(McGraw-Hill) (Instructors Manual) Electric Machinery Fundamentals 4th Edition Episode 1 Part 5 ppsx
(McGraw-Hill) (Instructors Manual) Electric Machinery Fundamentals 4th Edition Episode 1 Part 5 ppsx
...
12 /T−
12 /T
c b SCR
3
SCR
5
SCR
5
-30
°
12 /T 12 /3T
a b SCR
1
SCR
5
SCR
1
30°
12 /3T
12 /5T
a c SCR
1
SCR
6
SCR
6
90
°
12 /5T
12 /7T
b c SCR
2
SCR
6
SCR
2
15 0°
12 /7T
... SCR
6
SCR
2
15 0°
12 /7T
12 /9T
b a SCR
2
SCR
4
SCR
4
210
°
12 /9T
12 /11 T
c a SCR
3
SCR
4
SCR
3
270
°
12 /11 T 12 /T
c b SCR
3
SCR
5
SCR
5...
(McGraw-Hill) (Instructors Manual) Electric Machinery Fundamentals 4th Edition Episode 1 Part 3 ppsx
...
()
2
2
base
base
base
15 kV
1. 1 25
200 MVA
V
Z
S
== =Ω
so
(
)
(
)
EQ
0. 012 1. 1 25 0. 013 5 R =Ω=Ω
()( )
EQ
0. 05 1. 1 25 0. 056 3 X =Ω=Ω
49
6 250 VA
52 .1 A
12 0 V
S
S
S
I
V
== =
2 -16 . A 50 00-VA 480 /12 0-V ...
,SC SC
16 00 VVV
φ
==
,
,SC SC
/
3 1. 154 7 AII
φ
==
, and
,SC SC
/
3 383 WPP
φ
==
.
,
,
16 00 V
13 85
1. 155 A
SC
EQ
SC
V
Z
I
φ
φ
== =...
(McGraw-Hill) (Instructors Manual) Electric Machinery Fundamentals 4th Edition Episode 2 Part 5 ppsx
... 19 0∠0° V,
1
11
I
0 .5 0 .5
FB
RjX Z Z
=
++ +
V
()( )( )
1
190 0 V
I 11 .2 27.0 A
1. 40 1. 90 0 .5 26 .59 9.69 0 .5 0.7 41 1.870jjj
∠°
==∠−°
++ ++ +
()
()( )
2
2
AG, 1
0 .5 11 .2 A 13 .29 16 67 W
FF
PIR== ...
()()
9 15 .00.962 0.9 51 ===
dpw
kkk
276
1. 4 Ω j1.9 Ω
+
-
V = 220∠0° V
I
1
R
1
jX
1
s
R
2
5. 0
j0.5X
2
j0.5X
M
j1.90 Ω
j30 Ω
s
R
−2
5. 0...
(McGraw-Hill) (Instructors Manual) Electric Machinery Fundamentals 4th Edition Episode 1 Part 1 pot
... 0.233 10 4.4
0.267 11 8.86
0.3 13 2.86
0.333 14 6.46
0.367 15 9.78
0.4 17 2 .18
0.433 18 3.98
0.467 19 5. 04
0 .5 2 05 .18
0 .53 3 214 .52
0 .56 7 223.06
0.6 2 31. 2
0.633 238
0.667 244 .14 ... 0.733 255 .08
0.767 259 .2
0.8 263.74
0.833 267.6
0.867 270.8
0.9 273.6
0.933 276 .14
0.966 278
1 279.74
1. 033 2 81. 48
1. 067 282.94
1....
(McGraw-Hill) (Instructors Manual) Electric Machinery Fundamentals 4th Edition Episode 1 Part 2 ppt
... Lagging:
()()
EQ
11 5 0 V 0 .14 0 0 .53 2 8.7 36 87 A
PS S
Zj.
′
=+ =∠°+ + Ω ∠− °VV I
11 8.8 1. 4 V
P
′
=∠°
V
11 8.8 -11 5
VR 10 0% 3.3%
11 5
=×=
(2) 1. 0 PF:
()()
EQ
11 5 0 V 0 .14 0 0 .53 2 8.7 0 A
PS ... be
(1. 2 T)(0.04 m)(0.04 m) 0.0 019 2 WbBA
φ
== =
(c) The total reluctance of the core is:
28
11 6.3 -11 5
VR 10 0% 1. 1%
11 5
=×=
(...
(McGraw-Hill) (Instructors Manual) Electric Machinery Fundamentals 4th Edition Episode 1 Part 4 pot
...
()()
()()
EQ
1. 51 3 1. 134 3.36
0. 010 0.040 0.00723 0.0482 0.040 0 .17 0
1. 51 3 1. 134 3.36
jj
Zj j j
jj
+−
=+ + + ++ +
++−
EQ
0. 010 0.040 0.00788 0. 052 5 0.040 0 .17 0 (2. 358 0 .10 9)Zj j j j=+++++++
...
EQ
0. 010 0.040 0.00723 0.0482 0.040 0 .17 0 1. 51 3 1. 134Zj j j j=+ + + ++ ++
EQ
1. 57 02 1. 3922 2.099 41. 6Zj=+ =∠°
The resulting current is
10
0.47 65...
(McGraw-Hill) (Instructors Manual) Electric Machinery Fundamentals 4th Edition Episode 1 Part 6 pps
...
()()()()
13 28 0 0 . 15 2 51 36.87 A 1. 1 2 51 36.87 A
A
j=∠°+ Ω∠− °+ Ω ∠− °E
15 37 7.4 V
A
=∠°E
(c) The equivalent open-circuit terminal voltage corresponding to an
A
E of 15 37 volts is
()
,oc
3 15 27 ... and electrical
frequency is
12 0
e
m
f
n
P
=
The resulting table is
Number of Poles
e
f
= 25 Hz
2 15 00 r/min
4 750 r/min
6 50 0 r/min
8 3 75 r/min
10 3...
(McGraw-Hill) (Instructors Manual) Electric Machinery Fundamentals 4th Edition Episode 1 Part 7 doc
...
(
)
()
(
)
()
(
)
()
sys sys sys
7 MW 1. 5 61. 0 1. 676 61. 5 1. 9 61 60.5fff=−+ −+ −
sys sys sys
7 MW 91. 5 1. 5 10 3.07 1. 676 11 8.64 1. 961fff=−+− +−
sys
5 .13 7 306.2f =
sys
59 . 61 Hzf =
The power supplied ... MW/Hz
2 Hz
PA
S ==
3 MW
1. 676 MW/Hz
1. 79 Hz
PB
S ==
3 MW
1. 9 61 MW/Hz
1. 53 Hz
PC
S ==
11 6
()()()()
13 28 0 0 . 15 2...
(McGraw-Hill) (Instructors Manual) Electric Machinery Fundamentals 4th Edition Episode 1 Part 8 ppt
... will be
()
11
1
21
2
13 76 V
sin sin sin sin 25. 3 24.6
14 15 V
A
A
E
E
δδ
−−
== −°=−°
Therefore, the new armature current will be
13 28 0 V 14 15 - 25. 3 V
214 .5 3 .5 A
0.4 2.8
A
A
AS
RjX ... 419 kWPPP=+= + =
TOT 1 2
14 5 kVAR 11 5 kVAR 260 kVARQQQ=+= + =
The overall power factor is
14 0
()()()()
7 217 0 0. 018 7 4 619 36.87 A 1. 716 4 61...
(McGraw-Hill) (Instructors Manual) Electric Machinery Fundamentals 4th Edition Episode 1 Part 9 pot
... then V
φ
= ( 15 /50 )(277) = 83 .1 V.
Also, note that
S
X
= ( 15 /50 ) (1. 5 Ω) = 0. 45 Ω. The maximum power that the motor could supply would
be
()()
max
3
3 83 .1 V 12 9 V
71. 5 kW
0. 45
A
S
VE
P
X
φ
== ...
(
)
(
)
,nl
13 28 0 V 2.8 10 .5 0 A 13 28.3 1. 27 V
A
j=∠°− Ω ∠°= ∠−°E
()( )
,half
13 28 0 V 1. 5 93.6 0 A 13 54 11 .2 V
A
j=∠°− Ω ∠°=∠−°E
(
)
(...
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