OPTICAL IMAGING AND SPECTROSCOPY Phần 1 pdf

... yields b ¼ n 1 =n 2 ðÞÀ ffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi 1 þ ( r =R 1 ) 2 À( r =R 1 ) 2 (n 1 =n 2 ) 2 q 1 þ ( r =R 1 ) 2 (2 :13 ) Under the approximation that r /R 1 (1, the solutions to a and b reduce to lowest order as b % (n 1 /n 2 ) 2 1 and a % 1. Under ... David Jones, 19 61- Optical imaging and spectroscopy / David Jones Bra...

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... ¼ b 0 (2x) À b 0 (2x À 1) ¼ f 1, 0 (x) À f 1, 1 (x)(3 :10 9) The scaling function can also be expressed in the basis V 1 as f (x)¼ b 0 (x) ¼ f 1, 0 (x) þ f 1, 1 (x)(3 :11 0) The wavelet and scaling functions ... Coefficients of SF14 Glass B 1 1.6 918 2538 B 2 0.285 919 934 B 3 1. 1259 514 5 C 1 0. 013 315 1542 C 2 0.0 612 647445 C 3 11 8.405242 50 GEOMETRIC IMAGING It is ofte...

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... 3 .12 , and 3 .17 for your function. 3 .11 2D Wavelet Analysis. Replicate Figs. 3 .13 and 3 .14 for an image of your choosing. 3 .12 Spline Interpolation: (a) Show that a one-dimensional pinhole imaging ... (4. 91) that the diffraction efficiency reaches 1 at z ¼ p =2 g ¼ l cos( u )1= (2D1), where u is the angle between the reconstruction and signal wavevec- tors and the z axis. A...

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... is W(x 0 1 , y 0 1 , x 0 2 , y 0 2 , n) ¼ ðððð W(x 1 Àx 2 , y 1 Ày 2 , n)t à (x 1 , y 1 )t(x 2 , y 2 ) Âexp 2 p i x 1 x 0 1 þy 1 y 0 1 l F  exp À2 p i x 2 x 0 2 þy 2 y 0 2 l F  dx 1 dy 1 dx 2 dy 2 (6:26) where ... 78,000 750 PbS 0.37 3.35 800 1, 000 PbSe 0.26 4.77 1, 500 1, 500 Si 1. 1 1. 13 1, 900 500 ZnS 3.54 0.35 18 0 — 15 6 DETECTION A thermal detector...

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... 3.6 and 0.6. The coherent modes are j f 1 i%À0:98j f a iÀ0 :17 j f b i j f 2 i¼À0 :17 j f a iþ0:98j f b i (6 :10 8) and the cross-spectral density is W(x 1 , y 1 , x 2 , y 2 , n) % S(n)3:6j f 1 ih f 1 jþ0:6j f 2 ih f 2 j ½ (6 :10 9) The ... input modes j f 1 i and j f 2 i interfere in output modes j f a i and j f b i. The mutual intensity of the input modes is described b...

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... column. The second object position from the left cor- responds to the code 011 111 1. The third column produces 10 111 11. The last column on the right corresponds to the code 0000000 (producing a ... position is unique. In Fig. 7. 21( a) each column corresponds to an object position. Taking black as 0 and white as 1, the code for the first object position is 11 111 11 measured along the...

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... f 1 , f 2 [ V f a f 1 þ (1  a ) f 2 [ V f (8:38) for 0  a  1. The point a f 1 þ (1  a ) f 2 is on the line segment between f 1 and f 2 at a distance (1 2 a )kf 1 2 f 2 k from f 1 and a kf 1 2 ... 8 .17 , which analyzes the same image as in Fig. 8.6 using the sampling codes 11 110 000 and 11 10 010 0. The first 12 5 out of 256 singular vectors are used in each cas...

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... ordinary axis is ˆ H(0, 0) ¼ 1 4 11 11  e 2 p in o (d= l ) 0 0 e 2 p in e (d= l ) ! 11 11  ¼ 1 2 e p i(n o þn e )d= l cos p (n o  n e ) d l  11 11  (9 :10 3) Assuming that the incident ... that n 1 =n 2 ¼ 1 Dn=n þ Dn 2 =n 2 and n 2 =n 1 ¼ 1 þ Dn, which yields a band edge at sin 2 2 p d l   1  Dn 2 2n 2 (9:90) Stopbands are centered on the wavelengths l...

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... challenges here, but we do Figure 10 .10 Cross sections of the 3D irradiance produced by the field C( r , f ) ¼ 10 ~ c 1, 1 =3 þ2 ~ c 5,3 þ ~ c 9,5 =16 þ ~ c 13 ,7 = 312 þ ~ c 17 ,9 =6950 as a function of ... focus for a Gaussian mode is Dz i ¼ 2 ffiffiffiffiffiffiffiffiffiffiffiffiffiffi N 2  1 p Dx 2 l  (10 :5) In comparing Eqns. (10 .4) and (10 .5) and Figs. 10 .2 and 10 .3, one finds that while th...

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... 37 pseudo-random, 292, 468–4 71, 480 shift, 312 – 319 , 4 51 Coded aperture imaging, 31 spectroscopy, 3 41 Coded aperture snapshot spectral imaging (CASSI), 479 Coherence between bases, 289 optical, 18 7 Coherence ... coherence tomography, Science 254 :11 78 11 81, 19 91. 12 3. G. Ha ¨ usler, A method to increase the depth of focus by two step image processing, Opt. Commun. 6 (1) :...

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