... class="bi x0 y0 w1 h 1" alt =""
Ngày tải lên: 05/08/2014, 15:21
... Communications and Networking 2 011 , 2 011 :208 http://jwcn.eurasipjournals.com/content/2 011 /1/ 208 Page 2 of 8 w i = w ∗ i = 1 √ k ,1 ≤ i ≤ k . (22) Therefore, ε and P f of problem P1 can be expressed as ε(k, ... and Networking 2 011 , 2 011 :208 http://jwcn.eurasipjournals.com/content/2 011 /1/ 208 © 2 011 Yu et al; licensee Springer. This is an Open Access article distributed un...
Ngày tải lên: 20/06/2014, 21:20
Báo cáo toán học: "Characterization of Hilbert space operators with unitary cross sections " pps
...
Ngày tải lên: 05/08/2014, 09:46
Báo cáo toán học: " Product of integers in an interval, modulo squares" ppsx
... × 1 2 , 3=3× 1 2 .Foru =3wehave8=2× 2 2 , 6 × 8=3× 4 2 , 5= 5 1 2 , 7=7× 1 2 .Foru =4wehave10 12 15 = 2 × 30 2 , 12 = 3 × 2 2 , 12 × 15 = 5 ×6 2 , 10 12 14 15 = 7 ×60 2 , 11 = 11 1 2 , 13 ... = 1 these are: z ≤ 2pq, p(2q +1) ,q(2p +1) <z+∆ p(2q − 1) ,q(2p 1) , (2p +1) (q − 1) , (2q +1) (p − 1) <z p(2q +2),q(2p +2), (2p +1) (q +1) , (2q +1) (p +1) ≥ z +∆. Now, by swap...
Ngày tải lên: 07/08/2014, 06:22
Báo cáo toán học: "Consistent cycles in 1 -arc-transitive graphs 2" ppsx
... cyclets, two of them of signature [0, 0], two of signature [1, 1] , one of signature [0, 1] and one of signature [1, 0]. One of the two orbits of signature [0, 0] is clearly a shift of the other of the ... of combinatorics 16 (2009), #R5 4 The proof of the above theorem is a word by word translation of the proof of [10 , Theorem 5 .1] with δ (Γ,G) () replaced...
Ngày tải lên: 07/08/2014, 21:21
Báo cáo toán học: "Tilings of the sphere with right triangles II: The (1, 3, 2), (0, 2, n) subfamily" ppt
... 2 13 12 B O B O M N P P’ 3’3’ 1 1 2’2’ 8’8’ 7’7’ 6’6’ 9 10 11 14 12 3’3’ 1 1 2’2’ 8’8’ 7’7’ 6’6’ 9 10 11 13 14 14 ’ 12 12 ’ 9’9’ 10 10 ’ 11 11 ’ 13 13 ’ a b Figure 15 : A 24-tile configuration forced at any (0, 5, 1) vertex Figure ... of combinatorics 13 (2006), #R49 4 B D 1 5 6 1 6’ 5’ 9 10 2’ 8 7 2 3 4 7’ 8’ 9’ 10 ’ C 4’ 3’ E F B 5 6 9 8 7 3 4 E F 11 12 G B...
Ngày tải lên: 07/08/2014, 13:21
Báo cáo toán học: "K0 of Exchange Rings with Stable Range 1" pps
... Journal of Mathematics 34:2 (2006) 17 1 17 8 K 0 of Exchange Rings with Stable Range 1 * Xinmin Lu 1, 2 and Hourong Qin 2 1 Faculty of Science, Jiangxi University of Science and Technology, Ganzhou 3 410 00, ... Rings and Categories of modules, Springer, Berlin, 19 73. 2. P. Ara, Aleph-nought-continuous regular rings, J. A lgebra 10 9 (19 87) 11 5 12 6. 3. G. Baccella, an...
Ngày tải lên: 06/08/2014, 05:20
Báo cáo toán học: "Permanents of Hessenberg (0,1)-matrices" ppsx
... a i +1, i =1for i =1, 2, ,n− 1, and a ii =1for i =1, 2, ,n. (c) If each a i,i +1 =1( i =1, 2, ,n− 1) and k and l are integers such that n ≥ k ≥ l ≥ 1, then per A(k,l)=perA[ 1, l− 1 ]perA[k +1, n], in ... example, M 6 = 16 16 0 0 0 0 8 816 000 4 4 816 0 0 224 816 0 11 24 816 11 24 816 . Lemma 5.2 Let A =[a ij ] be an n-by-n Hessenberg (0,...
Ngày tải lên: 07/08/2014, 13:21
Báo cáo toán học: "Characterization of [1, k]-Bar Visibility Trees" pps
... a 2 − a 1 , a 2 − a 1 , a 1 } ≤ max{a d − a 1 , a 1 }. ✷ Corollary. (4.2) Let 1 ≤ a 1 ≤ . . . ≤ a d with a i ≤ 2k. Then {a i : 1 ≤ i ≤ d − 1} has a k-balanced partition. Proof. By lemma (4 .1) , ... p 1 p 2 · · · p t . Define N 0 (p 1 ) = N(p 1 ) if t = 1, N(p 1 ) \ p 2 if t ≥ 2. % N 0 (p 1 ) contains all neighbors of p 1 outside of P . • Case 1: N 0 (...
Ngày tải lên: 07/08/2014, 13:21
Báo cáo toán học: "Expressions of EphA2 and EphrinA-1 in early squamous cell cervical carcinomas and their relation to prognosis" pps
... 11 -15 48 45 3 (6) 45 3 (6) > 15 47 40 7 (15 ) 35 12 (25) Vascular invasion 0. 716 0.669 Absent 11 7 10 6 11 (9) 10 4 13 (11 ) Present 10 0 92 8 (8) 87 13 (13 ) ... 0. 011 <0.0 01 Absent 202 18 7 15 (7) 18 3 19 (9) Present 15 11 4 (27) 8 7 (47) Lymph node metastasis 0.680 0.298 Absent 17 5 15 9 16 (9) 15 6 19 (11...
Ngày tải lên: 08/08/2014, 17:20