(McGraw-Hill) (Instructors Manual) Electric Machinery Fundamentals 4th Edition Episode 1 Part 4 pot

... ()() ()() EQ 1. 513 1. 1 34 3.36 0. 010 0. 040 0.00723 0. 048 2 0. 040 0 .17 0 1. 513 1. 1 34 3.36 jj Zj j j jj +− =+ + + ++ + ++− EQ 0. 010 0. 040 0.00788 0.0525 0. 040 0 .17 0 (2.358 0 .10 9)Zj j j j=+++++++ EQ 2. 41 5 ... Load 0 .47 65 41 . 6 1. 513 1. 1 34 0.9 01 4. 7Zj== ∠−°+ =∠−°VI ()( ) Load Load,pu base3 0.9 01 48 0 V 43 2 VVVV== = The power supplied to...

Ngày tải lên: 05/08/2014, 20:22

... below. 0.20 Ω j0. 41 Ω + - V φ I A R 1 jX 1 R F jX F The equivalent impedance of the rotor circuit in parallel with M jX is: 2 11 2.220 0. 745 2. 34 18 .5 11 1 1 15 2 .40 0. 41 F M Zj jX Z j ... between the lines tested. R 1 R 1 R 1 V DC Therefore, the stator resistance 1 R will be () () 11 1 DC 1 DC 1 1 1 2 3 RR R V R IRRR + == ++ DC 1 DC...

Ngày tải lên: 05/08/2014, 20:22

... 0.233 10 4. 4 0.267 11 8.86 0.3 13 2.86 0.333 14 6 .46 0.367 15 9.78 0 .4 17 2 .18 0 .43 3 18 3.98 0 .46 7 19 5. 04 0.5 205 .18 0.533 2 14 .52 0.567 223.06 0.6 2 31. 2 0.633 238 0.667 244 . 14 ... 249 . 74 0.733 255.08 0.767 259.2 0.8 263. 74 0.833 267.6 0.867 270.8 0.9 273.6 0.933 276 . 14 0.966 278 1 279. 74 1. 033 2 81. 48...

Ngày tải lên: 05/08/2014, 20:22

... Lagging: ()() EQ 11 5 0 V 0 . 14 0 0.532 8.7 36 87 A PS S Zj. ′ =+ =∠°+ + Ω ∠− °VV I 11 8.8 1. 4 V P ′ =∠° V 11 8.8 -11 5 VR 10 0% 3.3% 11 5 =×= (2) 1. 0 PF: ()() EQ 11 5 0 V 0 . 14 0 0.532 8.7 0 ... V 46 .03 31. 8 A 1. 18 4 .11 46 .03 31. 8 A 0 .12 0.5 jj ′ = ∠ ° + ∠− ° + Ω + ∠− ° + ΩV source 246 7 3.5 V ′ =∠°V Therefore, the voltage at the power source i...

Ngày tải lên: 05/08/2014, 20:22

... 2.50 :1 Y- ∆ 19 .9 kV 13 .8 kV 200 kVA 1. 44 :1 ∆ -Y 34. 5 kV 7.97 kV 200 kVA 4. 33 :1 ∆ - ∆ 34. 5 kV 13 .8 kV 200 kVA 2.50 :1 open- ∆ 34. 5 kV 13 .8 kV 346 kVA 2.50 :1 open-Y—open- ∆ 19 .9 kV 13 .8 ... EX 15 .1 A 0.0 010 942 13 .8 kV CM YGjB=− = = ()() 11 OC OC OC 44 .9 kW cos cos 77.56 13 .8 kV 15 .1 A P VI θ −− == =° EX 0.0 010 942 77.56 S 0.00...

Ngày tải lên: 05/08/2014, 20:22

... 12 /T− 12 /T c b SCR 3 SCR 5 SCR 5 -30 ° 12 /T 12 /3T a b SCR 1 SCR 5 SCR 1 30° 12 /3T 12 /5T a c SCR 1 SCR 6 SCR 6 90 ° 12 /5T 12 /7T b c SCR 2 SCR 6 SCR 2 15 0° 12 /7T ... 12 /7T b c SCR 2 SCR 6 SCR 2 15 0° 12 /7T 12 /9T b a SCR 2 SCR 4 SCR 4 210 ° 12 /9T 12 /11 T c a SCR 3 SCR 4 SCR 3 270 ° 12 /11 T 12 /T c b SCR 3...

Ngày tải lên: 05/08/2014, 20:22

... output power is ()() OUT 10 00 kVA 0.8 800 kWP == ( ) ( ) 2 2 CU 3 3 2 51 A 0 .15 28 .4 kW AA PIR== Ω= F&W 24 kWP = 11 4 OUT IN 5 54 kW 10 0% 10 0% 90.5% 612 kW P P η =× = × = (d) ... r/min 6000 r/min 10 600 r/min 720 r/min 48 00 r/min 12 500 r/min 600 r/min 40 00 r/min 14 42 8.6 r/min 5 14 .3 r/min 342 9 r/min 4- 3. A three-phase four-pole winding is...

Ngày tải lên: 05/08/2014, 20:22

... MW/Hz 2 Hz PA S == 3 MW 1. 676 MW/Hz 1. 79 Hz PB S == 3 MW 1. 9 61 MW/Hz 1. 53 Hz PC S == 11 6 ()()()() 13 28 0 0 .15 2 51 0 A 1. 1 2 51 0 A A jE =∠°+ Ω∠°+ Ω∠° 13 93 11 .4 V A E =∠° The voltage ... AAASA RjXEV I I φ =+ + ()( )( )( ) 7967 0 1. 5 41 8 36.87 A 12 .0 41 8 36.87 A A jE =∠°+Ω∠− °+ Ω∠− ° 12 , 040 17 .6 V A E =∠° 12 3 () ()( ) 11 nl1sy...

Ngày tải lên: 05/08/2014, 20:22

... generator is 15 1 () 11 1 21 2 3 84 V sin sin sin sin 36 .4 31. 1 4 41 . 6 V A A E E δδ −− == −°=−° The new armature current is 2 2 48 0 0 V 4 41 . 6 31. 1 V 227 24 .1 A 1. 1 A A S jX ... kW 41 9 kWPPP=+= + = TOT 1 2 14 5 kVAR 11 5 kVAR 260 kVARQQQ=+= + = The overall power factor is 14 0 ()()()() 7 217 0 0. 018 7 4 619 36.87 A 1. 716...

Ngày tải lên: 05/08/2014, 20:22

... () () ( ) ( ) () 11 TH 11 15 0.20 0. 41 0 .18 95 0 .4 016 0 .44 4 64. 7 0.20 0. 41 15 M M jX R jX j j Zj RjXX j +ΩΩ+Ω == =+Ω=∠°Ω ++ Ω+ Ω+Ω () ( ) () () TH 11 15 12 0 0 V 11 6.8 0.7 V 0.22 0 .43 15 M M j jX RjXX ... Characteristic'); grid on; 18 3 ()( ) () () 11 1 1 TH 11 11 MM MM jX R jX R j X X Z RjXX RjXX +−+ = ++ −+ () 222 2 11 11 1...

Ngày tải lên: 05/08/2014, 20:22