Báo cáo toán học: "On the Asymptotic Distribution of the Bootstrap Estimate with Random Resample Size" ppsx

... =[(1−s 0 )m],v=[(1+s 0 )m]. Vietnam Journal of Mathematics 33:3 (2005) 261–270 On the Asymptotic Distribution of the Bootstrap Estimate with Random Resample Size * Nguyen Van Toan Department of Mathematics, College of Science, Hue ... the bootstrap with random resample size which is not independent of the original sample. We find sufficient conditions on...

Ngày tải lên: 06/08/2014, 05:20

Ngày tải lên: 05/08/2014, 10:20

... gradient of the mean transmittance existed from the bottom to the top of the tree crown. Like in the PAR domain, the variability of the transmittance was more marked at the top and the bottom ... 1b. Distribution of the leaf area density (LAD in m 2 /m 3 ) within an North-South cross section of the tree crown. The zero position represents the trunk positi...

Ngày tải lên: 08/08/2014, 14:22

... cleavage of the aromatic fluoroquinolone core for the first time. Hence, two decades after the emergence of the notion of the non- biodegradability of fluoroquinolones, fungal degradation of all ... degradation of the cyclopropyl-substituent, which, however, is a natural product found, e.g., in the lipids of E. coli (Goldfine 1982). Two decades after the emerge...

Ngày tải lên: 20/06/2014, 21:20

... functions F i i  1, 2. The proof of a is complete. b In virtue of Lemma 5.5 the proof of the theorem will be complete if we show that the sequences H and h satisfy the conditions H 2 –H 5  ... is the well-known Riemann function. 5. Proofs of the main theorems 5.1. Proof of Theorem 3.1 To prove Theorem 3.1 we need the next result from 20. I. Gy ˝ ori and...

Ngày tải lên: 22/06/2014, 11:20

... by w. The multiplication of A by  n i=1 1 1−t i and the extraction of the coefficient of t r 1 t r 2 ···t r n in the result corresponds at the set theoretic level to the concatenation of the signed ... helps in carrying out the calculations with symmetric functions. To restrict the frequency of occurrence of symbols, we let P 3 be the set of all partitions...

Ngày tải lên: 07/08/2014, 06:20

... is the floor of x (the biggest integer less than or equal to x), and α k is the positive root of the equation x 2 +(k − 2)x − k =0. Golomb credits A. Fraenkel with suggesting the study of the ... values of the descendant sequence of 1. Golomb’s conjecture amounts to the assertion that, in the case B =1,foreachpositive integer k,thereisanunique way of assigning t...

Ngày tải lên: 07/08/2014, 06:20

... reasoning to the above, the probability that both these edges appear in the same member of D π is exactly h−2 r−2 h−3 r−3 . There are (h −1)(h −2)(h −3)/2 pairs of adjacent edges of the form (a i ,a j ), ... one member of L. The H-covering number of G, denoted by cov(G, H), is the minimum number of members in an H-covering design of G.(IfthereisanedgeofGwhich cannot...

Ngày tải lên: 07/08/2014, 06:20

... entries of a height function matrix for an ASM should be thought of as ofset from the entries of the ASM itself. If the entries of the ASM lie on vertices in the square grid, then the entries of the height ... the proof of the theorem. Lemma. Two fixed vertices are in the same component of the blue (respectively green) subgraph after the action of H k if...

Ngày tải lên: 07/08/2014, 06:20

... will meet each of the original sets. Proof of Lemma 1. If we can find a set of f (d, g) points that meets the convex hull of every subset of g|Q| of the elements of Q,itwillmeeteveryoneofourpolytopes. In ... (1−(p−1)h). Weexaggeratethisfactorbyreplacingitby(1−hp 2 /2);ifweuseLemma3,andset h=i/(d+1),weobtain i=(  q d+1  /  p d+1  )(1−ip 2 /(2(d+1)))or i=  q d+1  /  p...

Ngày tải lên: 07/08/2014, 06:22