Machinery Components Maintenance And Repair Episode 2 Part 9 pps

... Model: ( ) ( ) ( ) 2 13 2 12 2 11 2 eScSaST ASM δδδ ++= ( ) ( )( )( ) ( )( )( ) ) 790 9 32( )4500 82( 2 ) 790 9 32( 2 2 222 627 221 018 696 45008 646 92 0 14 92 2 7 790 93 627 22 )0004)(548310()646 92 ( )017453( ./. ./ da ... 0.0005 0.00 12 0.600-0 .99 9 0.046 821 58 0.5654 92 0.0006 0.0015 1.000-1. 499 0.0 420 49 92 0.6 021 191 0.0008 0.0 02 1.500 -2. 799 0.048 096 84 0....

Ngày tải lên: 21/07/2014, 15:20

... Johnson ( 198 5, Chs 4 and 5) Asperity peak shape c, eqns (A3.8) and (3 .9) (p r / τ max )(p r / τ max )/c Spherical 0. 42 2.6 6 .2 Cylindrical 0. 39 2. 2 5.6 Conical 0.50 1.6 3 .2 Wedge-like 0.50 1.0 2. 0 Childs ... u˘ z d l hD ikj 21 10 + —— [ 121 0 ] 12 1 120 0000 (A2 .26 ) and 11 1 q*V e 1 qD ikj 1 hT 0 D ikj 1 {F} e = ——— {} – ——— {} – ——— {} (A2 .27 ) 4 1 3 1 3 1 10...

Ngày tải lên: 21/07/2014, 17:20

... of cut and feed are limited by tool geom- etry and the stock allowance as well: (C2) d ≤ a 1 l c cos y (9. 19) (C3) f ≤ a 2 r n (9 .20 ) (C4) d ≤ d a (9 .21 ) where a 1 and a 2 are constants, and l c is ... C p (x) 29 2 Process selection, improvement and control Fig. 9. 12 Fuzzy optimization of cutting conditions; only three constraints 1, 4 and 10 are considered Chi...

Ngày tải lên: 21/07/2014, 17:20

... given in Table 11 .2. Figure 11,s Contact model. 4 52 Chapter II 8. 9. 10. 1 I. 12. 13. 14. 15. 16. 17. 18. 19. 20 . 21 22 . 23 . 24 . 25 . Symmons, G., and McNulty, G., “Acoustic ... April 198 7, Vol. 1 09, pp. 26 4 -27 0. Greenwood, J. A., and Williamson, J. B. P., “Contact of Nominally Flat Surfaces,” Proc. Roy. Soc. Lond. Series A, 196 6, V...

Ngày tải lên: 05/08/2014, 09:20

... Fig. 9. 12) with 19 : 29 at input and 23 :31 at output. For a complete meshing cycle the layshaft would have to do 19 x 31 revs and 5 89 revs would take rather a long time and require ... continuous spectrum, and the "power" in each line is concentrated into an extremely narrow frequency band (Fig. 9. 6). A line will be at 29 times...

Ngày tải lên: 05/08/2014, 09:20

... there is a 20 8 Chapter 12 end for th = 1:8; % rotate for other 8 teeth xl((th *2* N +l):(th+l) *2* N) = xl(l :2* N)*cos(0. 698 13*th)+yl(l :2* N)*sin(0. 698 13*th); yl((th *2* N +l):(th+l) *2* N) =- xl(l :2* N)*sin(0. 698 13*th)+yl(l :2* N)*cos(0. 698 13*th); end saveteeth9 ... 40.784*sin(ang*0.15); end xtl = [17 .23 6 -17 .23 6]; ytl - [36 .96 3 53.037] ; % tange...

Ngày tải lên: 05/08/2014, 09:20

... (brl*psil - brl*tan(phi2))/(pi*cos(phio)); r2 = (br2*psi2 - br2*tan(phi2))/(pi*cos(phio)); conratio = rl + r2; disp( f angle rl r2 contact ratio') disp([ phi2 rl r2 conratio ]) phi3 ... Vol. 178, 196 3-64, Part I, pp 20 7 -22 6. Leming, J. C., 'High contact ratio (2+ ) spur gears.' SAE Gear Design, Warrendale, 199 0. Ch 6. Yildirim, N., Theoretica...

Ngày tải lên: 05/08/2014, 09:20

Ngày tải lên: 21/07/2014, 17:20

... F H w 2h a 2 ⎛ ⎜ ⎝ ⎞ ⎟ ⎠ 2 = tan θ max () wa 2F H = cos θ max () 2F H 4 F H 2 wa() 2 + = T max F H cos θ max () = F H 2 wa() 2 4 += wa 2 a 2 16h 2 1+= Guess h 1 m= Given T max wa 2 a 2 16h 2 1+= h Find h()= h 7. 09 m= Problem ... y−()= Σ M = 0; Mwy y 2 ⎛ ⎜ ⎝ ⎞ ⎟ ⎠ + wb b 2 ⎛ ⎜ ⎝ ⎞ ⎟ ⎠ + wa a 2 ⎛ ⎜ ⎝ ⎞ ⎟ ⎠ + wby− 0= My() wby 1 2 wy 2 − 1 2 wb 2 − 1 2...

Ngày tải lên: 21/07/2014, 17:20

Ngày tải lên: 21/07/2014, 21:21