 18 67 1. 1892 1. 175 7 1. 1862 0.6 1. 3033 1. 3043 1. 29 21 1.30 27 0 .7 ... 1. 1892 1. 175 7 1. 1862 0.6 1. 3033 1. 3043 1. 29 21 1.30 27 0 .7 1. 4882 1. 48 41 1. 477 9 1. 4 873 0.8 1. 81...

Ngày tải lên: 06/08/2014, 11:21

... 4.44). Ch04-H6 875 .tex 24 /11 /2006 17 : 47 page 17 6 17 6 Chapter 4 Mode analysis D C Figure 4. 57 ANSYS Graphics window. Figure 4.58 ANSYS Graphics window. Ch04-H6 875 .tex 24 /11 /2006 17 : 47 page 16 9 4.3 Mode analysis ... Ch04-H6 875 .tex 24 /11 /2006 17 : 47 page 17 4 D E Figure 4.53 Window of Solid Circular Area. Figure 4.54 ANSYS Graphics window. Ch04-H6 875...

Ngày tải lên: 06/08/2014, 11:21

... contact stress 12 0 FM-H6 875 .tex 28 /11 /2006 16 : 7 page i Engineering Analysis With ANSYS Software This page intentionally left blank FM-H6 875 .tex 28 /11 /2006 16 : 7 page xi Contents xi 6.4 .1 Problem ... (1. 12)  1 0 w i Rdx =  1 0 1 −  −A 1 x 2 +(A 1 1) x +2A 1  dx = 13 6 A 1 − 1 2 = 0 (1. 13) Consequently, the first-order approximate solution...

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... c 3 1 c 1 1 b 1 1 c 2 1 b 2 1 c 3 1 b 3 1 ⎤ ⎥ ⎦ = 1 2 (1) ⎡ ⎢ ⎣ y 2 1 −y 3 1 0 y 3 1 −y 1 1 0 y 1 1 −y 2 1 0 0 x 3 1 −x 2 1 0 x 1 1 −x 3 1 0 x 2 1 −x 1 1 x 3 1 −x 2 1 y 2 1 −y 3 1 x 1 1 −x 3 1 y 3 1 −y 1 1 x 2 1 −x 1 1 y 1 1 −y 2 1 ⎤ ⎥ ⎦ (1. 102) Since ... Element 1. From Equations (1. 73 ) and (1. 69a) through (1. 69c), t...

Ngày tải lên: 06/08/2014, 11:21

... arithmetic calculations and complex algebra. Ch03-H6 875 .tex 24 /11 /2006 17 : 2 page 57 3 .1 Cantilever beam 57 (2) Input the value of Young’s modulus, 2.1e 11 (Pa), and that of Poisson’s ratio, 0.3, into ... subjects in engineering. 51 Ch03-H6 875 .tex 24 /11 /2006 17 : 2 page 62 62 Chapter 3 Application of ANSYS to stress analysis In order to delete the elements, execute the...

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... window. Ch03-H6 875 .tex 24 /11 /2006 17 : 2 page 77 3 .1 Cantilever beam 77 10 0 mm 10 0 N 50 mm 10 mm Figure P3.2 A beam clamped at the both ends and subjected to a concentrated force of 10 0 N at the ... solid Ch03-H6 875 .tex 24 /11 /2006 17 : 2 page 73 3 .1 Cantilever beam 73 C Figure 3.40 “Note” window. 3 .1. 3.6 GRAPHICAL REPRESENTATION OF THE RESULTS [1] Contour plot o...

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... → Mesh →Areas →Free (1) The Mesh Areas window opens. Ch03-H6 875 .tex 24 /11 /2006 17 : 2 page 93 3.3 Stress concentration due to elliptic holes 93 0 5 10 0 5 10 15 20 x (mm) 200 19 0 18 0 10 0 Longitudinal ... does not exist in reality. To erase this Ch03-H6 875 .tex 24 /11 /2006 17 : 2 page 10 1 3.3 Stress concentration due to elliptic holes 10 1 Figure 3 .72 Boundary condition...

Ngày tải lên: 06/08/2014, 11:21

... k  b 2 −x 2 (P3 . 17 a) k = 2P’ πb 2 (P3 . 17 b) b = 2 √ π  P’R 1 R 2 R 1 +R 2  1 −ν 2 1 E 1 + 1 −ν 2 2 E 2  (P3 . 17 c) p 0 = 1 √ π     P’(R 1 +R 2 ) R 1 R 2 · 1  1 ν 2 1 E 1 + 1 ν 2 2 E 2  (P3 . 17 d) PROBLEM ... are attached: Command ANSYS Utility Menu →Select →Entities … Ch03-H6 875 .tex 24 /11 /2006 17 : 2 page 14 0 14 0 Chapter 3 Application of...

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... to step 2 (Figure 4 .15 ). Ch04-H6 875 .tex 24 /11 /2006 17 : 47 page 15 1 4.2 Mode analysis of a straight bar 15 1 F G Figure 4 .14 Window of Density for Material Number 1. A B C Figure 4 .15 Window of Create ... window. Ch04-H6 875 .tex 24 /11 /2006 17 : 47 page 16 0 A Figure 4.30 Window of Solve Current Load Step. B Figure 4. 31 Window of Note. C Figure 4.32 Window of /STATUS C...

Ngày tải lên: 06/08/2014, 11:21