Maintenance Fundamentals Episode 2 part 7 ppsx

... products. "+ Pu'h""riP'"(~","B~' Roll"diw,R E ~ J.lFRcosB i D.ht2 ~' Sucks strip out Original strip thickness FIgure 7. 38 The roll bile: the top edge (E) is shown meeting tbe roll. 7. 7 Glossary 321 7. 7 .25 Roll Gap The area between ... [(a 2 + b 2 + c 2 + + n 2 )/n j.Typical values of R" might be 125 rnicroinches for s...

Ngày tải lên: 21/07/2014, 17:20

Ngày tải lên: 22/07/2014, 01:21

... B 19. C 20 . E 21 . D 22 . B 23 . C 24 . E 25 . A 26 . D 27 . C 28 . B 29 . D 30. C 31. D 32. A 33. C 34. A 35. E 36. B 37. D 38. C 39. C 40. A 41. D 42. B 43. A 44. E 45. B 46. A 47. C 48. B 49. E 50. ... O A O B O C O D O E 21 O A O B O C O D O E 22 O A O B O C O D O E 23 O A O B O C O D O E 24 O A O B O C O D O E 25 O A O B O C O D O E 26 O A O B O C O D O E 27 O A O...

Ngày tải lên: 22/07/2014, 11:20

... argument.  e correct answer is E. 12_ 44 974 5-ch08.indd 6 421 2_44 974 5-ch08.indd 6 42 2 /23 /09 11:44 : 27 AM2 /23 /09 11:44 : 27 AM 663 9.6 Sentence Correction Sample Questions 29 . The end of the eighteenth century ... doctors have also written 13_44 974 5-ch09.indd 6 72 1 3_44 974 5-ch09.indd 6 72 2 /23 /09 11:45: 42 AM2 /23 /09 11:45: 42 AM The Offi cial Guide for GMAT ® Revie...

Ngày tải lên: 22/07/2014, 14:20

... lubricant. I I r I I I I I I Torque =22 .6*(1 -cos (2& apos;pi'Pt)) /2 N-m =20 0'( 1 -cos (2& apos;pi'f9)) /2 Ib-in - f=100 HZ Figure 9. 37 The heat flux at four key points under ... 0.1 47 - H,, where h = fretting wear depth H, = Vickers hardness I I I 1 I 1 I I 1 Torque =22 .6‘( 1 -cos (2* pi’ft)) /2 N-m =20 0’(1 -ws(P*pi’f...

Ngày tải lên: 05/08/2014, 09:20

... M o ( 2 2 x −Lx)+C 2 Condition 2: v = 0 at x = LC 2 = M o 2 2 L EIv = M o ( 2 22 Lx + −Lx) Rotation: θ = v’ = EI M o (x−L) at x=0, v’= − EI M o L Deflection: v = EI M o ( 2 22 Lx + −Lx) ... diagrams. 2aaa P P a R eactions P a /2 − Pa M oment Diagram 2aaa Conjugate Beam P a/2EI P a/EI 2aaa R eactions P a/2EI P a/EI 11Pa 2 /12EI 5Pa 2 /12EI Shear(Rotation)Diagram (...

Ngày tải lên: 05/08/2014, 09:20

... us: M F bc = − 12 )( )( 2 Lengthw = − 12 (4) (3) 2 = − 4 kN-m M F cb = 12 )( )( 2 Lengthw = 12 (4) (3) 2 = 4 kN-m (d) Compute DF at b: 2 m 2 m 4 m a c b 3 kN/m 4 kN 2 m 2 kN 2 m 2 m 4 m a c b 3 ... loads 2. 46 4. 92 -14 . 27 15 .73 -7. 87 I nflection point Beam and Frame Analysis: Displacement Method, Part I by S. T. Mau 179 M bc = 2 1 ( M ba +...

Ngày tải lên: 05/08/2014, 09:20

... = ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎦ ⎤ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎣ ⎡ − +−−−−− −−+−−−−− −− −−−−−−+− −−−−−+ EK L EK C L EK S-EK L EK C L EK S L EK C L EK C L EA S L EK L EA CS L EK C L EK C L EA S L EK L EA CS L EK S L EK L EA CS L EK S L EA C L EK S L EK L EA CS L EK S L EA C EK L EK C L EK SEK L EK C L EK S L EK C L EK C L EA S L EK L EA CS L EK C L EK C L EA S L EK L EA CS L EK S L...

Ngày tải lên: 05/08/2014, 09:20

... Solutions Member Force (MN) Elongation (m) Member Force (MN) Elongation (m) 1 0. 375 0.011 8 0 0 2 0. 375 0.011 9 0. 625 0.031 3 0. 375 0.011 10 0 0 4 0. 375 0.011 11 -0. 625 -0.031 5 -0. 625 -0.031 12 -0 .75 0 -0. 023 6 0 0 13 -0 .75 0 -0. 023 7 0. 625 -0.031 Case (a): ... kN 0.5 kN 1.5 kN −1. 12 kN −1. 12 0 kN 2 kN 2. 24 −1 kN 0 kN 2. 24 0 kN 1 kN 1. 12 2 .24 −1. 12 −1 kN 1 k...

Ngày tải lên: 05/08/2014, 09:20

... Solutions Member Force (MN) Elongation (m) Member Force (MN) Elongation (m) 1 0. 375 0.011 8 0 0 2 0. 375 0.011 9 0. 625 0.031 3 0. 375 0.011 10 0 0 4 0. 375 0.011 11 -0. 625 -0.031 5 -0. 625 -0.031 12 -0 .75 0 -0. 023 6 0 0 13 -0 .75 0 -0. 023 7 0. 625 -0.031 Case (a): ... 0.00 2 0.011 -0. 073 6 0.045 -0. 073 3 0. 023 -0. 129 7 0. 023 -0. 129 4 0.034 -0. 073 8 0.000 -0. 073 The...

Ngày tải lên: 05/08/2014, 09:20