(McGraw-Hill) (Instructors Manual) Electric Machinery Fundamentals 4th Edition Episode 1 Part 8 ppt

... generator is 15 1 () 11 1 21 2 384 V sin sin sin sin 36.4 31. 1 4 41. 6 V A A E E δδ −− == −°=−° The new armature current is 2 2 480 0 V 4 41. 6 31. 1 V 227 24 .1 A 1. 1 A A S jX ... kW 419 kWPPP=+= + = TOT 1 2 14 5 kVAR 11 5 kVAR 260 kVARQQQ=+= + = The overall power factor is 14 0 ()()()() 7 217 0 0. 0 18 7 4 619 36 .87 A 1. 716 4 619 36 .87...

Ngày tải lên: 05/08/2014, 20:22

... ()() EQ 11 5 0 V 0 .14 0 0.532 8. 7 36 87 A PS S Zj. ′ =+ =∠°+ + Ω ∠− °VV I 11 8. 8 1. 4 V P ′ =∠° V 11 8. 8 -11 5 VR 10 0% 3.3% 11 5 =×= (2) 1. 0 PF: ()() EQ 11 5 0 V 0 .14 0 0.532 8. 7 0 A PS ... ) 7967 0 V 7967 0 V 1. 78 28. 2 A 80 300 38 71 1 81 5 44 81 28. 2 S jj ∠° ∠° ′ ===∠−° +Ω+ + Ω ∠°Ω I and the referred secondary voltage is ()() 1. 78 28. 2...

Ngày tải lên: 05/08/2014, 20:22

... 255. 08 0.767 259.2 0 .8 263.74 0 .83 3 267.6 0 .86 7 270 .8 0.9 273.6 0.933 276 .14 0.966 2 78 1 279.74 1. 033 2 81 . 48 1. 067 282 .94 1. 1 284 . 28 1. 133 285 . 48 1. 167 286 .54 1. 2 287 .3 ... 285 . 48 1. 167 286 .54 1. 2 287 .3 1. 233 287 .86 1. 267 288 .36 1. 3 288 .82 1. 333 289 .2 1. 367 289 .375 1. 4 289 .567 1....

Ngày tải lên: 05/08/2014, 20:22

... ,SC SC 16 00 VVV φ == , ,SC SC / 3 1. 1547 AII φ == , and ,SC SC / 3 383 WPP φ == . , , 16 00 V 13 85 1. 155 A SC EQ SC V Z I φ φ == = Ω ()( ) , 11 ,, 383 W cos cos 78. 0 16 00 V 1. 155 A SC SC ... 2.50 :1 Y- ∆ 19 .9 kV 13 .8 kV 200 kVA 1. 44 :1 ∆ -Y 34.5 kV 7.97 kV 200 kVA 4.33 :1 ∆ - ∆ 34.5 kV 13 .8 kV 200 kVA 2.50 :1 open- ∆ 34.5 kV 13 .8 kV 346...

Ngày tải lên: 05/08/2014, 20:22

... ()() ()() EQ 1. 513 1. 134 3.36 0. 010 0.040 0.00723 0.0 482 0.040 0 .17 0 1. 513 1. 134 3.36 jj Zj j j jj +− =+ + + ++ + ++− EQ 0. 010 0.040 0.00 788 0.0525 0.040 0 .17 0 (2.3 58 0 .10 9)Zj j j j=+++++++ ... = ()( ) 11 38 W cos cos 78. 87 480 V 0. 41 A OC OC OC P VI θ −− =− =− =− ° 0.00 085 4 78. 87 0.00 016 5 0.00 083 8 EX C M YGjB j=− = ∠− °= − 1/...

Ngày tải lên: 05/08/2014, 20:22

... 12 /T− 12 /T c b SCR 3 SCR 5 SCR 5 -30 ° 12 /T 12 /3T a b SCR 1 SCR 5 SCR 1 30° 12 /3T 12 /5T a c SCR 1 SCR 6 SCR 6 90 ° 12 /5T 12 /7T b c SCR 2 SCR 6 SCR 2 15 0° 12 /7T ... equation: 12 1 0BB RC ω += ⇒ 21 BRCB ω =− sine equation: 21 1 M V BB RC RC ω −+ = 2 11 1 M V RC B B RC RC ω += 2 1 1 M V RC B RC RC ω +=...

Ngày tải lên: 05/08/2014, 20:22

... ( ) ( ) ( ) ( ) 12 40 0 0 .15 18 6 30 A 1. 1 18 6 30 A A j=∠°+ Ω∠−°+ Ω∠−°E 13 77 6 .8 V A =∠°E The resulting phasor diagram is shown below (not to scale): I = 18 6 ∠ -30° A V = 12 40 ∠ 0° V φ E = 13 77 ∠ 6 .8 ... this generator is 13 77 V 13 77 V 18 6 A 0 .15 1. 1 6.667 30 1. 82 9 A A AS E I RjXZ j == == ++ ++ ∠° Ω Therefore, the magnitude of the phase voltage...

Ngày tải lên: 05/08/2014, 20:22

... +EV I I ()( )()( ) 13 28 0 0 .15 2 51 36 .87 A 1. 1 2 51 36 .87 A A jE =∠°+ Ω∠°+ Ω∠ ° 12 17 11 .5 V A E =∠° The voltage regulation would be: 12 17 13 28 VR 10 0% 8. 4% 13 28 − =×=− (d) If the ... MW/Hz 2 Hz PA S == 3 MW 1. 676 MW/Hz 1. 79 Hz PB S == 3 MW 1. 9 61 MW/Hz 1. 53 Hz PC S == 11 6 ()()()() 13 28 0 0 .15 2 51 0 A 1. 1 2 51 0 A A jE =∠°...

Ngày tải lên: 05/08/2014, 20:22

... ( ) ( ) ,nl 13 28 0 V 2 .8 10 .5 0 A 13 28. 3 1. 27 V A j=∠°− Ω ∠°= ∠−°E ()( ) ,half 13 28 0 V 1. 5 93.6 0 A 13 54 11 .2 V A j=∠°− Ω ∠°=∠−°E ( ) ( ) ,full 13 28 0 V 2 .8 19 8 0 A 14 39 22.7 V A j=∠°− ... between the lines tested. R 1 R 1 R 1 V DC Therefore, the stator resistance 1 R will be () () 11 1 DC 1 DC 1 1 1 2 3 RR R V R IRRR + == ++...

Ngày tải lên: 05/08/2014, 20:22

... Characteristic'); grid on; 18 3 ()( ) () () 11 1 1 TH 11 11 MM MM jX R jX R j X X Z RjXX RjXX +−+ = ++ −+ () 222 2 11 11 1 1 1 1 TH 2 2 11 MMM MMM M RX X RX X RX j R X ... () () ( ) ( ) () 11 TH 11 15 0.20 0. 41 0 . 18 95 0.4 016 0.444 64.7 0.20 0. 41 15 M M jX R jX j j Zj RjXX j +ΩΩ+Ω == =+Ω=∠°Ω ++ Ω+ Ω+Ω () ( ) () () TH 11 15 12 0...

Ngày tải lên: 05/08/2014, 20:22