... the first and second factor (independent) variables. 1. The four vertex points are drawn. The vertex points are ( -1, -1) , ( -1, 1), (1, 1), (1, -1) . At each vertex point, the average of all the response ... and so we conclude that the X1*X2 term is not significant. 1. 3.3 .10 .1. DEX Contour Plot http://www.itl.nist.gov/div898 /handbook/ eda/section3/eda33a1.htm (3 of 4) [5 /1/ 2006 9:...
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... or lognormal. 1. 3.3. 21. 4. Normal Probability Plot: Data are Skewed Right http://www.itl.nist.gov/div898 /handbook/ eda/section3/eda33l4.htm (2 of 2) [5 /1/ 2006 9:56: 51 AM] indication of a departure from ... uniform order statistic medians are defined as: m(i) = 1 - m(n) for i = 1 m(i) = (i - 0. 3 17 5)/(n + 0.365) for i = 2, 3, , n -1 m(i) = 0.5** (1/ n) for i = n In addition, a...
Ngày tải lên: 06/08/2014, 11:20
Engineering Statistics Handbook Episode 1 Part 11 ppsx
... 6) [5 /1/ 2006 9:57 :14 AM] FACTOR 2 1 115 24.053 711 11 524.053 711 2.8982 91. 067% FACTOR 3 1 14380.633789 14 380.633789 3. 616 6 94. 219 % FACTOR 4 1 72 714 3 .12 5000 72 714 3 .12 5000 18 2.8703 10 0.000% ... 22 13 33 18 39 22 36 19 28 18 27 23 21 26 24 25 30 20 34 21 32 13 38 14 37 15 30 14 31 17 37 11 32 13 47 12 41 13 45 15 34 13...
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Engineering Statistics Handbook Episode 2 Part 7 ppt
... 2. 526 2. 4 72 2. 424 2. 3 82 2.345 2. 311 2. 281 2. 253 2. 228 56. 2. 5 82 2. 520 2. 465 2. 418 2. 376 2. 339 2. 305 2. 275 2. 2 47 2. 222 57. 2. 576 2. 513 2. 459 2. 4 12 2. 370 2. 3 32 2 .29 9 2. 268 2. 241 2. 215 58. 2. 570 ... 97. 2. 436 2. 373 2. 319 2. 271 2. 229 2. 191 2. 1 57 2. 126 2. 098 2. 073 98. 2. 434 2. 371 2. 3 17 2. 269...
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Engineering Statistics Handbook Episode 3 Part 6 ppsx
... purpose. ● 2 .3. 3. What are calibration designs? http://www.itl.nist.gov/div898 /handbook/ mpc/section3/mpc 33. htm (2 of 3) [5/1/20 06 10:11 :37 AM] 2. Measurement Process Characterization 2 .3. Calibration The ... reference standards and test items ● 2 .3. 3. What are calibration designs? http://www.itl.nist.gov/div898 /handbook/ mpc/section3/mpc 33. htm (3 of 3) [5/1/20 06 10:11 :...
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Engineering Statistics Handbook Episode 3 Part 7 pptx
... 1 1 1 1 1 0 .35 36 + 1 0 .35 36 + 1 0.6124 + 1 0.6124 + 0 0 .70 71 + - FACTORS FOR LEVEL-2 STANDARD DEVIATIONS WT FACTOR K 2 1 1 1 1 1 0 .70 71 + 1 0 .70 71 + 1 1.22 47 + 2 .3. 3 .3. 4. Calculation ... example, and ● 2 .3. 3 .3. 4. Calculation of standard deviations for 1,1,1,1 design http://www.itl.nist.gov/div898 /handbook/ mpc/section3/mpc 333 4.htm (3 of 3) [5/1/2006 10:...
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Engineering Statistics Handbook Episode 5 Part 7 pps
... lie in the range 0. 25 to 0 .5 for most LOESS applications. 4.1.4.4. LOESS (aka LOWESS) http://www.itl.nist.gov/div898 /handbook/ pmd/section1/pmd144.htm (2 of 5) [5/ 1/2006 10:21 :55 AM] Assumption Not ... robust method. 4.1.4.4. LOESS (aka LOWESS) http://www.itl.nist.gov/div898 /handbook/ pmd/section1/pmd144.htm (5 of 5) [5/ 1/2006 10:21 :55 AM] Disadvantages shared with the linear...
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Engineering Statistics Handbook Episode 6 Part 7 ppt
... Function http://www.itl.nist.gov/div898 /handbook/ pmd/section8/pmd8124.htm (4 of 6) [5/1/20 06 10:23:08 AM] 4.8.1.2.3. Linear / Quadratic Rational Function http://www.itl.nist.gov/div898 /handbook/ pmd/section8/pmd8123.htm (6 of 6) ... Function http://www.itl.nist.gov/div898 /handbook/ pmd/section8/pmd8123.htm (2 of 6) [5/1/20 06 10:23: 06 AM] 4.8.1.2.3. Linear / Quadratic Rational...
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Engineering Statistics Handbook Episode 10 Part 7 ppsx
... are: R (10) = 19/20 R(32) = 19/20 x 18/19 R(56) = 19/20 x 18/19 x 16/ 17 R(98) = 19/20 x 18/19 x 16/ 17 x 15/16 R(122) = 19/20 x 18/19 x 16/ 17 x 15/16 x 13/14 R(181) = 19/20 x 18/19 x 16/ 17 x 15/16 ... Reliability Evaluation 8.1 .10. How can Bayesian methodology be used for reliability evaluation? http://www.itl.nist.gov/div898 /handbook/ apr/section1/apr1a.htm (2 of 4) [5/1/2006 10: 4...
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